我如何检测当一个方向键被按下?我用这个找到了答案:

function checkKey(e) {
    var event = window.event ? window.event : e;
    console.log(event.keyCode)
}

虽然它适用于所有其他键,但它不适用于方向键(可能是因为浏览器默认情况下应该在这些键上滚动)。


当前回答

这是chrome和firefox的工作代码

<html>
<head>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.1/jquery.min.js"></script>

<script type="text/javascript">

    function leftArrowPressed() {
      alert("leftArrowPressed" );
      window.location = prevUrl  
    }

    function rightArrowPressed() {
      alert("rightArrowPressed" );
      window.location = nextUrl  
    }
    function topArrowPressed() {
      alert("topArrowPressed" );
      window.location = prevUrl  
    }

    function downArrowPressed() {
      alert("downArrowPressed" );
      window.location = nextUrl  
    }

        document.onkeydown = function(evt) {
                        var nextPage = $("#next_page_link")
                        var prevPage = $("#previous_page_link")
                        nextUrl = nextPage.attr("href")
                        prevUrl = prevPage.attr("href")
        evt = evt || window.event;
        switch (evt.keyCode) {
                case 37:
                leftArrowPressed(nextUrl);
                break;

                case 38:
                topArrowPressed(nextUrl);
                break;

                 case 39:
                rightArrowPressed(prevUrl);
                break;

                case 40:
                downArrowPressed(prevUrl);
                break;

        }
    };


</script>
</head>
<body>
<p>
<a id="previous_page_link" href="http://www.latest-tutorial.com">Latest Tutorials</a> 
<a id="next_page_link" href="http://www.zeeshanakhter.com">Zeeshan Akhter</a>
 </p>
</body>
</html>

其他回答

对于不可打印的键,如方向键,使用向下键,而不是按下键:

function checkKey(e) {
    e = e || window.event;
    alert(e.keyCode);
}

document.onkeydown = checkKey;

我找到的最好的JavaScript键事件参考资料(例如,打败quirksmode)在这里:http://unixpapa.com/js/key.html

这个图书馆真棒! https://craig.is/killing/mice

Mousetrap.bind('up up down down left right left right b a enter', function() {
    highlight([21, 22, 23]);
});

不过,您需要快速按下序列以突出显示该页中的代码。

如果你想检测箭头按键,但不需要特定的Javascript

function checkKey(e) {
   if (e.keyCode !== 38 || e.keyCode !== 40 || e.keyCode !== 37 || e.keyCode !== 39){
    // do something
   };
}

这是chrome和firefox的工作代码

<html>
<head>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.1/jquery.min.js"></script>

<script type="text/javascript">

    function leftArrowPressed() {
      alert("leftArrowPressed" );
      window.location = prevUrl  
    }

    function rightArrowPressed() {
      alert("rightArrowPressed" );
      window.location = nextUrl  
    }
    function topArrowPressed() {
      alert("topArrowPressed" );
      window.location = prevUrl  
    }

    function downArrowPressed() {
      alert("downArrowPressed" );
      window.location = nextUrl  
    }

        document.onkeydown = function(evt) {
                        var nextPage = $("#next_page_link")
                        var prevPage = $("#previous_page_link")
                        nextUrl = nextPage.attr("href")
                        prevUrl = prevPage.attr("href")
        evt = evt || window.event;
        switch (evt.keyCode) {
                case 37:
                leftArrowPressed(nextUrl);
                break;

                case 38:
                topArrowPressed(nextUrl);
                break;

                 case 39:
                rightArrowPressed(prevUrl);
                break;

                case 40:
                downArrowPressed(prevUrl);
                break;

        }
    };


</script>
</head>
<body>
<p>
<a id="previous_page_link" href="http://www.latest-tutorial.com">Latest Tutorials</a> 
<a id="next_page_link" href="http://www.zeeshanakhter.com">Zeeshan Akhter</a>
 </p>
</body>
</html>

控制键码%=37和&=38…只有箭头键左=37向上=38

function IsArrows (e) {
   return ( !evt.shiftKey && (e.keyCode >= 37 && e.keyCode <= 40)); 
}