我想有一个函数从Unicode字符串创建鼻涕虫,例如gen_slug('Andrés Cortez')应该返回andres-cortez。我该怎么做呢?


当前回答

不确定它适用于每一种情况,但我从Laravel Str类中采用了slug方法,并添加了iconv('utf-8', 'us-ascii//TRANSLIT', $title)的东西来处理口音,而不需要使用voku/便携式ascii,这似乎对我的用例工作得很好:

    public static function slug($title, $separator = '-')
    {
        $title = iconv('utf-8', 'us-ascii//TRANSLIT', $title);
        $flip = $separator === '-' ? '_' : '-';
        $title = preg_replace('!['.preg_quote($flip).']+!u', $separator, $title);
        // Replace @ with the word 'at'
        $title = str_replace('@', $separator.'at'.$separator, $title);
        // Remove all characters that are not the separator, letters, numbers, or whitespace.
        $title = preg_replace('![^'.preg_quote($separator).'\pL\pN\s]+!u', '', mb_strtolower($title, 'UTF-8'));
        // Replace all separator characters and whitespace by a single separator
        $title = preg_replace('!['.preg_quote($separator).'\s]+!u', $separator, $title);

        return trim($title, $separator);
    }

其他回答

在Laravel 8中是:

Str::slug('Hola como te va', '-');

// hola-como-te-va

不确定它适用于每一种情况,但我从Laravel Str类中采用了slug方法,并添加了iconv('utf-8', 'us-ascii//TRANSLIT', $title)的东西来处理口音,而不需要使用voku/便携式ascii,这似乎对我的用例工作得很好:

    public static function slug($title, $separator = '-')
    {
        $title = iconv('utf-8', 'us-ascii//TRANSLIT', $title);
        $flip = $separator === '-' ? '_' : '-';
        $title = preg_replace('!['.preg_quote($flip).']+!u', $separator, $title);
        // Replace @ with the word 'at'
        $title = str_replace('@', $separator.'at'.$separator, $title);
        // Remove all characters that are not the separator, letters, numbers, or whitespace.
        $title = preg_replace('![^'.preg_quote($separator).'\pL\pN\s]+!u', '', mb_strtolower($title, 'UTF-8'));
        // Replace all separator characters and whitespace by a single separator
        $title = preg_replace('!['.preg_quote($separator).'\s]+!u', $separator, $title);

        return trim($title, $separator);
    }

你可以看看Normalizer::normalize(),看这里。它只需要加载PHP的intl模块

与其用冗长的替换,不如试试下面这个:

public static function slugify($text, string $divider = '-')
{
  // replace non letter or digits by divider
  $text = preg_replace('~[^\pL\d]+~u', $divider, $text);

  // transliterate
  $text = iconv('utf-8', 'us-ascii//TRANSLIT', $text);

  // remove unwanted characters
  $text = preg_replace('~[^-\w]+~', '', $text);

  // trim
  $text = trim($text, $divider);

  // remove duplicate divider
  $text = preg_replace('~-+~', $divider, $text);

  // lowercase
  $text = strtolower($text);

  if (empty($text)) {
    return 'n-a';
  }

  return $text;
}

这是基于Symfony的Jobeet教程。

我正在使用这个函数,它工作得很好:

function slugify($string) {
  return strtolower(trim(preg_replace('~[^0-9a-z]+~i', '-', html_entity_decode(preg_replace('~&([a-z]{1,2})(?:acute|cedil|circ|grave|lig|orn|ring|slash|th|tilde|uml);~i', '$1', htmlentities($string, ENT_QUOTES, 'UTF-8')), ENT_QUOTES, 'UTF-8')), '-'));
}