我想有一个函数从Unicode字符串创建鼻涕虫,例如gen_slug('Andrés Cortez')应该返回andres-cortez。我该怎么做呢?


当前回答

这可能也是一种方法。灵感来自这些链接专家交流和alinalexander

function slugifier($txt){

   /* Get rid of accented characters */
   $search = explode(",","ç,æ,œ,á,é,í,ó,ú,à,è,ì,ò,ù,ä,ë,ï,ö,ü,ÿ,â,ê,î,ô,û,å,e,i,ø,u");
   $replace = explode(",","c,ae,oe,a,e,i,o,u,a,e,i,o,u,a,e,i,o,u,y,a,e,i,o,u,a,e,i,o,u");
   $txt = str_replace($search, $replace, $txt);

   /* Lowercase all the characters */
   $txt = strtolower($txt);

   /* Avoid whitespace at the beginning and the ending */
   $txt = trim($txt);

   /* Replace all the characters that are not in a-z or 0-9 by a hyphen */
   $txt = preg_replace("/[^a-z0-9]/", "-", $txt);
   /* Remove hyphen anywhere it's more than one */
   $txt = preg_replace("/[\-]+/", '-', $txt);
   return $txt;   
}

其他回答

不要为此使用preg_replace。有一个php函数是专门为这个任务构建的:strtr() http://php.net/manual/en/function.strtr.php

从上面链接的评论(我自己测试过;工作原理:

function normalize ($string) {
    $table = array(
        'Š'=>'S', 'š'=>'s', 'Đ'=>'Dj', 'đ'=>'dj', 'Ž'=>'Z', 'ž'=>'z', 'Č'=>'C', 'č'=>'c', 'Ć'=>'C', 'ć'=>'c',
        'À'=>'A', 'Á'=>'A', 'Â'=>'A', 'Ã'=>'A', 'Ä'=>'A', 'Å'=>'A', 'Æ'=>'A', 'Ç'=>'C', 'È'=>'E', 'É'=>'E',
        'Ê'=>'E', 'Ë'=>'E', 'Ì'=>'I', 'Í'=>'I', 'Î'=>'I', 'Ï'=>'I', 'Ñ'=>'N', 'Ò'=>'O', 'Ó'=>'O', 'Ô'=>'O',
        'Õ'=>'O', 'Ö'=>'O', 'Ø'=>'O', 'Ù'=>'U', 'Ú'=>'U', 'Û'=>'U', 'Ü'=>'U', 'Ý'=>'Y', 'Þ'=>'B', 'ß'=>'Ss',
        'à'=>'a', 'á'=>'a', 'â'=>'a', 'ã'=>'a', 'ä'=>'a', 'å'=>'a', 'æ'=>'a', 'ç'=>'c', 'è'=>'e', 'é'=>'e',
        'ê'=>'e', 'ë'=>'e', 'ì'=>'i', 'í'=>'i', 'î'=>'i', 'ï'=>'i', 'ð'=>'o', 'ñ'=>'n', 'ò'=>'o', 'ó'=>'o',
        'ô'=>'o', 'õ'=>'o', 'ö'=>'o', 'ø'=>'o', 'ù'=>'u', 'ú'=>'u', 'û'=>'u', 'ý'=>'y', 'ý'=>'y', 'þ'=>'b',
        'ÿ'=>'y', 'Ŕ'=>'R', 'ŕ'=>'r',
    );

    return strtr($string, $table);
}

不确定它适用于每一种情况,但我从Laravel Str类中采用了slug方法,并添加了iconv('utf-8', 'us-ascii//TRANSLIT', $title)的东西来处理口音,而不需要使用voku/便携式ascii,这似乎对我的用例工作得很好:

    public static function slug($title, $separator = '-')
    {
        $title = iconv('utf-8', 'us-ascii//TRANSLIT', $title);
        $flip = $separator === '-' ? '_' : '-';
        $title = preg_replace('!['.preg_quote($flip).']+!u', $separator, $title);
        // Replace @ with the word 'at'
        $title = str_replace('@', $separator.'at'.$separator, $title);
        // Remove all characters that are not the separator, letters, numbers, or whitespace.
        $title = preg_replace('![^'.preg_quote($separator).'\pL\pN\s]+!u', '', mb_strtolower($title, 'UTF-8'));
        // Replace all separator characters and whitespace by a single separator
        $title = preg_replace('!['.preg_quote($separator).'\s]+!u', $separator, $title);

        return trim($title, $separator);
    }

我根据梅林的回答写了这篇文章。无论页面上的字符编码如何,此函数都将正常工作。它也不会把单引号变成破折号:)

function slugify ($string) {
    $string = utf8_encode($string);
    $string = iconv('UTF-8', 'ASCII//TRANSLIT', $string);   
    $string = preg_replace('/[^a-z0-9- ]/i', '', $string);
    $string = str_replace(' ', '-', $string);
    $string = trim($string, '-');
    $string = strtolower($string);

    if (empty($string)) {
        return 'n-a';
    }

    return $string;
}

与其用冗长的替换,不如试试下面这个:

public static function slugify($text, string $divider = '-')
{
  // replace non letter or digits by divider
  $text = preg_replace('~[^\pL\d]+~u', $divider, $text);

  // transliterate
  $text = iconv('utf-8', 'us-ascii//TRANSLIT', $text);

  // remove unwanted characters
  $text = preg_replace('~[^-\w]+~', '', $text);

  // trim
  $text = trim($text, $divider);

  // remove duplicate divider
  $text = preg_replace('~-+~', $divider, $text);

  // lowercase
  $text = strtolower($text);

  if (empty($text)) {
    return 'n-a';
  }

  return $text;
}

这是基于Symfony的Jobeet教程。

因为我在这里看到了很多方法,但我为自己找到了一个最简单的方法。也许它会帮助别人。

$slug = strtolower(preg_replace('/[^a-zA-Z0-9\-]/', '',preg_replace('/\s+/', '-', $string) ));