Java代码:(适用于所有url:

http://www.youtube.com/watch?v=0zM3nApSvMg&feature=feedrec_grec_index http://www.youtube.com/user/IngridMichaelsonVEVO#p/a/u/1/QdK8U-VIH_o http://youtube.googleapis.com/v/0zM3nApSvMg?fs=1&hl=en_US&rel=0 http://www.youtube.com/watch?v=0zM3nApSvMg#t=0m10s http://www.youtube.com/embed/0zM3nApSvMg?rel=0” http://www.youtube.com/watch?v=0zM3nApSvMg http://youtu.be/0zM3nApSvMg http://www.youtube.com/watch?v=0zM3nApSvMg/ http://www.youtube.com/watch?feature=player_detailpage&v=8UVNT4wvIGY

)

    String url = "http://www.youtube.com/watch?v=0zM3nApSvMg&feature=feedrec_grec_index";

    String regExp = "/.*(?:youtu.be\\/|v\\/|u/\\w/|embed\\/|watch\\?.*&?v=)";
    Pattern compiledPattern = Pattern.compile(regExp);
    Matcher matcher = compiledPattern.matcher(url);
    if(matcher.find()){
        int start = matcher.end();
        System.out.println("ID : " + url.substring(start, start+11));

    }

DailyMotion网站:

String url = "http://www.dailymotion.com/video/x4xvnz_the-funny-crash-compilation_fun";

    String regExp = "/video/([^_]+)/?";
    Pattern compiledPattern = Pattern.compile(regExp);
    Matcher matcher = compiledPattern.matcher(url);
    if(matcher.find()){
        String match = matcher.group();
        System.out.println("ID : " + match.substring(match.lastIndexOf("/")+1));

    }

由于YouTube视频id被设置为11个字符，我们可以简单地在用v=分割url后使用子字符串。 那么我们就不依赖于最后的&号了。

var sampleUrl = "http://www.youtube.com/watch?v=JcjoGn6FLwI&asdasd";

var video_id = sampleUrl.split("v=")[1].substring(0, 11)

很好很简单:)

简单的正则表达式，如果你有完整的URL，保持简单。

results = url.match("v=([a-zA-Z0-9]+)&?")
videoId = results[1] // watch you need.

强大的Python来了

import pytube

yt = pytube.YouTube("https://www.youtube.com/watch?v=kwM2ApskJy4")

video_id = yt.video_id

print("video id from utl..",video_id)

如果有人需要Kotlin中的完美函数来节省他们的时间。希望这能有所帮助

fun extractYTId(ytUrl: String?): String? {
    var vId: String? = null
    val pattern = Pattern.compile(
        "^https?://.*(?:youtu.be/|v/|u/\\w/|embed/|watch?v=)([^#&?]*).*$",
        Pattern.CASE_INSENSITIVE
    )
    val matcher = pattern.matcher(ytUrl)
    if (matcher.matches()) {
        vId = matcher.group(1)
    }
    return vId
}

我做了一个小函数，从Youtube url中提取视频id，如下所示。

var videoId =函数(url) { Var match = url.match(/v=([0-9a-z_-]{1,20})/i); 返回(match ?匹配['1']:false); }; console.log (videoId (' https://www.youtube.com/watch?v=dQw4w9WgXcQ ')); console.log (videoId (' https://www.youtube.com/watch?t=17s&v=dQw4w9WgXcQ ')); console.log (videoId (' https://www.youtube.com/watch?v=dQw4w9WgXcQ&t=17s '));

这个函数将提取视频id，即使url中有多个参数。