对于文件和输入控件，我能想到的最简单的方法是:

  <%
      if (request.getContentType() == null)
          return;
      // For input type=text controls
      String v_Text =
          (new BufferedReader(new InputStreamReader(request.getPart("Text1").getInputStream()))).readLine();

      // For input type=file controls
      InputStream inStr = request.getPart("File1").getInputStream();
      char charArray[] = new char[inStr.available()];
      new InputStreamReader(inStr).read(charArray);
      String contents = new String(charArray);
  %>

在Tomcat 6或Tomcat 7中没有组件或外部库

在web.xml文件中启用上传:

手动安装PHP、Tomcat和Httpd Lounge。

<servlet>
    <servlet-name>jsp</servlet-name>
    <servlet-class>org.apache.jasper.servlet.JspServlet</servlet-class>
    <multipart-config>
      <max-file-size>3145728</max-file-size>
      <max-request-size>5242880</max-request-size>
    </multipart-config>
    <init-param>
        <param-name>fork</param-name>
        <param-value>false</param-value>
    </init-param>
    <init-param>
        <param-name>xpoweredBy</param-name>
        <param-value>false</param-value>
    </init-param>
    <load-on-startup>3</load-on-startup>
</servlet>

如你所见:

<multipart-config>
  <max-file-size>3145728</max-file-size>
  <max-request-size>5242880</max-request-size>
</multipart-config>

使用JSP上传文件。文件:

在HTML文件中

<form method="post" enctype="multipart/form-data" name="Form" >

  <input type="file" name="fFoto" id="fFoto" value="" /></td>
  <input type="file" name="fResumen" id="fResumen" value=""/>

在JSP文件或Servlet中

InputStream isFoto = request.getPart("fFoto").getInputStream();
InputStream isResu = request.getPart("fResumen").getInputStream();
ByteArrayOutputStream baos = new ByteArrayOutputStream();
byte buf[] = new byte[8192];
int qt = 0;
while ((qt = isResu.read(buf)) != -1) {
  baos.write(buf, 0, qt);
}
String sResumen = baos.toString();

编辑您的代码以满足servlet的要求，如max-file-size, max-request-size和其他选项，您可以设置…

为文件发送多个文件，我们必须使用enctype="multipart/form-data"。

如果要发送多个文件，在input标签中使用multiple="multiple":

<form action="upload" method="post" enctype="multipart/form-data">
    <input type="file" name="fileattachments"  multiple="multiple"/>
    <input type="submit" />
</form>

下面是一个使用apache common -fileupload的例子:

// apache commons-fileupload to handle file upload
DiskFileItemFactory factory = new DiskFileItemFactory();
factory.setRepository(new File(DataSources.TORRENTS_DIR()));
ServletFileUpload fileUpload = new ServletFileUpload(factory);

List<FileItem> items = fileUpload.parseRequest(req.raw());
FileItem item = items.stream()
  .filter(e ->
  "the_upload_name".equals(e.getFieldName()))
  .findFirst().get();
String fileName = item.getName();

item.write(new File(dir, fileName));
log.info(fileName);

对于文件和输入控件，我能想到的最简单的方法是:

  <%
      if (request.getContentType() == null)
          return;
      // For input type=text controls
      String v_Text =
          (new BufferedReader(new InputStreamReader(request.getPart("Text1").getInputStream()))).readLine();

      // For input type=file controls
      InputStream inStr = request.getPart("File1").getInputStream();
      char charArray[] = new char[inStr.available()];
      new InputStreamReader(inStr).read(charArray);
      String contents = new String(charArray);
  %>

Use:

DiskFileUpload upload = new DiskFileUpload();

从这个对象中你必须获得文件项和字段，然后你可以像下面这样存储到服务器中:

String loc = "./webapps/prjct name/server folder/" + contentid + extension;
File uploadFile = new File(loc);
item.write(uploadFile);