我的python脚本使用subprocess调用一个非常吵闹的linux实用程序。我想将所有输出存储到一个日志文件中,并将其中一些显示给用户。我认为下面的代码可以工作,但是直到实用程序产生大量输出,输出才显示在我的应用程序中。

#fake_utility.py, just generates lots of output over time
import time
i = 0
while True:
   print hex(i)*512
   i += 1
   time.sleep(0.5)

#filters output
import subprocess
proc = subprocess.Popen(['python','fake_utility.py'],stdout=subprocess.PIPE)
for line in proc.stdout:
   #the real code does filtering here
   print "test:", line.rstrip()

我真正想要的行为是让过滤器脚本打印从子进程接收到的每一行。有点像tee,但用的是python代码。

我错过了什么?这可能吗?


更新:

如果将sys.stdout.flush()添加到fake_utility.py中,代码在python 3.1中具有所需的行为。我使用的是python 2.6。您可能认为使用proc.stdout.xreadlines()的工作方式与py3k相同,但事实并非如此。


更新2:

下面是最小的工作代码。

#fake_utility.py, just generates lots of output over time
import sys, time
for i in range(10):
   print i
   sys.stdout.flush()
   time.sleep(0.5)

#display out put line by line
import subprocess
proc = subprocess.Popen(['python','fake_utility.py'],stdout=subprocess.PIPE)
#works in python 3.0+
#for line in proc.stdout:
for line in iter(proc.stdout.readline,''):
   print line.rstrip()

当前回答

我尝试用python3,它工作,源代码

当你使用popen生成新线程时,你告诉操作系统PIPE子进程的stdout,这样父进程就可以读取它,在这里,stderr被复制到父进程的stderr。

在output_reader中,我们读取子进程的每一行stdout,方法是将它包装在迭代器中,每当有新行准备好时,迭代器就会逐行填充子进程的输出。

def output_reader(proc):
    for line in iter(proc.stdout.readline, b''):
        print('got line: {0}'.format(line.decode('utf-8')), end='')


def main():
    proc = subprocess.Popen(['python', 'fake_utility.py'],
                            stdout=subprocess.PIPE,
                            stderr=subprocess.STDOUT)

    t = threading.Thread(target=output_reader, args=(proc,))
    t.start()

    try:
        time.sleep(0.2)
        import time
        i = 0
    
        while True:
        print (hex(i)*512)
        i += 1
        time.sleep(0.5)
    finally:
        proc.terminate()
        try:
            proc.wait(timeout=0.2)
            print('== subprocess exited with rc =', proc.returncode)
        except subprocess.TimeoutExpired:
            print('subprocess did not terminate in time')
    t.join()

其他回答

允许逐行实时遍历stdout和stderr的函数

如果需要同时获取stdout和stderr的输出流,可以使用下面的函数。

该函数使用Queues将两个Popen管道合并到一个迭代器中。

这里我们创建了函数read_popen_pipes():

from queue import Queue, Empty
from concurrent.futures import ThreadPoolExecutor


def enqueue_output(file, queue):
    for line in iter(file.readline, ''):
        queue.put(line)
    file.close()


def read_popen_pipes(p):

    with ThreadPoolExecutor(2) as pool:
        q_stdout, q_stderr = Queue(), Queue()

        pool.submit(enqueue_output, p.stdout, q_stdout)
        pool.submit(enqueue_output, p.stderr, q_stderr)

        while True:

            if p.poll() is not None and q_stdout.empty() and q_stderr.empty():
                break

            out_line = err_line = ''

            try:
                out_line = q_stdout.get_nowait()
            except Empty:
                pass
            try:
                err_line = q_stderr.get_nowait()
            except Empty:
                pass

            yield (out_line, err_line)

Read_popen_pipes()正在使用:

import subprocess as sp


with sp.Popen(my_cmd, stdout=sp.PIPE, stderr=sp.PIPE, text=True) as p:

    for out_line, err_line in read_popen_pipes(p):

        # Do stuff with each line, e.g.:
        print(out_line, end='')
        print(err_line, end='')

    return p.poll() # return status-code

我认为问题在于proc.stdout中的for line语句,它在迭代整个输入之前读取它。解决方案是使用readline()代替:

#filters output
import subprocess
proc = subprocess.Popen(['python','fake_utility.py'],stdout=subprocess.PIPE)
while True:
  line = proc.stdout.readline()
  if not line:
    break
  #the real code does filtering here
  print "test:", line.rstrip()

当然,您仍然需要处理子进程的“缓冲”。

注意:根据文档,使用迭代器的解决方案应该等效于使用readline(),除了预读缓冲区,但(或正因为如此)建议的更改确实为我产生了不同的结果(Windows XP上的Python 2.5)。

实际上,如果您对迭代器进行了排序,那么缓冲现在可能是您的问题。你可以告诉子进程中的python不要缓冲它的输出。

proc = subprocess.Popen(['python','fake_utility.py'],stdout=subprocess.PIPE)

就变成了

proc = subprocess.Popen(['python','-u', 'fake_utility.py'],stdout=subprocess.PIPE)

当从python内部调用python时,我需要这个。

我有一个问题与Popen的参数列表更新服务器,下面的代码解决了这一点。

import getpass
from subprocess import Popen, PIPE

username = 'user1'
ip = '127.0.0.1'

print ('What is the password?')
password = getpass.getpass()
cmd1 = f"""sshpass -p {password} ssh {username}@{ip}"""
cmd2 = f"""echo {password} | sudo -S apt update"""
cmd3 = " && "
cmd4 = f"""echo {password} | sudo -S apt upgrade -y"""
cmd5 = " && "
cmd6 = "exit"
commands = [cmd1, cmd2, cmd3, cmd4, cmd5, cmd6]

command = " ".join(commands)

cmd = command.split()

with Popen(cmd, stdout=PIPE, bufsize=1, universal_newlines=True) as p:
    for line in p.stdout:
        print(line, end='')

要在本地计算机上运行更新,下面的代码示例将执行此操作。

import getpass
from subprocess import Popen, PIPE

print ('What is the password?')
password = getpass.getpass()

cmd1_local = f"""apt update"""
cmd2_local = f"""apt upgrade -y"""
commands = [cmd1_local, cmd2_local]

with Popen(['echo', password], stdout=PIPE) as auth:
    for cmd in commands:
        cmd = cmd.split()
        with Popen(['sudo','-S'] + cmd, stdin=auth.stdout, stdout=PIPE, bufsize=1, universal_newlines=True) as p:
            for line in p.stdout:
                print(line, end='')

您需要将这些额外的参数传递给子进程。Popen:

bufsize=1, universal_newlines=True

然后可以像示例中那样进行迭代。(使用Python 3.5测试)