是否有一个很好的简单的方法来删除MySQL数据库中的所有表,忽略任何外键约束,可能在那里?
当前回答
只要在这里放上Jonathan Watt所做的一些有用的评论,就可以删除所有表格
MYSQL="mysql -h HOST -u USERNAME -pPASSWORD DB_NAME"
$MYSQL -BNe "show tables" | awk '{print "set foreign_key_checks=0; drop table `" $1 "`;"}' | $MYSQL
unset MYSQL
这对我有帮助,我希望它能有用
其他回答
下面是修改后的SurlyDre的存储过程,这样外键就被忽略了:
DROP PROCEDURE IF EXISTS `drop_all_tables`;
DELIMITER $$
CREATE PROCEDURE `drop_all_tables`()
BEGIN
DECLARE _done INT DEFAULT FALSE;
DECLARE _tableName VARCHAR(255);
DECLARE _cursor CURSOR FOR
SELECT table_name
FROM information_schema.TABLES
WHERE table_schema = SCHEMA();
DECLARE CONTINUE HANDLER FOR NOT FOUND SET _done = TRUE;
SET FOREIGN_KEY_CHECKS = 0;
OPEN _cursor;
REPEAT FETCH _cursor INTO _tableName;
IF NOT _done THEN
SET @stmt_sql = CONCAT('DROP TABLE ', _tableName);
PREPARE stmt1 FROM @stmt_sql;
EXECUTE stmt1;
DEALLOCATE PREPARE stmt1;
END IF;
UNTIL _done END REPEAT;
CLOSE _cursor;
SET FOREIGN_KEY_CHECKS = 1;
END$$
DELIMITER ;
call drop_all_tables();
DROP PROCEDURE IF EXISTS `drop_all_tables`;
从http://www.devdaily.com/blog/post/mysql/drop-mysql-tables-in-any-order-foreign-keys:
SET FOREIGN_KEY_CHECKS = 0;
drop table if exists customers;
drop table if exists orders;
drop table if exists order_details;
SET FOREIGN_KEY_CHECKS = 1;
(注意,这回答了如何禁用外键检查,以便能够以任意顺序删除表。它没有回答如何为所有现有的表自动生成drop-table语句,并在一个脚本中执行它们。Jean的回答是。)
这是一个基于游标的解决方案。有点长,但可以作为单个SQL批处理:
DROP PROCEDURE IF EXISTS `drop_all_tables`;
DELIMITER $$
CREATE PROCEDURE `drop_all_tables`()
BEGIN
DECLARE _done INT DEFAULT FALSE;
DECLARE _tableName VARCHAR(255);
DECLARE _cursor CURSOR FOR
SELECT table_name
FROM information_schema.TABLES
WHERE table_schema = SCHEMA();
DECLARE CONTINUE HANDLER FOR NOT FOUND SET _done = TRUE;
OPEN _cursor;
REPEAT FETCH _cursor INTO _tableName;
IF NOT _done THEN
SET @stmt_sql = CONCAT('DROP TABLE ', _tableName);
PREPARE stmt1 FROM @stmt_sql;
EXECUTE stmt1;
DEALLOCATE PREPARE stmt1;
END IF;
UNTIL _done END REPEAT;
CLOSE _cursor;
END$$
DELIMITER ;
call drop_all_tables();
DROP PROCEDURE IF EXISTS `drop_all_tables`;
上面的每个方法都包含了比这个AFAICT更多的工作…
( mysqldump --add-drop-table --no-data -u root -p database | grep 'DROP TABLE' ) > ./drop_all_tables.sql
mysql -u root -p database < ./drop_all_tables.sql
基于@Dion Truter和@Wade Williams的回答,下面的shell脚本将删除所有表,首先显示它将要运行的内容,并让您有机会使用Ctrl-C中止。
#!/bin/bash
DB_HOST=xxx
DB_USERNAME=xxx
DB_PASSWORD=xxx
DB_NAME=xxx
CMD="mysql -sN -h ${DB_HOST} -u ${DB_USERNAME} -p${DB_PASSWORD} ${DB_NAME}"
# Generate the drop statements
TMPFILE=/tmp/drop-${RANDOM}.sql
echo 'SET FOREIGN_KEY_CHECKS = 0;' > ${TMPFILE}
${CMD} $@ >> ${TMPFILE} << ENDD
SELECT concat('DROP TABLE IF EXISTS \`', table_name, '\`;')
FROM information_schema.tables
WHERE table_schema = '${DB_NAME}';
ENDD
echo 'SET FOREIGN_KEY_CHECKS = 1;' >> ${TMPFILE}
# Warn what we are about to do
echo
cat ${TMPFILE}
echo
echo "Press ENTER to proceed (or Ctrl-C to abort)."
read
# Run the SQL
echo "Dropping tables..."
${CMD} $@ < ${TMPFILE}
echo "Exit status is ${?}."
rm ${TMPFILE}