我喜欢你的“唯一的想法”只是做一个静态字符宽度地图!它实际上很适合我的目的。有时，出于性能原因，或者因为不容易访问DOM，您可能只想要一个快速的、独立的、校准为单一字体的计算器。这是一个用Helvetica字体校准的;传递一个字符串和字体大小:

const widths = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0.2796875,0.2765625,0.3546875,0.5546875,0.5546875,0.8890625,0.665625,0.190625,0.3328125,0.3328125,0.3890625,0.5828125,0.2765625,0.3328125,0.2765625,0.3015625,0.5546875,0.5546875,0.5546875,0.5546875,0.5546875,0.5546875,0.5546875,0.5546875,0.5546875,0.5546875,0.2765625,0.2765625,0.584375,0.5828125,0.584375,0.5546875,1.0140625,0.665625,0.665625,0.721875,0.721875,0.665625,0.609375,0.7765625,0.721875,0.2765625,0.5,0.665625,0.5546875,0.8328125,0.721875,0.7765625,0.665625,0.7765625,0.721875,0.665625,0.609375,0.721875,0.665625,0.94375,0.665625,0.665625,0.609375,0.2765625,0.3546875,0.2765625,0.4765625,0.5546875,0.3328125,0.5546875,0.5546875,0.5,0.5546875,0.5546875,0.2765625,0.5546875,0.5546875,0.221875,0.240625,0.5,0.221875,0.8328125,0.5546875,0.5546875,0.5546875,0.5546875,0.3328125,0.5,0.2765625,0.5546875,0.5,0.721875,0.5,0.5,0.5,0.3546875,0.259375,0.353125,0.5890625]
const avg = 0.5279276315789471

function measureText(str, fontSize) {
  return Array.from(str).reduce(
    (acc, cur) => acc + (widths[cur.charCodeAt(0)] ?? avg), 0
  ) * fontSize
}

这个巨大的丑陋数组是由字符代码索引的ASCII字符宽度。所以这只支持ASCII(否则它假设平均字符宽度)。幸运的是，宽度基本上是随字体大小线性缩放的，所以它在任何字体大小下都能很好地工作。它明显缺乏对字距或结扎之类的意识。

为了“校准”，我只是在svg上渲染了charCode 126(强大的波浪号)的每个字符，并获得了边界框并将其保存到这个数组中;这里有更多的代码、解释和演示。

var textWidth = (function (el) {
    el.style.position = 'absolute';
    el.style.top = '-1000px';
    document.body.appendChild(el);

    return function (text) {
        el.innerHTML = text;
        return el.clientWidth;
    };
})(document.createElement('div'));

从头重写了我的答案(谢谢你的减分)。 现在函数接受一个文本和css规则被应用(不再使用jQuery)。所以它也会尊重填充。结果值被四舍五入(您可以看到Math。四舍五入，如果你想要更精确的值，可以去掉)

function getSpan(){ const span = document.createElement('span') span.style.position = 'fixed'; span.style.visibility = 'hidden'; document.body.appendChild(span); return span; } function textWidth(str, css) { const span = getSpan(); Object.assign(span.style, css || {}); span.innerText = str; const w = Math.round(span.getBoundingClientRect().width); span.remove(); return w; } const testStyles = [ {fontSize: '10px'}, {fontSize: '12px'}, {fontSize: '60px'}, {fontSize: '120px'}, {fontSize: '120px', padding: '10px'}, {fontSize: '120px', fontFamily: 'arial'}, {fontSize: '120px', fontFamily: 'tahoma'}, {fontSize: '120px', fontFamily: 'tahoma', padding: '5px'}, ]; const ul = document.getElementById('output'); testStyles.forEach(style => { const li = document.createElement('li'); li.innerText = `${JSON.stringify(style)} > ${textWidth('abc', style)}`; ul.appendChild(li); }); <ul id="output"></ul>

试试下面的代码:

function GetTextRectToPixels(obj)
{
var tmpRect = obj.getBoundingClientRect();
obj.style.width = "auto"; 
obj.style.height = "auto"; 
var Ret = obj.getBoundingClientRect(); 
obj.style.width = (tmpRect.right - tmpRect.left).toString() + "px";
obj.style.height = (tmpRect.bottom - tmpRect.top).toString() + "px"; 
return Ret;
}

你也可以使用createRange，这比文本克隆技术更准确:

function getNodeTextWidth(nodeWithText) {
    var textNode = $(nodeWithText).contents().filter(function () {
        return this.nodeType == Node.TEXT_NODE;
    })[0];
    var range = document.createRange();
    range.selectNode(textNode);
    return range.getBoundingClientRect().width;
}

如果有人在这里寻找一种测量字符串宽度的方法，以及一种知道适合特定宽度的最大字体大小的方法，这里有一个基于@Domi的解决方案的函数，使用二进制搜索:

/**
 * Find the largest font size (in pixels) that allows the string to fit in the given width.
 * 
 * @param {String} text - The text to be rendered.
 * @param {String} font - The css font descriptor that text is to be rendered with (e.g. "bold ?px verdana") -- note the use of ? in place of the font size.
 * @param {Number} width - The width in pixels the string must fit in
 * @param {Number} minFontPx - The smallest acceptable font size in pixels
 * @param {Number} maxFontPx - The largest acceptable font size in pixels
 **/
function GetTextSizeForWidth(text, font, width, minFontPx, maxFontPx) {
  for (;;) {
    var s = font.replace("?", maxFontPx);
    var w = GetTextWidth(text, s);
    if (w <= width) {
      return maxFontPx;
    }

    var g = (minFontPx + maxFontPx) / 2;

    if (Math.round(g) == Math.round(minFontPx) || Math.round(g) == Math.round(maxFontPx)) {
      return g;
    }

    s = font.replace("?", g);
    w = GetTextWidth(text, s);
    if (w >= width) {
      maxFontPx = g;
    } else {
      minFontPx = g;
    }
  }
}