fs.statSync(path, function(err, stat){
      if(err == null) {
          console.log('File exists');
          //code when all ok
      }else if (err.code == "ENOENT") {
        //file doesn't exist
        console.log('not file');

      }
      else {
        console.log('Some other error: ', err.code);
      }
    });

vannilla Nodejs 回调

function fileExists(path, cb){
  return fs.access(path, fs.constants.F_OK,(er, result)=> cb(!err && result)) //F_OK checks if file is visible, is default does no need to be specified.
}

文档说你应该使用access()来代替已弃用的exists()

带有内置承诺的Nodejs (node 7+)

function fileExists(path, cb){
  return new Promise((accept,deny) => 
    fs.access(path, fs.constants.F_OK,(er, result)=> cb(!err && result))
  );
}

流行的javascript框架

fs-extra

var fs = require('fs-extra')
await fs.pathExists(filepath)

如你所见，简单多了。与promisify相比，它的优势在于你可以使用这个包实现完整的类型(完整的智能感知/typescript)!大多数情况下，您已经包含了这个库，因为(+-10.000)其他库都依赖于它。

2021年8月

读完所有帖子后:

let filePath = "./directory1/file1.txt";

if (fs.existsSync(filePath)) {
    console.log("The file exists");
} else {
    console.log("The file does not exist");
}

异步等待风格的简洁解决方案:

import { stat } from 'fs/promises';

const exists = await stat('foo.txt')
   .then(() => true)
   .catch(() => false);

我是这样做的，详见https://nodejs.org/api/fs.html#fs_fs_access_path_mode_callback

fs.access('./settings', fs.constants.F_OK | fs.constants.R_OK | fs.constants.W_OK, function(err){
  console.log(err ? 'no access or dir doesnt exist' : 'R/W ok');

  if(err && err.code === 'ENOENT'){
    fs.mkdir('settings');
  }
});

这有什么问题吗?

V6之前的旧版本: 下面是文档

  const fs = require('fs');    
  fs.exists('/etc/passwd', (exists) => {
     console.log(exists ? 'it\'s there' : 'no passwd!');
  });
// or Sync

  if (fs.existsSync('/etc/passwd')) {
    console.log('it\'s there');
  }

更新

V6的新版本:fs.stat的文档

fs.stat('/etc/passwd', function(err, stat) {
    if(err == null) {
        //Exist
    } else if(err.code == 'ENOENT') {
        // NO exist
    } 
});