我需要做什么

我有一个不了解时区的datetime对象,我需要向它添加一个时区,以便能够将它与其他了解时区的datetime对象进行比较。我不想将我的整个应用程序转换为不知道这个遗留情况的时区。

我的努力

首先,演示问题:

Python 2.6.1 (r261:67515, Jun 24 2010, 21:47:49) 
[GCC 4.2.1 (Apple Inc. build 5646)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> import datetime
>>> import pytz
>>> unaware = datetime.datetime(2011,8,15,8,15,12,0)
>>> unaware
datetime.datetime(2011, 8, 15, 8, 15, 12)
>>> aware = datetime.datetime(2011,8,15,8,15,12,0,pytz.UTC)
>>> aware
datetime.datetime(2011, 8, 15, 8, 15, 12, tzinfo=<UTC>)
>>> aware == unaware
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: can't compare offset-naive and offset-aware datetimes

首先,我尝试了astimezone:

>>> unaware.astimezone(pytz.UTC)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: astimezone() cannot be applied to a naive datetime
>>>

这个失败并不奇怪,因为它实际上是在尝试进行转换。Replace似乎是一个更好的选择(如如何在Python中获得“时区感知”的datetime.today()值?):

>>> unaware.replace(tzinfo=pytz.UTC)
datetime.datetime(2011, 8, 15, 8, 15, 12, tzinfo=<UTC>)
>>> unaware == aware
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: can't compare offset-naive and offset-aware datetimes
>>> 

但正如您所看到的,replace似乎设置了tzinfo,但并没有使对象感知。我准备在解析输入字符串之前修改输入字符串以获得时区(如果有问题的话,我将使用dateutil进行解析),但这似乎非常笨拙。

此外,我在Python 2.6和Python 2.7中都尝试了这一点,得到了相同的结果。

上下文

I am writing a parser for some data files. There is an old format I need to support where the date string does not have a timezone indicator. I've already fixed the data source, but I still need to support the legacy data format. A one time conversion of the legacy data is not an option for various business BS reasons. While in general, I do not like the idea of hard-coding a default timezone, in this case it seems like the best option. I know with reasonable confidence that all the legacy data in question is in UTC, so I'm prepared to accept the risk of defaulting to that in this case.


当前回答

对于那些只是想使一个时区感知datetime

import datetime

datetime.datetime(2019, 12, 7, tzinfo=datetime.timezone.utc)

对于那些在python 3.9 stdlib中希望使用非utc时区的datetime的人

import datetime
from zoneinfo import ZoneInfo

datetime.datetime(2019, 12, 7, tzinfo=ZoneInfo("America/Los_Angeles")) 

其他回答

还有另一种让datetime对象不幼稚的方法:

>>> from datetime import datetime, timezone
>>> datetime.now(timezone.utc)
datetime.datetime(2021, 5, 1, 22, 51, 16, 219942, tzinfo=datetime.timezone.utc)

我同意之前的答案,如果你可以用UTC开始,那就没问题。但我认为,对于人们来说,使用具有非UTC本地时区的datetime的tz感知值也是一种常见的情况。

如果只按名称命名,可能会推断replace()将适用并生成正确的日期时间感知对象。事实并非如此。

替换(tzinfo=…)它的行为似乎是随机的。因此,它是无用的。不要用这个!

localalize是正确的函数。例子:

localdatetime_aware = tz.localize(datetime_nonaware)

或者一个更完整的例子:

import pytz
from datetime import datetime
pytz.timezone('Australia/Melbourne').localize(datetime.now())

给我当前本地时间的时区感知datetime值:

datetime.datetime(2017, 11, 3, 7, 44, 51, 908574, tzinfo=<DstTzInfo 'Australia/Melbourne' AEDT+11:00:00 DST>)

这是@Sérgio和@unutbu的答案。它将“只是工作”与任何一个pytz。对象或IANA时区字符串。

def make_tz_aware(dt, tz='UTC', is_dst=None):
    """Add timezone information to a datetime object, only if it is naive."""
    tz = dt.tzinfo or tz
    try:
        tz = pytz.timezone(tz)
    except AttributeError:
        pass
    return tz.localize(dt, is_dst=is_dst) 

这似乎是datetime. localalize()(或.inform()或. aware())应该做的事情,为tz参数接受字符串和时区对象,如果没有指定时区,则默认为UTC。

以上所有提到的方法,当它是Unix时间戳时,有一个非常简单的解决方案使用pandas。

import pandas as pd

unix_timestamp = 1513393355
pst_tz = pd.Timestamp(unix_timestamp, unit='s', tz='US/Pacific')
utc_tz = pd.Timestamp(unix_timestamp, unit='s', tz='UTC')

这里有一个简单的解决方案,以尽量减少对代码的更改:

from datetime import datetime
import pytz

start_utc = datetime.utcnow()
print ("Time (UTC): %s" % start_utc.strftime("%d-%m-%Y %H:%M:%S"))

时间(UTC): 09-01-2021 03:49:03

tz = pytz.timezone('Africa/Cairo')
start_tz = datetime.now().astimezone(tz)
print ("Time (RSA): %s" % start_tz.strftime("%d-%m-%Y %H:%M:%S"))

时间(RSA): 09-01-2021 05:49:03