我有一个非常简单的JavaScript数组,可能包含也可能不包含重复项。
var names = ["Mike","Matt","Nancy","Adam","Jenny","Nancy","Carl"];
我需要删除重复项并将唯一值放入新数组。
我可以指出我尝试过的所有代码,但我认为它们没有用,因为它们不起作用。我也接受jQuery解决方案。
类似的问题:
获取数组中的所有非唯一值(即:重复/多次出现)
我有一个非常简单的JavaScript数组,可能包含也可能不包含重复项。
var names = ["Mike","Matt","Nancy","Adam","Jenny","Nancy","Carl"];
我需要删除重复项并将唯一值放入新数组。
我可以指出我尝试过的所有代码,但我认为它们没有用,因为它们不起作用。我也接受jQuery解决方案。
类似的问题:
获取数组中的所有非唯一值(即:重复/多次出现)
当前回答
function removeDuplicates(inputArray) {
var outputArray=new Array();
if(inputArray.length>0){
jQuery.each(inputArray, function(index, value) {
if(jQuery.inArray(value, outputArray) == -1){
outputArray.push(value);
}
});
}
return outputArray;
}
其他回答
VanillaJS:使用像Set这样的Object删除重复项
您可以始终尝试将其放入对象中,然后遍历其关键点:
function remove_duplicates(arr) {
var obj = {};
var ret_arr = [];
for (var i = 0; i < arr.length; i++) {
obj[arr[i]] = true;
}
for (var key in obj) {
ret_arr.push(key);
}
return ret_arr;
}
Vanilla JS:通过跟踪已经看到的值来删除重复项(订单安全)
或者,对于订单安全版本,使用一个对象来存储所有以前看到的值,并在添加到数组之前检查值。
function remove_duplicates_safe(arr) {
var seen = {};
var ret_arr = [];
for (var i = 0; i < arr.length; i++) {
if (!(arr[i] in seen)) {
ret_arr.push(arr[i]);
seen[arr[i]] = true;
}
}
return ret_arr;
}
ECMAScript 6:使用新的Set数据结构(顺序安全)
ECMAScript 6添加了新的Set Data Structure,它允许您存储任何类型的值。Set.values按插入顺序返回元素。
function remove_duplicates_es6(arr) {
let s = new Set(arr);
let it = s.values();
return Array.from(it);
}
示例用法:
a = ["Mike","Matt","Nancy","Adam","Jenny","Nancy","Carl"];
b = remove_duplicates(a);
// b:
// ["Adam", "Carl", "Jenny", "Matt", "Mike", "Nancy"]
c = remove_duplicates_safe(a);
// c:
// ["Mike", "Matt", "Nancy", "Adam", "Jenny", "Carl"]
d = remove_duplicates_es6(a);
// d:
// ["Mike", "Matt", "Nancy", "Adam", "Jenny", "Carl"]
这里非常简单,可以在任何地方(甚至在PhotoshopScript中)理解和工作代码。检查一下!
var peoplenames = new Array("Mike","Matt","Nancy","Adam","Jenny","Nancy","Carl");
peoplenames = unique(peoplenames);
alert(peoplenames);
function unique(array){
var len = array.length;
for(var i = 0; i < len; i++) for(var j = i + 1; j < len; j++)
if(array[j] == array[i]){
array.splice(j,1);
j--;
len--;
}
return array;
}
//*result* peoplenames == ["Mike","Matt","Nancy","Adam","Jenny","Carl"]
var uniqueCompnies = function(companyArray) {
var arrayUniqueCompnies = [],
found, x, y;
for (x = 0; x < companyArray.length; x++) {
found = undefined;
for (y = 0; y < arrayUniqueCompnies.length; y++) {
if (companyArray[x] === arrayUniqueCompnies[y]) {
found = true;
break;
}
}
if ( ! found) {
arrayUniqueCompnies.push(companyArray[x]);
}
}
return arrayUniqueCompnies;
}
var arr = [
"Adobe Systems Incorporated",
"IBX",
"IBX",
"BlackRock, Inc.",
"BlackRock, Inc.",
];
删除重复项的最简单方法是执行for循环,比较不同的元素并将它们推入新数组
var array = ["Mike","Matt","Nancy","Adam","Jenny","Nancy","Carl"];
var removeDublicate = function(arr){
var result = []
var sort_arr = arr.sort() //=> optional
for (var i = 0; i < arr.length; i++) {
if(arr[ i + 1] !== arr[i] ){
result.push(arr[i])
}
};
return result
}
console.log(removeDublicate(array))
==> ["Adam", "Carl", "Jenny", "Matt", "Mike", "Nancy"]
如果不想包含整个库,可以使用此选项添加任何数组都可以使用的方法:
Array.prototype.uniq = function uniq() {
return this.reduce(function(accum, cur) {
if (accum.indexOf(cur) === -1) accum.push(cur);
return accum;
}, [] );
}
["Mike","Matt","Nancy","Adam","Jenny","Nancy","Carl"].uniq()