简单。在编辑或更改值时，首先放置焦点，然后设置值。

$("#catg_name").focus();
$("#catg_name").val(catg_name);

我以前尝试过这些建议，但没有一个对我有效(在Chrome中测试了它们)，所以我写了自己的代码-它在Firefox, IE, Safari, Chrome中工作得很好……

在短信中：

onfocus() = sendCursorToEnd(this);

在Javascript中:

function sendCursorToEnd(obj) { 
var value = obj.value; //store the value of the element
var message = "";
if (value != "") {
    message = value + "\n";
};
$(obj).focus().val(message);}

While this may be an old question with lots of answers, I ran across a similar issue and none of the answers were quite what I wanted and/or were poorly explained. The issue with selectionStart and selectionEnd properties is that they don't exist for input type number (while the question was asked for text type, I reckon it might help others who might have other input types that they need to focus). So if you don't know whether the input type the function will focus is a type number or not, you cannot use that solution.

跨浏览器和所有输入类型的解决方案相当简单:

获取输入值并将其存储在变量中 关注输入 将输入值设置为存储值

这样，光标就位于输入元素的末尾。 所以你所要做的就是这样(使用jquery，提供一个人希望关注的元素选择器是通过点击元素的“data-focus-element”数据属性和函数在点击后执行)。foo的元素):

$('.foo').click(function() {
    element_selector = $(this).attr('data-focus-element');
    $focus = $(element_selector);
    value = $focus.val();
    $focus.focus();
    $focus.val(value);
});

Why does this work? Simply, when the .focus() is called, the focus will be added to the beginning of the input element (which is the core problem here), ignoring the fact, that the input element already has a value in it. However, when the value of an input is changed, the cursor is automatically placed at the end of the value inside input element. So if you override the value with the same value that had been previously entered in the input, the value will look untouched, the cursor will, however, move to the end.

试试下面的代码:

$('input').focus(function () {
    $(this).val($(this).val());
}).focus()

拿出一些答案。制作单行jquery。

$('#search').focus().val($('#search').val());

试试这个，它对我很有效:

//input is the input element

input.focus(); //sets focus to element
var val = this.input.value; //store the value of the element
this.input.value = ''; //clear the value of the element
this.input.value = val; //set that value back.  

为了让光标移动到最后，输入必须先有焦点，然后当值改变时，它才会移动到最后。如果你将.value设置为相同的值，它在chrome中不会改变。