在Flask中重定向到URL

我想做的是类似于回应。重定向作为在c# -即:重定向到一个特定的URL -我怎么去做这个?

这是我的代码:

import os
from flask import Flask

app = Flask(__name__)

@app.route('/')
def hello():
    return 'Hello World!'

if __name__ == '__main__':
    # Bind to PORT if defined, otherwise default to 5000.
    port = int(os.environ.get('PORT', 5000))
    app.run(host='0.0.0.0', port=port)

当前回答

如何重定向用户/请求在Flask

在API处理程序函数中抛出错误将把用户重定向到可以处理重定向的错误处理程序。或者你也可以像其他人说的那样调用重定向，但这是另一种重定向未经授权用户的方式。为了说明我的意思，我在下面提供了一个示例。

在用户应获授权的情况下

首先让我们假设你有一条被保护的路由，你像这样保护它。

def handle_api_auth(func):
    """
    **handle_api_auth**
        wrapper to handle public api calls authentications

    :param func: a function to be wrapped
    :return: wrapped function
    """

    @functools.wraps(func)
    def auth_wrapper(*args, **kwargs):
        api_key: Optional[str] = request.headers.get('x-api-key')
        secret_token: Optional[str] = request.headers.get('x-secret-token')
        domain: Optional[str] = request.base_url
        if is_request_valid(api_key=api_key, secret=secret_token, domain=domain):
            return func(*args, **kwargs)
        # NOTE: throwing an Error Here will redirect your user to an error handler or alteratively you can just call redirect like everyone else is saying, but this is another way of redirecting unathorized users
        message: str = "request not authorized"
        raise UnAuthenticatedError(status=error_codes.un_auth_error_code, description=message)

    return auth_wrapper

is_request_valid的定义如下

@app_cache.cache.memoize(timeout=15 * 60, cache_none=False)  # timeout equals fifteen minutes // 900 seconds
def is_request_valid(api_key: str, secret: str, domain: str) -> bool:
    """
    **is_api_key_valid**
        validates api keys on behalf of client api calls

    :param api_key: str -> api_key to check
    :param secret: str -> secret token
    :param domain: str -> domain registered for the api_key and secret_token
    :return: bool -> True if api_key is valid
    """

    organization_id: str = config_instance.ORGANIZATION_ID
    # NOTE: lets assumy api_keys_view.get_api_key will return the api keys from some database somewhere
    response = api_keys_view.get_api_key(api_key=api_key, organization_id=organization_id)

    response_data, status_code = response
    response_dict = response_data.get_json()

    if not response_dict.get('status'):
        return False

    api_instance: dict = response_dict.get('payload')
    if not isinstance(api_instance, dict):
        return False

    domain: str = domain.lower().strip()
    # NOTE accessing the keys this way will throw ValueError if keys are not available which is what we want
    # Any Error which gets thrown Ridirects the Users from the path the user is on to an error handler.
    is_secret_valid: bool = hmac.compare_digest(api_instance['secret_token'], secret)
    is_domain_valid: bool = hmac.compare_digest(api_instance['domain'], domain)
    _request_valid: bool = is_secret_valid and is_domain_valid

    return not not api_instance.get('is_active') if _request_valid else False

像这样定义错误处理程序

from flask import Blueprint, jsonify, request, redirect
from werkzeug.exceptions Unauthorized

error_handler = BluePrint('error_handlers', __name__)

@error_handler.app_errorhandler(Unauthorized)
def handle_error(e : Unauthorized) -> tuple:
    """default unath handler"""
    return jsonify(dict(message=e.description)), e.code if request.headers.get('content-type') == 'application/json' else redirect('/login')

以同样的方式处理其他错误，并注意万一请求是

不是json，用户被重定向到登录页面如果json用户得到一个unathecated的响应，那么它到前端处理Unath错误..

2021-09-11 12:15:58

其他回答

你可以这样用:

import os
from flask import Flask

app = Flask(__name__)

@app.route('/')
def hello():
     # Redirect from here, replace your custom site url "www.google.com"
    return redirect("https://www.google.com", code=200)

if __name__ == '__main__':
    # Bind to PORT if defined, otherwise default to 5000.
    port = int(os.environ.get('PORT', 5000))
    app.run(host='0.0.0.0', port=port)

下面是该代码的引用链接。

2020-03-02 12:57:04

#!/usr/bin/env python
# -*- coding: utf-8 -*-

import os
from flask import Flask, redirect, url_for

app = Flask(__name__)

@app.route('/')
def hello():
    return redirect(url_for('foo'))

@app.route('/foo')
def foo():
    return 'Hello Foo!'

if __name__ == '__main__':
    # Bind to PORT if defined, otherwise default to 5000.
    port = int(os.environ.get('PORT', 5000))
    app.run(host='0.0.0.0', port=port)

请查看文档中的示例。

2013-01-15 18:05:21

你必须返回一个重定向:

import os
from flask import Flask,redirect

app = Flask(__name__)

@app.route('/')
def hello():
    return redirect("http://www.example.com", code=302)

if __name__ == '__main__':
    # Bind to PORT if defined, otherwise default to 5000.
    port = int(os.environ.get('PORT', 5000))
    app.run(host='0.0.0.0', port=port)

请参阅有关flask文档的文档。code的默认值是302，因此code=302可以被省略或替换为其他重定向代码(301、302、303、305和307中的一个)。

2013-01-15 18:03:43

这很容易，如果你只是想重定向到一个url没有任何状态码或类似的东西，你可以简单地说

from flask import Flask, redirect

app = Flask(__name__)

@app.route('/')
def redirect_to_link():
    # return redirect method, NOTE: replace google.com with the link u want
    return redirect('https://google.com')

这里是Flask Docs的链接，可以获得更多的解释

2020-07-13 16:08:42