是的，你可以:

UPDATE foobar SET column_a = CASE
   WHEN column_b = '123' THEN 1
   WHEN column_b = '345' THEN 2
END
WHERE column_b IN ('123','345')

并工作证明:http://sqlfiddle.com/#!2/97c7ea / 1

你也可以使用update…从语法和使用映射表。如果你想要更新多个列，它是更一般化的:

update test as t set
    column_a = c.column_a
from (values
    ('123', 1),
    ('345', 2)  
) as c(column_b, column_a) 
where c.column_b = t.column_b;

你可以添加任意多的列:

update test as t set
    column_a = c.column_a,
    column_c = c.column_c
from (values
    ('123', 1, '---'),
    ('345', 2, '+++')  
) as c(column_b, column_a, column_c) 
where c.column_b = t.column_b;

SQL演示

根据@Roman的解决方案，可以设置多个值:

update users as u set -- postgres FTW
  email = u2.email,
  first_name = u2.first_name,
  last_name = u2.last_name
from (values
  (1, 'hollis@weimann.biz', 'Hollis', 'Connell'),
  (2, 'robert@duncan.info', 'Robert', 'Duncan')
) as u2(id, email, first_name, last_name)
where u2.id = u.id;

假设你有一个id数组和等价的状态数组-这里有一个例子，如何用一个静态SQL(一个SQL查询不会因为数组的不同值而改变)来做到这一点:

drop table if exists results_dummy;
create table results_dummy (id int, status text, created_at timestamp default now(), updated_at timestamp default now());
-- populate table with dummy rows
insert into results_dummy
(id, status)
select unnest(array[1,2,3,4,5]::int[]) as id, unnest(array['a','b','c','d','e']::text[]) as status;

select * from results_dummy;

-- THE update of multiple rows with/by different values
update results_dummy as rd
set    status=new.status, updated_at=now()
from (select unnest(array[1,2,5]::int[]) as id,unnest(array['a`','b`','e`']::text[]) as status) as new
where rd.id=new.id;

select * from results_dummy;

-- in code using **IDs** as first bind variable and **statuses** as the second bind variable:
update results_dummy as rd
set    status=new.status, updated_at=now()
from (select unnest(:1::int[]) as id,unnest(:2::text[]) as status) as new
where rd.id=new.id;

遇到过类似的场景，CASE表达式对我很有用。

UPDATE reports SET is_default = 
case 
 when report_id = 123 then true
 when report_id != 123 then false
end
WHERE account_id = 321;

Reports -是这里的一个表，account_id与上面提到的report_ids相同。上面的查询将1条记录(符合条件的那条)设置为true，所有不匹配的记录设置为false。

要在单个查询中更新多行，您可以尝试这样做

UPDATE table_name
SET 
column_1 = CASE WHEN any_column = value and any_column = value THEN column_1_value end,
column_2 = CASE WHEN any_column = value and any_column = value THEN column_2_value end,
column_3 = CASE WHEN any_column = value and any_column = value THEN column_3_value end,
.
.
.
column_n = CASE WHEN any_column = value and any_column = value THEN column_n_value end

如果你不需要额外的条件，那么删除这个查询的一部分

除了其他答案、注释和文档之外，数据类型转换还可以放在使用上。这允许更容易的复制粘贴:

update test as t set
    column_a = c.column_a::number
from (values
    ('123', 1),
    ('345', 2)  
) as c(column_b, column_a) 
where t.column_b = c.column_b::text;

我认为公认的答案并不完全正确。它是顺序相关的。下面是一个用答案的方法不能正确工作的例子。

create table xxx (
    id varchar(64),
    is_enabled boolean
);

insert into xxx (id, is_enabled) values ('1',true);
insert into xxx (id, is_enabled) values ('2',true);
insert into xxx (id, is_enabled) values ('3',true);

UPDATE public.xxx AS pns
        SET is_enabled         = u.is_enabled
            FROM (
            VALUES
         (
            '3',
            false
         ,
            '1',
            true
         ,
            '2',
            false
         )
        ) AS u(id, is_enabled)
            WHERE u.id = pns.id;

select * from xxx;

所以问题仍然存在，有没有一种独立于顺序的方法?

----在尝试了一些事情后，这似乎是独立的秩序

UPDATE public.xxx AS pns
        SET is_enabled         = u.is_enabled
            FROM (
            SELECT '3' as id, false as is_enabled UNION
            SELECT '1' as id, true as is_enabled UNION
            SELECT '2' as id, false as is_enabled
         ) as u
            WHERE u.id = pns.id;

@Roman感谢你的解决方案，对于任何使用节点的人来说，我使用这个实用工具方法来抽出一个查询字符串，用n条记录更新n列。

不幸的是，它只处理n个具有相同列的记录，所以recordRows参数是非常严格的。

const payload = { rows: [ { id: 1, ext_id: 3 }, { id: 2, ext_id: 3 }, { id: 3, ext_id: 3 } , { id: 4, ext_id: 3 } ] }; var result = updateMultiple('t', payload); console.log(result); /* qstring returned is: UPDATE t AS t SET id = c.id, ext_id = c.ext_id FROM (VALUES (1,3),(2,3),(3,3),(4,3)) AS c(id,ext_id) WHERE c.id = t.id */ function updateMultiple(table, recordRows){ var valueSets = new Array(); var cSet = new Set(); var columns = new Array(); for (const [key, value] of Object.entries(recordRows.rows)) { var groupArray = new Array(); for ( const [key2, value2] of Object.entries(recordRows.rows[key])){ if(!cSet.has(key2)){ cSet.add(`${key2}`); columns.push(key2); } groupArray.push(`${value2}`); } valueSets.push(`(${groupArray.toString()})`); } var valueSetsString = valueSets.join(); var setMappings = new String(); for(var i = 0; i < columns.length; i++){ var fieldSet = columns[i]; setMappings += `${fieldSet} = c.${fieldSet}`; if(i < columns.length -1){ setMappings += ', '; } } var qstring = `UPDATE ${table} AS t SET ${setMappings} FROM (VALUES ${valueSetsString}) AS c(${columns}) WHERE c.id = t.id`; return qstring; }

@zero323提供的答案在Postgre 12上很有效。如果有人对column_b有多个值(在OP的问题中引用)

UPDATE conupdate SET orientation_status = CASE
   when id in (66934, 39) then 66
   when id in (66938, 49) then 77
END
WHERE id IN (66934, 39, 66938, 49)

在上面的查询中，id类似于column_b;Orientation_status类似于问题的column_a。