/^.*(youtu.be\/|v\/|e\/|u\/\w+\/|embed\/|v=)([^#\&\?]*).*/

测试:

http://www.youtube.com/v/0zM3nApSvMg?fs=1&hl=en_US&rel=0 http://www.youtube.com/embed/0zM3nApSvMg?rel=0 http://www.youtube.com/watch?v=0zM3nApSvMg&feature=feedrec_grec_index http://www.youtube.com/watch?v=0zM3nApSvMg http://youtu.be/0zM3nApSvMg http://www.youtube.com/watch?v=0zM3nApSvMg#t=0m10s http://www.youtube.com/user/IngridMichaelsonVEVO#p/a/u/1/KdwsulMb8EQ http://youtu.be/dQw4w9WgXcQ http://www.youtube.com/embed/dQw4w9WgXcQ http://www.youtube.com/v/dQw4w9WgXcQ http://www.youtube.com/e/dQw4w9WgXcQ http://www.youtube.com/watch?v=dQw4w9WgXcQ http://www.youtube.com/?v=dQw4w9WgXcQ http://www.youtube.com/watch?feature=player_embedded&v=dQw4w9WgXcQ http://www.youtube.com/?feature=player_embedded&v=dQw4w9WgXcQ http://www.youtube.com/user/IngridMichaelsonVEVO#p/u/11/KdwsulMb8EQ http://www.youtube-nocookie.com/v/6L3ZvIMwZFM?version=3&hl=en_US&rel=0

受到另一个答案的启发。

简单的正则表达式，如果你有完整的URL，保持简单。

results = url.match("v=([a-zA-Z0-9]+)&?")
videoId = results[1] // watch you need.

我做了一个小函数，从Youtube url中提取视频id，如下所示。

var videoId =函数(url) { Var match = url.match(/v=([0-9a-z_-]{1,20})/i); 返回(match ?匹配['1']:false); }; console.log (videoId (' https://www.youtube.com/watch?v=dQw4w9WgXcQ ')); console.log (videoId (' https://www.youtube.com/watch?t=17s&v=dQw4w9WgXcQ ')); console.log (videoId (' https://www.youtube.com/watch?v=dQw4w9WgXcQ&t=17s '));

这个函数将提取视频id，即使url中有多个参数。

Python3版本:

import re

def get_youtube_id(url):
   match = re.match('^.*((youtu.be\/)|(v\/)|(\/u\/\w\/)|(embed\/)|(watch\?))?\?v?=?(?P<id>\w*).*', url);
   return match.group('id')

如果你想在shell/bash/zsh/fish脚本中包含它，下面是如何做到的:

echo -n "$YOUTUBE_URL" | python -c "import re; import sys; m = re.match('^.*((youtu.be\/)|(v\/)|(\/u\/\w\/)|(embed\/)|(watch\?))?\?v?=?(?P<id>\w*).*', sys.stdin.read()); sys.stdout.write(m.group('id'))"

例子:

echo -n "https://www.youtube.com/watch/?v=APYVWYHS654" | python -c "import re; import sys; m = re.match('^.*((youtu.be\/)|(v\/)|(\/u\/\w\/)|(embed\/)|(watch\?))?\?v?=?(?P<id>\w*).*', sys.stdin.read()); sys.stdout.write(m.group('id'))"  

APYVWYHS654

/^.*(youtu.be\/|v\/|e\/|u\/\w+\/|embed\/|v=)([^#\&\?]*).*/

测试:

http://www.youtube.com/v/0zM3nApSvMg?fs=1&hl=en_US&rel=0 http://www.youtube.com/embed/0zM3nApSvMg?rel=0 http://www.youtube.com/watch?v=0zM3nApSvMg&feature=feedrec_grec_index http://www.youtube.com/watch?v=0zM3nApSvMg http://youtu.be/0zM3nApSvMg http://www.youtube.com/watch?v=0zM3nApSvMg#t=0m10s http://www.youtube.com/user/IngridMichaelsonVEVO#p/a/u/1/KdwsulMb8EQ http://youtu.be/dQw4w9WgXcQ http://www.youtube.com/embed/dQw4w9WgXcQ http://www.youtube.com/v/dQw4w9WgXcQ http://www.youtube.com/e/dQw4w9WgXcQ http://www.youtube.com/watch?v=dQw4w9WgXcQ http://www.youtube.com/?v=dQw4w9WgXcQ http://www.youtube.com/watch?feature=player_embedded&v=dQw4w9WgXcQ http://www.youtube.com/?feature=player_embedded&v=dQw4w9WgXcQ http://www.youtube.com/user/IngridMichaelsonVEVO#p/u/11/KdwsulMb8EQ http://www.youtube-nocookie.com/v/6L3ZvIMwZFM?version=3&hl=en_US&rel=0

受到另一个答案的启发。

我把Lasnv的回答简化了一点。

它还修复了WebDeb描述的错误。

下面就是:

var regExp = /^.*(youtu\.be\/|v\/|u\/\w\/|embed\/|watch\?v=|\&v=)([^#\&\?]*).*/;
var match = url.match(regExp);
if (match && match[2].length == 11) {
  return match[2];
} else {
  //error
}

下面是一个regexer链接: http://regexr.com/3dnqv