我有一个场景,在通过登录页面登录后,每个活动都会有一个注销按钮。

单击注销时,我将传递要注销的登录用户的会话id。有人能指导我如何让所有活动都可以使用会话id吗?

本案的任何替代方案


当前回答

源类:

Intent myIntent = new Intent(this, NewActivity.class);
myIntent.putExtra("firstName", "Your First Name Here");
myIntent.putExtra("lastName", "Your Last Name Here");
startActivity(myIntent)

目标类(NewActivity类):

protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.view);

    Intent intent = getIntent();

    String fName = intent.getStringExtra("firstName");
    String lName = intent.getStringExtra("lastName");
}

其他回答

使用捆绑包@链接https://medium.com/@nikhildhyani365/从一个活动到另一个活动的传递数据-18df2a701142//从介质复制

           Intent I =  new Intent(MainActivity.this,Show_Details.class);

            Bundle b = new Bundle();


            int x = Integer.parseInt(age.getText().toString());
            int y = Integer.parseInt(className.getText().toString());

            b.putString("Name",name.getText().toString());

            b.putInt("Age",x);
            b.putInt("ClassName",y);

            I.putExtra("student",b);

            startActivity(I);

使用Intent@链接https://android.jlelse.eu/passing-data-between-activities-using-intent-in-android-85cb097f3016

这是我的最佳实践,当项目规模巨大且复杂时,它会帮助很大。

假设我有两个活动,LoginActivity和HomeActivity。我想将2个参数(用户名和密码)从LoginActivity传递到HomeActivity。

首先,我创建HomeIntent

public class HomeIntent extends Intent {

    private static final String ACTION_LOGIN = "action_login";
    private static final String ACTION_LOGOUT = "action_logout";

    private static final String ARG_USERNAME = "arg_username";
    private static final String ARG_PASSWORD = "arg_password";


    public HomeIntent(Context ctx, boolean isLogIn) {
        this(ctx);
        //set action type
        setAction(isLogIn ? ACTION_LOGIN : ACTION_LOGOUT);
    }

    public HomeIntent(Context ctx) {
        super(ctx, HomeActivity.class);
    }

    //This will be needed for receiving data
    public HomeIntent(Intent intent) {
        super(intent);
    }

    public void setData(String userName, String password) {
        putExtra(ARG_USERNAME, userName);
        putExtra(ARG_PASSWORD, password);
    }

    public String getUsername() {
        return getStringExtra(ARG_USERNAME);
    }

    public String getPassword() {
        return getStringExtra(ARG_PASSWORD);
    }

    //To separate the params is for which action, we should create action
    public boolean isActionLogIn() {
        return getAction().equals(ACTION_LOGIN);
    }

    public boolean isActionLogOut() {
        return getAction().equals(ACTION_LOGOUT);
    }
}

以下是我如何在LoginActivity中传递数据

public class LoginActivity extends AppCompatActivity {
    @Override
    protected void onCreate(@Nullable Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_login);

        String username = "phearum";
        String password = "pwd1133";
        final boolean isActionLogin = true;
        //Passing data to HomeActivity
        final HomeIntent homeIntent = new HomeIntent(this, isActionLogin);
        homeIntent.setData(username, password);
        startActivity(homeIntent);

    }
}

最后一步,这里是我如何在HomeActivity中接收数据

public class HomeActivity extends AppCompatActivity {

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_home);

        //This is how we receive the data from LoginActivity
        //Make sure you pass getIntent() to the HomeIntent constructor
        final HomeIntent homeIntent = new HomeIntent(getIntent());
        Log.d("HomeActivity", "Is action login?  " + homeIntent.isActionLogIn());
        Log.d("HomeActivity", "username: " + homeIntent.getUsername());
        Log.d("HomeActivity", "password: " + homeIntent.getPassword());
    }
}

完成!酷:)我只是想分享我的经验。如果你在做小项目,这应该不是大问题。但当你在大项目上工作时,当你想进行重构或修复bug时,这真的很痛苦。

Destination活动的定义如下:

public class DestinationActivity extends AppCompatActivity{

    public static Model model;
    public static void open(final Context ctx, Model model){
          DestinationActivity.model = model;
          ctx.startActivity(new Intent(ctx, DestinationActivity.class))
    }

    public void onCreate(/*Parameters*/){
           //Use model here
           model.getSomething();
    }
}

在第一个活动中,按如下方式开始第二个活动:

DestinationActivity.open(this,model);

你可以用心工作。

String sessionId = "my session id";
startActivity(new Intent(getApplicationContext(),SignOutActivity.class).putExtra("sessionId",sessionId));

我们可以通过两种方式将值传递给另一个Activity(已经发布了相同类型的答案,但我在这里发布了通过意图尝试的redcing代码)

1.通过意图

  Activity1:
      startActivity(new Intent(getApplicationContext(),Activity2.class).putExtra("title","values"));

InActivity 2:

String recString= getIntent().getStringExtra("title");

2.通过SharedPreference

  Activity1:

SharedPreferences pref = getApplicationContext().getSharedPreferences("MyPref", 0); 
 // 0 - for private mode
Editor editor = pref.edit();
editor.putString("key_name", "string value"); // Storing string
editor.commit(); // commit changes

Activty2:
   SharedPreferences pref = getApplicationContext().getSharedPreferences("MyPref", 0); 

pref.getString("key_name", null); // getting String