下面是一个函数:

function days_between(date1, date2) {

    // The number of milliseconds in one day
    const ONE_DAY = 1000 * 60 * 60 * 24;

    // Calculate the difference in milliseconds
    const differenceMs = Math.abs(date1 - date2);

    // Convert back to days and return
    return Math.round(differenceMs / ONE_DAY);

}

调整以允许夏令时的差异。试试这个:

  function daysBetween(date1, date2) {

 // adjust diff for for daylight savings
 var hoursToAdjust = Math.abs(date1.getTimezoneOffset() /60) - Math.abs(date2.getTimezoneOffset() /60);
 // apply the tz offset
 date2.addHours(hoursToAdjust); 

    // The number of milliseconds in one day
    var ONE_DAY = 1000 * 60 * 60 * 24

    // Convert both dates to milliseconds
    var date1_ms = date1.getTime()
    var date2_ms = date2.getTime()

    // Calculate the difference in milliseconds
    var difference_ms = Math.abs(date1_ms - date2_ms)

    // Convert back to days and return
    return Math.round(difference_ms/ONE_DAY)

}

// you'll want this addHours function too 

Date.prototype.addHours= function(h){
    this.setHours(this.getHours()+h);
    return this;
}

用我的日期差计算器:

var startDate = new Date(2000, 1-1, 1);  // 2000-01-01
var endDate =   new Date();              // Today

// Calculate the difference of two dates in total days
function diffDays(d1, d2)
{
  var ndays;
  var tv1 = d1.valueOf();  // msec since 1970
  var tv2 = d2.valueOf();

  ndays = (tv2 - tv1) / 1000 / 86400;
  ndays = Math.round(ndays - 0.5);
  return ndays;
}

所以你可以调用:

var nDays = diffDays(startDate, endDate);

(完整来源:http://david.tribble.com/src/javascript/jstimespan.html)

齿顶高

代码可以通过更改以下几行来改进:

  var tv1 = d1.getTime();  // msec since 1970
  var tv2 = d2.getTime();

这是我用的。如果只是减去日期，它将无法跨越夏令时边界(例如4月1日至4月30日或10月1日至10月31日)。这省去了所有的小时，以确保您有一天的时间，并通过使用UTC消除了任何DST问题。

var nDays = (    Date.UTC(EndDate.getFullYear(), EndDate.getMonth(), EndDate.getDate()) -
                 Date.UTC(StartDate.getFullYear(), StartDate.getMonth(), StartDate.getDate())) / 86400000;

作为函数:

function DaysBetween(StartDate, EndDate) {
  // The number of milliseconds in all UTC days (no DST)
  const oneDay = 1000 * 60 * 60 * 24;

  // A day in UTC always lasts 24 hours (unlike in other time formats)
  const start = Date.UTC(EndDate.getFullYear(), EndDate.getMonth(), EndDate.getDate());
  const end = Date.UTC(StartDate.getFullYear(), StartDate.getMonth(), StartDate.getDate());

  // so it's safe to divide by 24 hours
  return (start - end) / oneDay;
}

下面是一个函数:

function days_between(date1, date2) {

    // The number of milliseconds in one day
    const ONE_DAY = 1000 * 60 * 60 * 24;

    // Calculate the difference in milliseconds
    const differenceMs = Math.abs(date1 - date2);

    // Convert back to days and return
    return Math.round(differenceMs / ONE_DAY);

}

这是我的实现:

function daysBetween(one, another) {
  return Math.round(Math.abs((+one) - (+another))/8.64e7);
}

+<date>对整数表示进行类型强制转换，与<date>. gettime()具有相同的效果，8.64e7是一天中的毫秒数。