不能解决equal - to操作中“SQL_Latin1_General_CP1_CI_AS”和“Latin1_General_CI_AS”之间的排序冲突

我有下面的代码

SELECT tA.FieldName As [Field Name],
       COALESCE(tO_A.[desc], tO_B.[desc], tO_C.Name, tA.OldVAlue) AS [Old Value],
       COALESCE(tN_A.[desc], tN_B.[desc], tN_C.Name, tA.NewValue) AS [New Value],
       U.UserName AS [User Name],
       CONVERT(varchar, tA.ChangeDate) AS [Change Date] 
  FROM D tA
       JOIN 
       [DRTS].[dbo].[User] U 
         ON tA.UserID = U.UserID
       LEFT JOIN 
       A tO_A 
         on tA.FieldName = 'AID' 
        AND tA.oldValue = CONVERT(VARCHAR, tO_A.ID)
       LEFT JOIN 
       A tN_A 
         on tA.FieldName = 'AID' 
        AND tA.newValue = CONVERT(VARCHAR, tN_A.ID)
       LEFT JOIN 
       B tO_B 
         on tA.FieldName = 'BID' 
        AND tA.oldValue = CONVERT(VARCHAR, tO_B.ID)
       LEFT JOIN 
       B tN_B 
         on tA.FieldName = 'BID' 
        AND tA.newValue = CONVERT(VARCHAR, tN_B.ID)
       LEFT JOIN 
       C tO_C 
         on tA.FieldName = 'CID' 
        AND tA.oldValue = tO_C.Name
       LEFT JOIN 
       C tN_C 
         on tA.FieldName = 'CID' 
        AND tA.newValue = tN_C.Name
 WHERE U.Fullname = @SearchTerm
ORDER BY tA.ChangeDate

当运行代码时，我在添加表c的两个连接后，将错误粘贴在标题中。我认为这可能与我使用SQL Server 2008的事实有关，并在2005年的机器上恢复了这个db的副本。

当前回答

我使用了这个网站的内容来创建以下脚本，它改变了所有表中所有列的排序规则:

CREATE PROCEDURE [dbo].[sz_pipeline001_collation] 
    -- Add the parameters for the stored procedure here
AS
BEGIN
    -- SET NOCOUNT ON added to prevent extra result sets from
    -- interfering with SELECT statements.
    SET NOCOUNT ON;


SELECT 'ALTER TABLE [' + SYSOBJECTS.Name + '] ALTER COLUMN [' + SYSCOLUMNS.Name + '] ' +
SYSTYPES.name + 
    CASE systypes.NAME
    WHEN 'text' THEN ' '
    ELSE
    '(' + RTRIM(CASE SYSCOLUMNS.length
    WHEN -1 THEN 'MAX'
    ELSE CONVERT(CHAR,SYSCOLUMNS.length)
    END) + ') ' 
    END

    + ' ' + ' COLLATE Latin1_General_CI_AS ' + CASE ISNULLABLE WHEN 0 THEN 'NOT NULL' ELSE 'NULL' END
    FROM SYSCOLUMNS , SYSOBJECTS , SYSTYPES
    WHERE SYSCOLUMNS.ID = SYSOBJECTS.ID
    AND SYSOBJECTS.TYPE = 'U'
    AND SYSTYPES.Xtype = SYSCOLUMNS.xtype
    AND SYSCOLUMNS.COLLATION IS NOT NULL
    AND NOT ( sysobjects.NAME LIKE 'sys%' )
    AND NOT ( SYSTYPES.name LIKE 'sys%' )

END

2015-06-04 08:39:05

其他回答

检查不匹配的排序规则级别(服务器、数据库、表、列、字符)。

如果是服务器，这些步骤曾经帮助过我:

停止服务器找到sqlservr.exe工具执行如下命令: sqlservr -m -T4022 -T3659 -s" name_of_instance " q“name_of_collation” 启动sql server: Net启动name_of_instance 再次检查服务器的排序规则。

以下是更多信息:

https://www.mssqltips.com/sqlservertip/3519/changing-sql-server-collation-after-installation/

2017-04-24 11:57:19

你可以通过4个简单的步骤轻松做到这一点

备份你的数据库，以防万一更改数据库排序规则:右键单击数据库，选择属性，转到选项并将排序规则更改为所需的排序规则。生成一个脚本来删除和重新创建所有数据库对象:右键单击数据库，选择任务，选择生成脚本…(请确保在向导的高级选项中选择了删除和创建，并选择模式和数据) 运行上面生成的脚本

2015-11-22 16:39:55

INSERT INTO eSSLSmartOfficeSource2.[dbo].DeviceLogs  (DeviceId,UserId,LogDate,UpdateFlag) 
SELECT DL1.DeviceId ,DL1.UserId COLLATE DATABASE_DEFAULT,DL1.LogDate 
,0 FROM eSSLSmartOffice.[dbo].DeviceLogs DL1 
WHERE  NOT EXISTS 
(SELECT DL2.DeviceId ,DL2.UserId COLLATE DATABASE_DEFAULT
,DL2.LogDate ,DL2.UpdateFlag 
FROM eSSLSmartOfficeSource2.[dbo].DeviceLogs DL2    
WHERE  DL1.DeviceId =DL2.DeviceId
 and DL1.UserId collate  Latin1_General_CS_AS=DL2.UserId collate  Latin1_General_CS_AS
  and DL1.LogDate =DL2.LogDate )

2018-03-08 06:34:25

如果这种情况发生在整个数据库中，那么最好像这样改变你的数据库排序规则:

USE master;  
GO  
ALTER DATABASE MyOptionsTest  
COLLATE << INSERT COLATION REQUIRED >> ;  
GO  

--Verify the collation setting.  
SELECT name, collation_name  
FROM sys.databases  
WHERE name = N'<< INSERT DATABASE NAME >>';  
GO

参考这里

2018-01-25 09:37:54

错误(无法解决....之间的排序冲突)通常在比较来自多个数据库的数据时发生。

因为你现在不能改变数据库的排序规则，所以使用COLLATE DATABASE_DEFAULT。

----------
AND db1.tbl1.fiel1 COLLATE DATABASE_DEFAULT =db2.tbl2.field2 COLLATE DATABASE_DEFAULT

2017-12-15 14:09:29

不能解决equal - to操作中“SQL_Latin1_General_CP1_CI_AS”和“Latin1_General_CI_AS”之间的排序冲突

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