我想在Typescript对象中存储string ->字符串的映射,并强制所有值映射到字符串。例如:
var stuff = {};
stuff["a"] = "foo"; // okay
stuff["b"] = "bar"; // okay
stuff["c"] = false; // ERROR! bool != string
是否有一种方法让我强制值必须是字符串(或任何类型..)?
我想在Typescript对象中存储string ->字符串的映射,并强制所有值映射到字符串。例如:
var stuff = {};
stuff["a"] = "foo"; // okay
stuff["b"] = "bar"; // okay
stuff["c"] = false; // ERROR! bool != string
是否有一种方法让我强制值必须是字符串(或任何类型..)?
当前回答
type KeyOf<T> = keyof T;
class SomeClass<T, R> {
onlyTFieldsAllowed = new Map<KeyOf<T>, R>();
}
class A {
myField = 'myField';
}
const some = new SomeClass<A, any>();
some.onlyTFieldsAllowed.set('myField', 'WORKS');
some.onlyTFieldsAllowed.set('noneField', 'Not Allowed!');
其他回答
var stuff: { [key: string]: string; } = {};
stuff['a'] = ''; // ok
stuff['a'] = 4; // error
// ... or, if you're using this a lot and don't want to type so much ...
interface StringMap { [key: string]: string; }
var stuff2: StringMap = { };
// same as above
实际上有一个内置的实用程序记录:
const record: Record<string, string> = {};
record['a'] = 'b';
record[1] = 'c'; // leads to typescript error
record['d'] = 1; // leads to typescript error
你可以传递一个名字给未知键,然后写你的类型:
type StuffBody = {
[key: string]: string;
};
现在你可以在你的类型检查中使用它:
let stuff: StuffBody = {};
但对于FlowType,不需要有名称:
type StuffBody = {
[string]: string,
};
基于@shabunc的答案,这将允许将键或值(或两者都是)强制为您想强制的任何值。
type IdentifierKeys = 'my.valid.key.1' | 'my.valid.key.2';
type IdentifierValues = 'my.valid.value.1' | 'my.valid.value.2';
let stuff = new Map<IdentifierKeys, IdentifierValues>();
也应该使用enum而不是类型定义。
定义接口
interface Settings {
lang: 'en' | 'da';
welcome: boolean;
}
强制键为设置界面的特定键
private setSettings(key: keyof Settings, value: any) {
// Update settings key
}