我有一个PHP数组如下:

$messages = [312, 401, 1599, 3, ...];

我想删除包含值$del_val的元素(例如,$del_val=401),但我不知道它的键。这可能会有帮助:每个值只能在那里出现一次。

我正在寻找执行这项任务的最简单的函数。


当前回答

如果你明确知道你的数组将只包含一个具有该值的元素,你可以这样做

$key = array_search($del_val, $array);
if (false !== $key) {
    unset($array[$key]);
}

但是,如果您的值可能在数组中出现多次,则可以这样做

$array = array_filter($array, function($e) use ($del_val) {
    return ($e !== $del_val);
});

注意:第二个选项只适用于带有闭包的PHP5.3+

其他回答

一个有趣的方法是使用array_keys():

foreach (array_keys($messages, 401, true) as $key) {
    unset($messages[$key]);
}

array_keys()函数接受两个额外的参数,只返回特定值的键,以及是否需要严格检查(即使用===进行比较)。

这也可以删除具有相同值的多个数组项(例如[1,2,3,3,4])。

我认为最简单的方法是使用带有foreach循环的函数:

//This functions deletes the elements of an array $original that are equivalent to the value $del_val
//The function works by reference, which means that the actual array used as parameter will be modified.

function delete_value(&$original, $del_val)
{
    //make a copy of the original, to avoid problems of modifying an array that is being currently iterated through
    $copy = $original;
    foreach ($original as $key => $value)
    {
        //for each value evaluate if it is equivalent to the one to be deleted, and if it is capture its key name.
        if($del_val === $value) $del_key[] = $key;
    };
    //If there was a value found, delete all its instances
    if($del_key !== null)
    {
        foreach ($del_key as $dk_i)
        {
            unset($original[$dk_i]);
        };
        //optional reordering of the keys. WARNING: only use it with arrays with numeric indexes!
        /*
        $copy = $original;
        $original = array();
        foreach ($copy as $value) {
            $original[] = $value;
        };
        */
        //the value was found and deleted
        return true;
    };
    //The value was not found, nothing was deleted
    return false;
};

$original = array(0,1,2,3,4,5,6,7,4);
$del_val = 4;
var_dump($original);
delete_value($original, $del_val);
var_dump($original);

输出将是:

array(9) {
  [0]=>
  int(0)
  [1]=>
  int(1)
  [2]=>
  int(2)
  [3]=>
  int(3)
  [4]=>
  int(4)
  [5]=>
  int(5)
  [6]=>
  int(6)
  [7]=>
  int(7)
  [8]=>
  int(4)
}
array(7) {
  [0]=>
  int(0)
  [1]=>
  int(1)
  [2]=>
  int(2)
  [3]=>
  int(3)
  [5]=>
  int(5)
  [6]=>
  int(6)
  [7]=>
  int(7)
}

从数组中删除一个元素基本上就是设置一个元素的差异。

array_diff( [312, 401, 15, 401, 3], [401] ) // removing 401 returns [312, 15, 3]

它很好地泛化了,你可以同时删除任意多的元素,如果你想的话。

免责声明:请注意,我的解决方案产生了一个新的数组副本,同时保持旧的完整,与变异的接受答案形成对比。选一个你需要的。

最好的方法是array_splice

array_splice($array, array_search(58, $array ), 1);

最佳理由请访问http://www.programmerinterview.com/index.php/php-questions/how-to-delete-an-element-from-an-array-in-php/

你可以:

unset($messages[array_flip($messages)['401']]);

解释:在翻转数组后删除键为401的元素。