在Objective-C中有没有(stringByAppendingString:)字符串连接的快捷方式，或者一般使用NSString的快捷方式?
例如，我想做:
NSString *myString = @"This";
NSString *test = [myString stringByAppendingString:@" is just a test"];
更像是:
string myString = "This";
string test = myString + " is just a test";
当前回答
对于所有Objective C爱好者，在ui测试中需要这个:
-(void) clearTextField:(XCUIElement*) textField{
NSString* currentInput = (NSString*) textField.value;
NSMutableString* deleteString = [NSMutableString new];
for(int i = 0; i < currentInput.length; ++i) {
[deleteString appendString: [NSString stringWithFormat:@"%c", 8]];
}
[textField typeText:deleteString];
}
其他回答
NSString *result=[NSString stringWithFormat:@"%@ %@", @"Hello", @"World"];
我一直在看这篇文章，最后总是整理答案，找到一个简单的解决方案，可以根据需要处理尽可能多的变量:
[NSString stringWithFormat:@"%@/%@/%@", three, two, one];
例如:
NSString *urlForHttpGet = [NSString stringWithFormat:@"http://example.com/login/username/%@/userid/%i", userName, userId];
NSNumber *lat = [NSNumber numberWithDouble:destinationMapView.camera.target.latitude];
NSNumber *lon = [NSNumber numberWithDouble:destinationMapView.camera.target.longitude];
NSString *DesconCatenated = [NSString stringWithFormat:@"%@|%@",lat,lon];
这里有一个简单的方法，使用新的数组文字语法:
NSString * s = [@[@"one ", @"two ", @"three"] componentsJoinedByString:@""];
^^^^^^^ create array ^^^^^
^^^^^^^ concatenate ^^^^^
尝试stringWithFormat:
NSString *myString = [NSString stringWithFormat:@"%@ %@ %@ %d", "The", "Answer", "Is", 42];
