我试图使用fetch POST一个JSON对象。

根据我的理解,我需要将一个字符串化的对象附加到请求的主体,例如:

fetch("/echo/json/",
{
    headers: {
      'Accept': 'application/json',
      'Content-Type': 'application/json'
    },
    method: "POST",
    body: JSON.stringify({a: 1, b: 2})
})
.then(function(res){ console.log(res) })
.catch(function(res){ console.log(res) })

当使用jsfiddle的JSON回显时,我希望看到我发送的对象({a: 1, b: 2})回来,但这不会发生- chrome devtools甚至不显示JSON作为请求的一部分,这意味着它没有被发送。


当前回答

我认为你的问题是jsfiddle只能处理表单url编码的请求。但是让json请求的正确方法是将正确的json作为body传递:

fetch (https://httpbin.org/post, { 方法:“文章”, 标题:{ 'Accept': 'application/json, text/plain, */*', “内容类型”:“application / json” }, 身体:JSON。stringify({a: 7, str: 'Some string: &=&'}) })。然后res => res.json()) .then(res => console.log(res));

其他回答

我认为,我们不需要将JSON对象解析为字符串,如果远程服务器接受JSON到他们的请求,只需运行:

const request = await fetch ('/echo/json', {
  headers: {
    'Content-type': 'application/json'
  },
  method: 'POST',
  body: { a: 1, b: 2 }
});

比如curl请求

curl -v -X POST -H 'Content-Type: application/json' -d '@data.json' '/echo/json'

如果远程服务不接受json文件作为主体,只需发送一个dataForm:

const data =  new FormData ();
data.append ('a', 1);
data.append ('b', 2);

const request = await fetch ('/echo/form', {
  headers: {
    'Content-type': 'application/x-www-form-urlencoded'
  },
  method: 'POST',
  body: data
});

比如curl请求

curl -v -X POST -H 'Content-type: application/x-www-form-urlencoded' -d '@data.txt' '/echo/form'

2021年的答案:以防你在这里寻找如何使用async/await或promises来进行GET和POST Fetch api请求,而不是axios。

我使用jsonplaceholder伪API来演示:

使用async/await获取api GET请求:

         const asyncGetCall = async () => {
            try {
                const response = await fetch('https://jsonplaceholder.typicode.com/posts');
                 const data = await response.json();
                // enter you logic when the fetch is successful
                 console.log(data);
               } catch(error) {
            // enter your logic for when there is an error (ex. error toast)
                  console.log(error)
                 } 
            }


          asyncGetCall()

使用async/await获取api POST请求:

    const asyncPostCall = async () => {
            try {
                const response = await fetch('https://jsonplaceholder.typicode.com/posts', {
                 method: 'POST',
                 headers: {
                   'Content-Type': 'application/json'
                   },
                   body: JSON.stringify({
             // your expected POST request payload goes here
                     title: "My post title",
                     body: "My post content."
                    })
                 });
                 const data = await response.json();
              // enter you logic when the fetch is successful
                 console.log(data);
               } catch(error) {
             // enter your logic for when there is an error (ex. error toast)

                  console.log(error)
                 } 
            }

asyncPostCall()

使用Promises获取请求:

  fetch('https://jsonplaceholder.typicode.com/posts')
  .then(res => res.json())
  .then(data => {
   // enter you logic when the fetch is successful
    console.log(data)
  })
  .catch(error => {
    // enter your logic for when there is an error (ex. error toast)
   console.log(error)
  })

使用承诺POST请求:

fetch('https://jsonplaceholder.typicode.com/posts', {
  method: 'POST',
  headers: {
    'Content-Type': 'application/json',
  },
   body: JSON.stringify({
     // your expected POST request payload goes here
      title: "My post title",
      body: "My post content."
      })
})
  .then(res => res.json())
  .then(data => {
   // enter you logic when the fetch is successful
    console.log(data)
  })
  .catch(error => {
  // enter your logic for when there is an error (ex. error toast)
   console.log(error)
  })  

使用Axios获取请求:

        const axiosGetCall = async () => {
            try {
              const { data } = await axios.get('https://jsonplaceholder.typicode.com/posts')
    // enter you logic when the fetch is successful
              console.log(`data: `, data)
           
            } catch (error) {
    // enter your logic for when there is an error (ex. error toast)
              console.log(`error: `, error)
            }
          }
    
    axiosGetCall()

使用Axios的POST请求:

const axiosPostCall = async () => {
    try {
      const { data } = await axios.post('https://jsonplaceholder.typicode.com/posts',  {
      // your expected POST request payload goes here
      title: "My post title",
      body: "My post content."
      })
   // enter you logic when the fetch is successful
      console.log(`data: `, data)
   
    } catch (error) {
  // enter your logic for when there is an error (ex. error toast)
      console.log(`error: `, error)
    }
  }


axiosPostCall()

有同样的问题-没有身体从客户端发送到服务器。 添加内容类型头为我解决了这个问题:

var headers = new Headers();

headers.append('Accept', 'application/json'); // This one is enough for GET requests
headers.append('Content-Type', 'application/json'); // This one sends body

return fetch('/some/endpoint', {
    method: 'POST',
    mode: 'same-origin',
    credentials: 'include',
    redirect: 'follow',
    headers: headers,
    body: JSON.stringify({
        name: 'John',
        surname: 'Doe'
    }),
}).then(resp => {
    ...
}).catch(err => {
   ...
})

在花了一些时间后,反向工程jsFiddle,试图生成有效负载-有一个效果。

请采取眼睛(照顾)在线返回response.json();这里的回应不是回应,而是承诺。

var json = {
    json: JSON.stringify({
        a: 1,
        b: 2
    }),
    delay: 3
};

fetch('/echo/json/', {
    method: 'post',
    headers: {
        'Accept': 'application/json, text/plain, */*',
        'Content-Type': 'application/json'
    },
    body: 'json=' + encodeURIComponent(JSON.stringify(json.json)) + '&delay=' + json.delay
})
.then(function (response) {
    return response.json();
})
.then(function (result) {
    alert(result);
})
.catch (function (error) {
    console.log('Request failed', error);
});

jsFiddle: http://jsfiddle.net/egxt6cpz/46/ && Firefox > 39 && Chrome > 42

如果您的JSON负载包含数组和嵌套对象,我将使用URLSearchParams和jQuery的param()方法。

fetch('/somewhere', {
  method: 'POST',
  body: new URLSearchParams($.param(payload))
})

对于您的服务器,这将看起来像一个标准的HTML <form>被post。