我试图打印出一个列表的所有元素,但它是打印对象的指针,而不是值。

这是我的打印代码…

for(int i=0;i<list.size();i++){
    System.out.println(list.get(i));
} 

有人能告诉我为什么它不打印元素的值吗?


当前回答

public static void main(String[] args) {
        answer(10,60);

    }
    public static void answer(int m,int k){
        AtomicInteger n = new AtomicInteger(m);
        Stream<Integer> stream = Stream.generate(() -> n.incrementAndGet()).limit(k);
        System.out.println(Arrays.toString(stream.toArray()));
    }

其他回答

这取决于List中存储的对象类型,以及它是否有toString()方法的实现。System.out.println(list)应该打印所有标准java对象类型(String, Long, Integer等)。在这种情况下,如果我们使用自定义对象类型,那么我们需要重写自定义对象的toString()方法。

例子:

class Employee {
 private String name;
 private long id;

 @Override
 public String toString() {
   return "name: " + this.name() + 
           ", id: " + this.id();
 }  
}

测试:

class TestPrintList {
   public static void main(String[] args) {
     Employee employee1 =new Employee("test1", 123);
     Employee employee2 =new Employee("test2", 453);
     List<Employee> employees = new ArrayList(2);
     employee.add(employee1);
     employee.add(employee2);
     System.out.println(employees);
   }
}
   List<String> textList=  messageList.stream()
                            .map(Message::getText)
                            .collect(Collectors.toList());

        textList.stream().forEach(System.out::println);
        public class Message  {

        String name;
        String text;

        public Message(String name, String text) {
            this.name = name;
            this.text = text;
        }

        public String getName() {
            return name;
        }

      public String getText() {
        return text;
     }
   }

或者你可以简单地使用Apache Commons实用程序:

https://commons.apache.org/proper/commons-lang/apidocs/org/apache/commons/lang3/ArrayUtils.html#toString-java.lang.Object-

List<MyObject> myObjects = ...
System.out.println(ArrayUtils.toString(myObjects));

列表中的对象必须实现toString,以便将有意义的内容打印到屏幕上。

下面是一个快速测试,可以看出区别:

public class Test {

    public class T1 {
        public Integer x;
    }

    public class T2 {
        public Integer x;

        @Override
        public String toString() {
            return x.toString();
        }
    }

    public void run() {
        T1 t1 = new T1();
        t1.x = 5;
        System.out.println(t1);

        T2 t2 = new T2();
        t2.x = 5;
        System.out.println(t2);

    }

    public static void main(String[] args) {        
        new Test().run();
    }
}

当它执行时,打印到屏幕的结果是:

t1 = Test$T1@19821f
t2 = 5

因为T1没有重写toString方法,所以它的实例T1输出的结果不是很有用。另一方面,T2重写了toString,所以我们控制了它在I/O中使用时打印的内容,我们在屏幕上看到了一些更好的东西。

You haven't specified what kind of elements the list contains, if it is a primitive data type then you can print out the elements. But if the elements are objects then as Kshitij Mehta mentioned you need to implement (override) the method "toString" within that object - if it is not already implemented - and let it return something meaning full from within the object, example: class Person { private String firstName; private String lastName; @Override public String toString() { return this.firstName + " " + this.lastName; } }