我想使用JavaScript来计算字符串的宽度。如果不使用单行字体,这可能吗?

如果它不是内置的,我唯一的想法是为每个字符创建一个宽度表,但这是非常不合理的,特别是支持Unicode和不同的类型大小(以及所有浏览器)。


当前回答

你可以使用画布,这样你就不必处理这么多css属性:

var canvas = document.createElement("canvas");
var ctx = canvas.getContext("2d");
ctx.font = "20pt Arial";  // This can be set programmaticly from the element's font-style if desired
var textWidth = ctx.measureText($("#myElement").text()).width;

其他回答

jQuery:

(function($) {

 $.textMetrics = function(el) {

  var h = 0, w = 0;

  var div = document.createElement('div');
  document.body.appendChild(div);
  $(div).css({
   position: 'absolute',
   left: -1000,
   top: -1000,
   display: 'none'
  });

  $(div).html($(el).html());
  var styles = ['font-size','font-style', 'font-weight', 'font-family','line-height', 'text-transform', 'letter-spacing'];
  $(styles).each(function() {
   var s = this.toString();
   $(div).css(s, $(el).css(s));
  });

  h = $(div).outerHeight();
  w = $(div).outerWidth();

  $(div).remove();

  var ret = {
   height: h,
   width: w
  };

  return ret;
 }

})(jQuery);

下面的代码片段,“计算”span标签的宽度,如果它太长,就添加“…”,并减少文本长度,直到它适合它的父标签(或者直到它尝试了超过1000次)

CSS

div.places {
  width : 100px;
}
div.places span {
  white-space:nowrap;
  overflow:hidden;
}

HTML

<div class="places">
  <span>This is my house</span>
</div>
<div class="places">
  <span>And my house are your house</span>
</div>
<div class="places">
  <span>This placename is most certainly too wide to fit</span>
</div>

JavaScript(使用jQuery)

// loops elements classed "places" and checks if their child "span" is too long to fit
$(".places").each(function (index, item) {
    var obj = $(item).find("span");
    if (obj.length) {
        var placename = $(obj).text();
        if ($(obj).width() > $(item).width() && placename.trim().length > 0) {
            var limit = 0;
            do {
                limit++;
                                    placename = placename.substring(0, placename.length - 1);
                                    $(obj).text(placename + "...");
            } while ($(obj).width() > $(item).width() && limit < 1000)
        }
    }
});

工作示例:http://jsfiddle.net/tdpLdqpo/1/

HTML:

<h1 id="test1">
    How wide is this text?
</h1>
<div id="result1"></div>
<hr/>
<p id="test2">
    How wide is this text?
</p>
<div id="result2"></div>
<hr/>
<p id="test3">
    How wide is this text?<br/><br/>
    f sdfj f sdlfj lfj lsdk jflsjd fljsd flj sflj sldfj lsdfjlsdjkf sfjoifoewj flsdjfl jofjlgjdlsfjsdofjisdojfsdmfnnfoisjfoi  ojfo dsjfo jdsofjsodnfo sjfoj ifjjfoewj fofew jfos fojo foew jofj s f j
</p>
<div id="result3"></div>

JavaScript代码:

function getTextWidth(text, font) {
    var canvas = getTextWidth.canvas ||
        (getTextWidth.canvas = document.createElement("canvas"));
    var context = canvas.getContext("2d");
    context.font = font;
    var metrics = context.measureText(text);
    return metrics.width;
};

$("#result1")
.text("answer: " +
    getTextWidth(
             $("#test1").text(),
             $("#test1").css("font")) + " px");

$("#result2")
    .text("answer: " +
        getTextWidth(
             $("#test2").text(),
             $("#test2").css("font")) + " px");

$("#result3")
    .text("answer: " +
        getTextWidth(
             $("#test3").text(),
             $("#test3").css("font")) + " px");

如果你可以安装一个包,并且你想要一个更权威或更精确的答案,你可以使用opentype.js(奇怪的是没有人提到这一点):

import { load } from "opentype.js";

const getWidth = async (text = "Hello World") => {
  const font = await load("path/to/some/font");
  const { x1, x2 } = font.getPath(text, 0, 0, 12).getBoundingBox();
  return x2 - x1;
};

当然,您希望每个字体只调用load一次,因此应该根据您的情况将该行拉出到更高的范围。

下面是一个代码沙盒,将OpenType方法与Canvas和DOM方法进行比较: https://codesandbox.io/s/measure-width-of-text-in-javascript-vctst2

在我的机器上,每个100个样品,典型的结果是:

女士的OpenType: 5 女士帆布:3 女士DOM: 4

我发现的另一个软件包是:https://github.com/sffc/word-wrappr

我喜欢你的“唯一的想法”只是做一个静态字符宽度地图!它实际上很适合我的目的。有时,出于性能原因,或者因为不容易访问DOM,您可能只想要一个快速的、独立的、校准为单一字体的计算器。这是一个用Helvetica字体校准的;传递一个字符串和字体大小:

const widths = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0.2796875,0.2765625,0.3546875,0.5546875,0.5546875,0.8890625,0.665625,0.190625,0.3328125,0.3328125,0.3890625,0.5828125,0.2765625,0.3328125,0.2765625,0.3015625,0.5546875,0.5546875,0.5546875,0.5546875,0.5546875,0.5546875,0.5546875,0.5546875,0.5546875,0.5546875,0.2765625,0.2765625,0.584375,0.5828125,0.584375,0.5546875,1.0140625,0.665625,0.665625,0.721875,0.721875,0.665625,0.609375,0.7765625,0.721875,0.2765625,0.5,0.665625,0.5546875,0.8328125,0.721875,0.7765625,0.665625,0.7765625,0.721875,0.665625,0.609375,0.721875,0.665625,0.94375,0.665625,0.665625,0.609375,0.2765625,0.3546875,0.2765625,0.4765625,0.5546875,0.3328125,0.5546875,0.5546875,0.5,0.5546875,0.5546875,0.2765625,0.5546875,0.5546875,0.221875,0.240625,0.5,0.221875,0.8328125,0.5546875,0.5546875,0.5546875,0.5546875,0.3328125,0.5,0.2765625,0.5546875,0.5,0.721875,0.5,0.5,0.5,0.3546875,0.259375,0.353125,0.5890625]
const avg = 0.5279276315789471

function measureText(str, fontSize) {
  return Array.from(str).reduce(
    (acc, cur) => acc + (widths[cur.charCodeAt(0)] ?? avg), 0
  ) * fontSize
}

这个巨大的丑陋数组是由字符代码索引的ASCII字符宽度。所以这只支持ASCII(否则它假设平均字符宽度)。幸运的是,宽度基本上是随字体大小线性缩放的,所以它在任何字体大小下都能很好地工作。它明显缺乏对字距或结扎之类的意识。

为了“校准”,我只是在svg上渲染了charCode 126(强大的波浪号)的每个字符,并获得了边界框并将其保存到这个数组中;这里有更多的代码、解释和演示。