最短的

.toJSON().slice(0,10).split`-`.join``;

let d = new Date(); let s = d.toJSON().slice(0,10).split ' - ' .join '; console.log(年代);

<pre>Date.prototype.getFromFormat = function(format) {
    var yyyy = this.getFullYear().toString();
    format = format.replace(/yyyy/g, yyyy)
    var mm = (this.getMonth()+1).toString(); 
    format = format.replace(/mm/g, (mm[1]?mm:"0"+mm[0]));
    var dd  = this.getDate().toString();
    format = format.replace(/dd/g, (dd[1]?dd:"0"+dd[0]));
    var hh = this.getHours().toString();
    format = format.replace(/hh/g, (hh[1]?hh:"0"+hh[0]));
    var ii = this.getMinutes().toString();
    format = format.replace(/ii/g, (ii[1]?ii:"0"+ii[0]));
    var ss  = this.getSeconds().toString();
    format = format.replace(/ss/g, (ss[1]?ss:"0"+ss[0]));
    var ampm = (hh >= 12) ? "PM" : "AM";
    format = format.replace(/ampm/g, (ampm[1]?ampm:"0"+ampm[0]));
    return format;
};
var time_var = $('#899_TIME');
var myVar = setInterval(myTimer, 1000);
function myTimer() {
    var d = new Date(); 
    var date = d.getFromFormat('dd-mm-yyyy hh:ii:ss:ampm');
    time_var.text(date);

} </pre>

use the code and get the output like **26-07-2017 12:29:34:PM**

check the below link for your reference

https://parthiban037.wordpress.com/2017/07/26/date-and-time-format-in-oracle-apex-using-javascript/ 

Try this:

函数showdate () {

var a = new Date();
var b = a.getFullYear();
var c = a.getMonth();
(++c < 10)? c = "0" + c : c;
var d = a.getDate();
(d < 10)? d = "0" + d : d;
var final = b + "-" + c + "-" + d; 

return final;


} 

document.getElementById("todays_date").innerHTML = showdate();

另一种方法是使用toLocaleDateString与一个具有大端日期格式标准的地区，如瑞典，立陶宛，匈牙利，韩国，…:

date.toLocaleDateString('se')

删除分隔符(-)只是替换非数字的问题:

登录(新日期)。代表(/ / / D/g， ');

这不会像UTC日期格式那样产生潜在错误:与本地时区的日期相比，UTC日期可能相差一天。

我希望这个函数会有用

function formatDate(dDate,sMode){       
        var today = dDate;
        var dd = today.getDate();
        var mm = today.getMonth()+1; //January is 0!
        var yyyy = today.getFullYear();
        if(dd<10) {
            dd = '0'+dd
        } 
        if(mm<10) {
            mm = '0'+mm
        } 
        if (sMode+""==""){
            sMode = "dd/mm/yyyy";
        }
        if (sMode == "yyyy-mm-dd"){
            return  yyyy + "-" + mm + "-" + dd + "";
        }
        if (sMode == "dd/mm/yyyy"){
            return  dd + "/" + mm + "/" + yyyy;
        }

    }

我不喜欢修改本机对象，而且我认为乘法比填充接受的解决方案的字符串更清楚。

函数yyyymmdd(dateIn) { var yyyy = dateIn.getFullYear(); var mm = dateIn.getMonth() + 1;// getMonth()是从零开始的 var dd = dateIn.getDate(); 返回String(10000 * yyyy + 100 * mm + dd);// mm和dd的前导零 ｝ var today = new Date(); console.log(名称(今天));

小提琴:http://jsfiddle.net/gbdarren/Ew7Y4/