我试图将一些文本数据插入到SQL Server 9中的表中。
文本中包含了一个引用。
我怎么逃脱呢?
我尝试使用两个单引号,但它给我带来了一些错误。
如。插入my_table值('hi, my name' s tim.');
我试图将一些文本数据插入到SQL Server 9中的表中。
文本中包含了一个引用。
我怎么逃脱呢?
我尝试使用两个单引号,但它给我带来了一些错误。
如。插入my_table值('hi, my name' s tim.');
当前回答
Also another thing to be careful of is whether or not it is really stored as a classic ASCII ' (ASCII 27) or Unicode 2019 (which looks similar, but not the same). This isn't a big deal on inserts, but it can mean the world on selects and updates. If it's the unicode value then escaping the ' in a WHERE clause (e.g where blah = 'Workers''s Comp') will return like the value you are searching for isn't there if the ' in "Worker's Comp" is actually the unicode value.If your client application supports free-key, as well as copy and paste based input, it could be Unicode in some rows, and ASCII in others! A simple way to confirm this is by doing some kind of open ended query that will bring back the value you are searching for, and then copy and paste that into notepad++ or some other unicode supporting editor. The differing appearance between the ascii value and the unicode one should be obvious to the eyes, but if you lean towards the anal, it will show up as 27 (ascii) or 92 (unicode) in a hex editor.
其他回答
我也遇到了同样的问题,但我的问题不是基于SQL代码本身中的静态数据,而是基于数据中的值。
这段代码列出了我的数据库中所有的列名和数据类型:
SELECT DISTINCT QUOTENAME(COLUMN_NAME),DATA_TYPE FROM INFORMATION_SCHEMA.COLUMNS
但是有些列名实际上在列名中嵌入了单引号!,例如……
[MyTable].[LEOS'DATACOLUMN]
为了处理这些,我必须使用REPLACE函数以及建议的QUOTED_IDENTIFIER设置。否则,在动态SQL中使用该列时会出现语法错误。
SET QUOTED_IDENTIFIER OFF;
SET @sql = 'SELECT DISTINCT ''' + @TableName + ''',''' + REPLACE(@ColumnName,"'","''") + ...etc
SET QUOTED_IDENTIFIER ON;
如何:
insert into my_table values('hi, my name' + char(39) + 's tim.')
下面的语法将只转义一个引号:
SELECT ''''
结果将是一个单引号。对于创建动态SQL:)可能非常有帮助。
有两种方法可以解决这个问题:
对于',你可以简单地在字符串中加倍它,例如。 选择'I' m happy '——将得到:I'm happy
对于任何你不确定的字符:在sql server中,你可以通过选择unicode(':')来获得任何字符的unicode(你保留这个数字)
在这种情况下你还可以选择I +nchar(39)+ m happy
通过将单引号加倍来转义,就像您在示例中展示的那样。下面的SQL说明了这个功能。我在SQL Server 2008上进行了测试:
DECLARE @my_table TABLE (
[value] VARCHAR(200)
)
INSERT INTO @my_table VALUES ('hi, my name''s tim.')
SELECT * FROM @my_table
结果
value
==================
hi, my name's tim.