这个函数运行得很好:

let isPhoneNumber = input => { try { let ISD_CODES = [93, 355, 213, 1684, 376, 244, 1264, 672, 1268, 54, 374, 297, 61, 43, 994, 1242, 973, 880, 1246, 375, 32, 501, 229, 1441, 975, 591, 387, 267, 55, 246, 1284, 673, 359, 226, 257, 855, 237, 1, 238, 1345, 236, 235, 56, 86, 61, 61, 57, 269, 682, 506, 385, 53, 599, 357, 420, 243, 45, 253, 1767, 1809, 1829, 1849, 670, 593, 20, 503, 240, 291, 372, 251, 500, 298, 679, 358, 33, 689, 241, 220, 995, 49, 233, 350, 30, 299, 1473, 1671, 502, 441481, 224, 245, 592, 509, 504, 852, 36, 354, 91, 62, 98, 964, 353, 441624, 972, 39, 225, 1876, 81, 441534, 962, 7, 254, 686, 383, 965, 996, 856, 371, 961, 266, 231, 218, 423, 370, 352, 853, 389, 261, 265, 60, 960, 223, 356, 692, 222, 230, 262, 52, 691, 373, 377, 976, 382, 1664, 212, 258, 95, 264, 674, 977, 31, 599, 687, 64, 505, 227, 234, 683, 850, 1670, 47, 968, 92, 680, 970, 507, 675, 595, 51, 63, 64, 48, 351, 1787, 1939, 974, 242, 262, 40, 7, 250, 590, 290, 1869, 1758, 590, 508, 1784, 685, 378, 239, 966, 221, 381, 248, 232, 65, 1721, 421, 386, 677, 252, 27, 82, 211, 34, 94, 249, 597, 47, 268, 46, 41, 963, 886, 992, 255, 66, 228, 690, 676, 1868, 216, 90, 993, 1649, 688, 1340, 256, 380, 971, 44, 1, 598, 998, 678, 379, 58, 84, 681, 212, 967, 260, 263], //extract numbers from string thenum = input.match(/[0-9]+/g).join(""), totalnums = thenum.length, last10Digits = parseInt(thenum) % 10000000000, ISDcode = thenum.substring(0, totalnums - 10); //phone numbers are generally of 8 to 16 digits if (totalnums >= 8 && totalnums <= 16) { if (ISDcode) { if (ISD_CODES.includes(parseInt(ISDcode))) { return true; } else { return false; } } else { return true; } } } catch (e) {} return false; } console.log(isPhoneNumber('91-9883208806'));

一个很简单的方法:

"9001234567".match(/^\d{10}$/g)

试试这个正则表达式

/[^0-9+() -.]/g

使用的例子:

<input type="tel" id="txtUserMobile" onkeyup="this.value=this.value.replace(/[^0-9+() -.]/g,'')">

享受

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正则表达式

使用以下Regex模式:

/^[\+]?[(]?[0-9]{3}[)]?[-\s\.]?[0-9]{3}[-\s\.]?[0-9]{4,6}$/im

这样的:<输入模式 ="/^[\+]?[(]?[ 0 - 9] {3} [)] ? [\ s \。]? [0 - 9]{3}[\ s \。]吗?[0 - 9] {4 6} $ / im”> *

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有效的格式:

(123) 456-7890, (123) 456-7890, 123-456-7890, 123.456 7890。, 1234567890, + 31636363634前 075-63546725

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阿根廷数据的RegExp: / ^((+[0 - 9]{1,3})) ?(([0 - 9]{8、13})|([0 - 9]{3、6})——([0 - 9]{4 7}))/美元

Valids:

X: from 8 to 13 numbers

XXXXXXXX

separate numbers by a hyphen = X from 3 to 6; Y: from 4 to 7

XXXX-YYYY

Z: from 1 to 3

(+ Z) XXXXXXXX

if you use Z then (+ ) is mandatory.

我要做的是忽略格式并验证数字内容:

var originalPhoneNumber = "415-555-1212";

function isValid(p) {
  var phoneRe = /^[2-9]\d{2}[2-9]\d{2}\d{4}$/;
  var digits = p.replace(/\D/g, "");
  return phoneRe.test(digits);
}