我刚来拉拉维尔。如何查找是否存在记录?
$user = User::where('email', '=', Input::get('email'));
我能做什么来查看$user是否有记录?
我刚来拉拉维尔。如何查找是否存在记录?
$user = User::where('email', '=', Input::get('email'));
我能做什么来查看$user是否有记录?
当前回答
我解决了这个问题,使用empty()函数:
$user = User::where('email', Input::get('email'))->get()->first();
//for example:
if (!empty($user))
User::destroy($user->id);
其他回答
最短工作选项:
// if you need to do something with the user
if ($user = User::whereEmail(Input::get('email'))->first()) {
// ...
}
// otherwise
$userExists = User::whereEmail(Input::get('email'))->exists();
简单地用这个来判断真假 $ user =用户::(“电子邮件”、“=”,输入::('邮件'))- >存在(); 如果你想要$user with result,你可以使用这个, $ user =用户::(“电子邮件”、“=”,输入::('邮件'))- > ();
像这样检查结果,
if(count($user)>0){}
你也可以用这个, $ user =用户::(“电子邮件”、“=”,输入::('邮件')); 如果存在($ user - > ()) { $user = $user->get(); }
$userCnt = User::where("id",1)->count();
if( $userCnt ==0 ){
//////////record not exists
}else{
//////////record exists
}
注:其中条件根据您的要求。
Laravel 6或顶部:写表名,然后给出where子句条件,例如where('id', $request->id)
public function store(Request $request)
{
$target = DB:: table('categories')
->where('title', $request->name)
->get()->first();
if ($target === null) { // do what ever you need to do
$cat = new Category();
$cat->title = $request->input('name');
$cat->parent_id = $request->input('parent_id');
$cat->user_id=auth()->user()->id;
$cat->save();
return redirect(route('cats.app'))->with('success', 'App created successfully.');
}else{ // match found
return redirect(route('cats.app'))->with('error', 'App already exists.');
}
}
在你的控制器中
$this->validate($request, [
'email' => 'required|unique:user|email',
]);
在您的视图-显示已经存在的消息
@if (count($errors) > 0)
<div class="alert alert-danger">
<ul>
@foreach ($errors->all() as $error)
<li>{{ $error }}</li>
@endforeach
</ul>
</div>
@endif