我如何知道是否在Bash中设置了变量?

例如,如何检查用户是否向函数提供了第一个参数?

function a {
    # if $1 is set ?
}

当前回答

我很惊讶没有人尝试编写一个shell脚本来以编程方式生成这个臭名昭著的难以摸索的表。既然我们在这里试图学习编码技术,为什么不用代码表达答案?:)这是我的看法(应该在任何POSIX shell中都适用):

H="+-%s-+-%s----+-%s----+-%s--+\n"       # table divider printf format
R="| %-10s | %-10s | %-10s | %-10s |\n"  # table row printf format

S='V'     # S is a variable that is set-and-not-null
N=''      # N is a variable that is set-but-null (empty "")
unset U   # U is a variable that is unset

printf "$H" "----------" "-------" "-------" "---------";
printf "$R" "expression" "FOO='V'" "FOO='' " "unset FOO";
printf "$H" "----------" "-------" "-------" "---------";
printf "$R" "\${FOO:-x}" "${S:-x}" "${N:-x}" "${U:-x}  "; S='V';N='';unset U
printf "$R" "\${FOO-x} " "${S-x} " "${N-x} " "${U-x}   "; S='V';N='';unset U
printf "$R" "\${FOO:=x}" "${S:=x}" "${N:=x}" "${U:=x}  "; S='V';N='';unset U
printf "$R" "\${FOO=x} " "${S=x} " "${N=x} " "${U=x}   "; S='V';N='';unset U
#                                  "${N:?x}" "${U:?x}  "
printf "$R" "\${FOO:?x}" "${S:?x}" "<error>" "<error>  "; S='V';N='';unset U
#                                            "${U?x}   "
printf "$R" "\${FOO?x} " "${S?x} " "${N?x} " "<error>  "; S='V';N='';unset U
printf "$R" "\${FOO:+x}" "${S:+x}" "${N:+x}" "${U:+x}  "; S='V';N='';unset U
printf "$R" "\${FOO+x} " "${S+x} " "${N+x} " "${U+x}   "; S='V';N='';unset U
printf "$H" "----------" "-------" "-------" "---------";

以及运行脚本的输出:

+------------+------------+------------+------------+
| expression | FOO='V'    | FOO=''     | unset FOO  |
+------------+------------+------------+------------+
| ${FOO:-x}  | V          | x          | x          |
| ${FOO-x}   | V          |            | x          |
| ${FOO:=x}  | V          | x          | x          |
| ${FOO=x}   | V          |            | x          |
| ${FOO:?x}  | V          | <error>    | <error>    |
| ${FOO?x}   | V          |            | <error>    |
| ${FOO:+x}  | x          |            |            |
| ${FOO+x}   | x          | x          |            |
+------------+------------+------------+------------+

该脚本缺少了一些功能,比如在发生(或不发生)副作用分配时显示,但也许其他更有野心的人希望以此为出发点,并以此为出发。

其他回答

您可以执行以下操作:

function a {
        if [ ! -z "$1" ]; then
                echo '$1 is set'
        fi
}

对于那些希望在使用set-u的脚本中检查未设置或空的脚本:

if [ -z "${var-}" ]; then
   echo "Must provide var environment variable. Exiting...."
   exit 1
fi

常规[-z“$var”]检查将因var而失败;未绑定变量如果设置-u但[-z“${var-}”]如果var未设置而不失败,则扩展为空字符串。

如果未设置,则要退出

这对我很有用。如果没有设置参数,我希望脚本退出并显示错误消息。

#!/usr/bin/env bash

set -o errexit

# Get the value and empty validation check all in one
VER="${1:?You must pass a version of the format 0.0.0 as the only argument}"

运行时返回错误

peek@peek:~$ ./setver.sh
./setver.sh: line 13: 1: You must pass a version of the format 0.0.0 as the only argument

仅检查,不退出-空和未设置无效

如果您只想检查值set=VALID或unset/empty=INVALID,请尝试此选项。

TSET="good val"
TEMPTY=""
unset TUNSET

if [ "${TSET:-}" ]; then echo "VALID"; else echo "INVALID";fi
# VALID
if [ "${TEMPTY:-}" ]; then echo "VALID"; else echo "INVALID";fi
# INVALID
if [ "${TUNSET:-}" ]; then echo "VALID"; else echo "INVALID";fi
# INVALID

或者,即使是短期测试;-)

[ "${TSET:-}"   ] && echo "VALID" || echo "INVALID"
[ "${TEMPTY:-}" ] && echo "VALID" || echo "INVALID"
[ "${TUNSET:-}" ] && echo "VALID" || echo "INVALID"

仅检查,不退出-仅空为无效

这就是问题的答案。如果您只想检查值set/empty=VALID或unset=INVALID,请使用此选项。

注意,“..-1}”中的“1”无关紧要,它可以是任何东西(比如x)

TSET="good val"
TEMPTY=""
unset TUNSET

if [ "${TSET+1}" ]; then echo "VALID"; else echo "INVALID";fi
# VALID
if [ "${TEMPTY+1}" ]; then echo "VALID"; else echo "INVALID";fi
# VALID
if [ "${TUNSET+1}" ]; then echo "VALID"; else echo "INVALID";fi
# INVALID

短期测试

[ "${TSET+1}"   ] && echo "VALID" || echo "INVALID"
[ "${TEMPTY+1}" ] && echo "VALID" || echo "INVALID"
[ "${TUNSET+1}" ] && echo "VALID" || echo "INVALID"

我把这个答案献给了@mklement0(comments),他要求我准确回答这个问题。

参考:2.6.2参数扩展

在shell中,可以使用-z运算符,如果字符串长度为零,则该运算符为True。

如果未设置默认MY_VAR,则使用一个简单的单行设置,否则您可以选择显示消息:

[[ -z "$MY_VAR" ]] && MY_VAR="default"
[[ -z "$MY_VAR" ]] && MY_VAR="default" || echo "Variable already set."

如果你和我一样,你所寻找的其实是

“如果设置了变量,bash仅运行命令”

你希望这是一行,所以下面这行是你想要的

仅适用于Bash 4.2或更高版本

仅在设置时运行

if [[ -v mytest ]]; then echo "this runs only if variable is set"; fi

仅在未设置时运行

if [[ ! -v mytest2 ]]; then echo "this runs only if variable is not set"; fi