给定一个呈现其子组件的简单组件:

class ContainerComponent extends Component {
  static propTypes = {
    children: PropTypes.object.isRequired,
  }

  render() {
    return (
      <div>
        {this.props.children}
      </div>
    );
  }
}

export default ContainerComponent;

问:儿童道具的道具类型应该是什么?

当我将它设置为一个对象时,当我使用有多个子组件时,它会失败:

<ContainerComponent>
  <div>1</div>
  <div>2</div>
</ContainerComponent>

警告:失败的道具类型:类型数组的无效道具子元素 提供给ContainerComponent,期望对象。

如果我把它设置为一个数组,如果我只给它一个子数组,它就会失败,即:

<ContainerComponent>
  <div>1</div>
</ContainerComponent>

警告:失败的道具类型:类型对象的无效道具子 提供给ContainerComponent,期望数组。

请建议,我不应该打扰做一个propTypes检查子元素?


当前回答

这里的答案似乎并没有完全涵盖对孩子们的检查。node和object太允许,我想检查确切的元素。这是我最终使用的:

使用oneOfType([])允许使用单个或一组子元素 对于单个子数组和数组子数组,分别使用shape和arrayOf(shape({})) 对于子元素本身使用oneOf

最后,是这样的:

import PropTypes from 'prop-types'
import MyComponent from './MyComponent'

children: PropTypes.oneOfType([
  PropTypes.shape({
    type: PropTypes.oneOf([MyComponent]),
  }),
  PropTypes.arrayOf(
    PropTypes.shape({
      type: PropTypes.oneOf([MyComponent]),
    })
  ),
]).isRequired

这个问题帮助我更清楚地了解了这一点:https://github.com/facebook/react/issues/2979

其他回答

如果你想包含渲染道具组件:

  children: PropTypes.oneOfType([
    PropTypes.arrayOf(PropTypes.node),
    PropTypes.node,
    PropTypes.func
  ])

PropTypes文档有以下内容

// Anything that can be rendered: numbers, strings, elements or an array
// (or fragment) containing these types.
optionalNode: PropTypes.node,

你可以使用PropTypes。节点来检查对象或对象数组

static propTypes = {
   children: PropTypes.node.isRequired,
}

例子:

import React from 'react';
import PropTypes from 'prop-types';

class MenuItem extends React.Component {
    render() {
        return (
            <li>
                <a href={this.props.href}>{this.props.children}</a>
            </li>
        );
    }
}

MenuItem.defaultProps = {
    href: "/",
    children: "Main page"
};

MenuItem.propTypes = {
    href: PropTypes.string.isRequired,
    children: PropTypes.string.isRequired
};

export default MenuItem;

图片:如果预期的类型不同,在控制台显示错误

尝试使用oneOfType或PropTypes.node这样做

import PropTypes from 'prop-types'

...

static propTypes = {
    children: PropTypes.oneOfType([
        PropTypes.arrayOf(PropTypes.node),
        PropTypes.node
    ]).isRequired
}

or

static propTypes = {
    children: PropTypes.node.isRequired,
}

尝试自定义propTypes:

 const  childrenPropTypeLogic = (props, propName, componentName) => {
          const prop = props[propName];
          return React.Children
                   .toArray(prop)
                   .find(child => child.type !== 'div') && new Error(`${componentName} only accepts "div" elements`);
 };


static propTypes = {

   children : childrenPropTypeLogic

}

小提琴

const {Component, PropTypes} = React; const childrenPropTypeLogic = (props, propName, componentName) => { var error; var prop = props[propName]; React.Children.forEach(prop, function (child) { if (child.type !== 'div') { error = new Error( '`' + componentName + '` only accepts children of type `div`.' ); } }); return error; }; class ContainerComponent extends Component { static propTypes = { children: childrenPropTypeLogic, } render() { return ( <div> {this.props.children} </div> ); } } class App extends Component { render(){ return ( <ContainerComponent> <div>1</div> <div>2</div> </ContainerComponent> ) } } ReactDOM.render(<App /> , document.querySelector('section')) <script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react.min.js"></script> <script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react-dom.min.js"></script> <section />