是否可以写入字符串或日志到控制台?
我的意思是
就像在JSP中一样,如果我们打印system.out.println("some")这样的东西,它将出现在控制台,而不是页面上。
是否可以写入字符串或日志到控制台?
我的意思是
就像在JSP中一样,如果我们打印system.out.println("some")这样的东西,它将出现在控制台,而不是页面上。
当前回答
如果你想写入PHP日志文件,而不是JavaScript控制台,你可以使用这个:
error_log(“这只记录到PHP日志”)
参考:error_log
其他回答
我认为它可以被用来
function jsLogs($data, $isExit) {
$html = "";
$coll;
if (is_array($data) || is_object($data)) {
$coll = json_encode($data);
} else {
$coll = $data;
}
$html = "<script id='jsLogs'>console.log('PHP: ${coll}');</script>";
echo($html);
if ($isExit) exit();
}
# For String
jsLogs("Testing string"); #PHP: Testing string
# For Array
jsLogs(array("test1", "test2")); # PHP: ["test1","test2"]
# For Object
jsLogs(array("test1"=>array("subtest1", "subtest2"))); #PHP: {"test1":["subtest1","subtest2"]}
简短简单,适用于数组、字符串或对象。
function console_log( $data ) {
$output = "<script>console.log( 'PHP debugger: ";
$output .= json_encode(print_r($data, true));
$output .= "' );</script>";
echo $output;
}
这里有一个方便的函数。它使用起来超级简单,允许您传递任意类型的任意数量的参数,并将在浏览器控制台窗口中显示对象内容,就像从JavaScript调用console.log一样——但是从PHP调用的
注意,你也可以通过传递' tag - yourtag '来使用标签,它将被应用,直到读取另一个标签,例如' tag - yournexttag '
/*
* Brief: Print to console.log() from PHP
*
* Description: Print as many strings,arrays, objects, and
* other data types to console.log from PHP.
*
* To use, just call consoleLog($data1, $data2, ... $dataN)
* and each dataI will be sent to console.log - note
* that you can pass as many data as you want an
* this will still work.
*
* This is very powerful as it shows the entire
* contents of objects and arrays that can be
* read inside of the browser console log.
*
* A tag can be set by passing a string that has the
* prefix TAG- as one of the arguments. Everytime a
* string with the TAG- prefix is detected, the tag
* is updated. This allows you to pass a tag that is
* applied to all data until it reaches another tag,
* which can then be applied to all data after it.
*
* Example:
*
* consoleLog('TAG-FirstTag', $data, $data2, 'TAG-SecTag, $data3);
*
* Result:
* FirstTag '...data...'
* FirstTag '...data2...'
* SecTag '...data3...'
*/
function consoleLog(){
if(func_num_args() == 0){
return;
}
$tag = '';
for ($i = 0; $i < func_num_args(); $i++) {
$arg = func_get_arg($i);
if(!empty($arg)){
if(is_string($arg) && strtolower(substr($arg, 0, 4)) === 'tag-'){
$tag = substr($arg, 4);
}else{
$arg = json_encode($arg, JSON_HEX_TAG | JSON_HEX_AMP );
echo "<script>console.log('" . $tag . " " . $arg . "');</script>";
}
}
}
}
注意:func_num_args()和func_num_args()是PHP函数,用于读取动态数量的输入参数,并允许该函数从一个函数调用中有无限多个console.log请求。
这是我的解决方案,这个的好处是你可以传递尽可能多的参数。
function console_log()
{
$js_code = 'console.log(' . json_encode(func_get_args(), JSON_HEX_TAG) .
');';
$js_code = '<script>' . $js_code . '</script>';
echo $js_code;
}
这样称呼它
console_log('DEBUG>>', 'Param 1', 'Param 2');
console_log('Console DEBUG:', $someRealVar1, $someVar, $someArray, $someObj);
现在你应该能够在你的控制台看到输出,愉快的编码:)
Use:
function console_log($data) {
$bt = debug_backtrace();
$caller = array_shift($bt);
if (is_array($data))
$dataPart = implode(',', $data);
else
$dataPart = $data;
$toSplit = $caller['file'])) . ':' .
$caller['line'] . ' => ' . $dataPart
error_log(end(split('/', $toSplit));
}