我想检查设备的iOS版本是否大于3.1.3 我尝试了以下方法:

[[UIDevice currentDevice].systemVersion floatValue]

但是不管用,我只想要一个:

if (version > 3.1.3) { }

我怎样才能做到这一点呢?


当前回答

在您的项目中添加以下Swift代码,并轻松访问iOS版本和设备等信息。

class DeviceInfo: NSObject {

    struct ScreenSize
    {
        static let SCREEN_WIDTH = UIScreen.main.bounds.size.width
        static let SCREEN_HEIGHT = UIScreen.main.bounds.size.height
        static let SCREEN_MAX_LENGTH = max(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
        static let SCREEN_MIN_LENGTH = min(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
    }

    struct DeviceType
    {
        static let IS_IPHONE_4_OR_LESS =  UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH < 568.0
        static let IS_IPHONE_5 = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 568.0
        static let IS_IPHONE_6 = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH >= 667.0
        static let IS_IPHONE_6P = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 736.0
        static let IS_IPHONE_X = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 812.0
        static let IS_IPAD      = UIDevice.current.userInterfaceIdiom == .pad && ScreenSize.SCREEN_MAX_LENGTH == 1024.0
        static let IS_IPAD_PRO  = UIDevice.current.userInterfaceIdiom == .pad && ScreenSize.SCREEN_MAX_LENGTH == 1366.0
    }

    struct VersionType{
        static let SYS_VERSION_FLOAT = (UIDevice.current.systemVersion as NSString).floatValue
        static let iOS7 = (VersionType.SYS_VERSION_FLOAT < 8.0 && VersionType.SYS_VERSION_FLOAT >= 7.0)
        static let iOS8 = (VersionType.SYS_VERSION_FLOAT >= 8.0 && VersionType.SYS_VERSION_FLOAT < 9.0)
        static let iOS9 = (VersionType.SYS_VERSION_FLOAT >= 9.0 && VersionType.SYS_VERSION_FLOAT < 10.0)
        static let iOS10 = (VersionType.SYS_VERSION_FLOAT >= 9.0 && VersionType.SYS_VERSION_FLOAT < 11.0)
    }
}

其他回答

Try:

NSComparisonResult order = [[UIDevice currentDevice].systemVersion compare: @"3.1.3" options: NSNumericSearch];
if (order == NSOrderedSame || order == NSOrderedDescending) {
    // OS version >= 3.1.3
} else {
    // OS version < 3.1.3
}

快速的例子,实际工作:

switch UIDevice.currentDevice().systemVersion.compare("8.0.0", options: NSStringCompareOptions.NumericSearch) {
case .OrderedSame, .OrderedDescending:
    println("iOS >= 8.0")
case .OrderedAscending:
    println("iOS < 8.0")
}

不要使用NSProcessInfo,因为它在8.0下不能工作,所以它在2016年之前几乎没用

我的解决方案是向您的实用程序类(提示提示)添加一个实用程序方法来解析系统版本并手动补偿浮点数排序。

此外,这段代码相当简单,所以我希望它能帮助一些新手。简单地传入一个目标浮点数,然后返回BOOL类型。

在你的共享类中这样声明它:

(+) (BOOL) iOSMeetsOrExceedsVersion:(float)targetVersion;

这样叫它:

BOOL shouldBranch = [SharedClass iOSMeetsOrExceedsVersion:5.0101];

(+) (BOOL) iOSMeetsOrExceedsVersion:(float)targetVersion {

/*
 Note: the incoming targetVersion should use 2 digits for each subVersion --

 example 5.01 for v5.1, 5.11 for v5.11 (aka subversions above 9), 5.0101 for v5.1.1, etc.
*/

// Logic: as a string, system version may have more than 2 segments (example: 5.1.1)
// so, a direct conversion to a float may return an invalid number
// instead, parse each part directly

NSArray *sysVersion = [[UIDevice currentDevice].systemVersion componentsSeparatedByString:@"."];
float floatVersion = [[sysVersion objectAtIndex:0] floatValue];
if (sysVersion.count > 1) {
    NSString* subVersion = [sysVersion objectAtIndex:1];
    if (subVersion.length == 1)
        floatVersion += ([[sysVersion objectAtIndex:1] floatValue] *0.01);
    else
        floatVersion += ([[sysVersion objectAtIndex:1] floatValue] *0.10);
}
if (sysVersion.count > 2) {
    NSString* subVersion = [sysVersion objectAtIndex:2];
    if (subVersion.length == 1)
        floatVersion += ([[sysVersion objectAtIndex:2] floatValue] *0.0001);
    else
        floatVersion += ([[sysVersion objectAtIndex:2] floatValue] *0.0010);
}

if (floatVersion  >= targetVersion) 
    return TRUE;

// else
return FALSE;
 }

首选的方法

在Swift 2.0中,苹果使用更方便的语法添加了可用性检查(点击这里阅读更多)。现在你可以用更简洁的语法检查操作系统版本:

if #available(iOS 9, *) {
    // Then we are on iOS 9
} else {
    // iOS 8 or earlier
}

这是首选检查respondsToSelector等(什么是新的在Swift)。现在,如果你没有正确地保护你的代码,编译器总是会警告你。


斯威夫特2.0

iOS 8的新功能是NSProcessInfo,允许更好的语义版本检查。

在iOS 8及更高版本上部署

对于iOS 8.0或以上版本的最低部署目标,使用NSProcessInfo operatingSystemVersion或isOperatingSystemAtLeastVersion。

这将产生以下结果:

let minimumVersion = NSOperatingSystemVersion(majorVersion: 8, minorVersion: 1, patchVersion: 2)
if NSProcessInfo().isOperatingSystemAtLeastVersion(minimumVersion) {
    //current version is >= (8.1.2)
} else {
    //current version is < (8.1.2)
}

在iOS 7上部署

对于iOS 7.1或以下的最低部署目标,使用compare with NSStringCompareOptions。UIDevice systemVersion上的NumericSearch。

这将产生:

let minimumVersionString = "3.1.3"
let versionComparison = UIDevice.currentDevice().systemVersion.compare(minimumVersionString, options: .NumericSearch)
switch versionComparison {
    case .OrderedSame, .OrderedDescending:
        //current version is >= (3.1.3)
        break
    case .OrderedAscending:
        //current version is < (3.1.3)
        fallthrough
    default:
        break;
}

更多阅读请访问NSHipster。

一个在obj - c++ 11中更通用的版本(你可能会用NSString/C函数替换其中的一些东西,但这不是那么冗长。这给了你两种机制。splitSystemVersion为你提供了一个包含所有部分的数组,如果你只是想打开主版本(例如switch([self splitSystemVersion][0]) {case 4: break;案例5:断裂;})。

#include <boost/lexical_cast.hpp>

- (std::vector<int>) splitSystemVersion {
    std::string version = [[[UIDevice currentDevice] systemVersion] UTF8String];
    std::vector<int> versions;
    auto i = version.begin();

    while (i != version.end()) {
        auto nextIllegalChar = std::find_if(i, version.end(), [] (char c) -> bool { return !isdigit(c); } );
        std::string versionPart(i, nextIllegalChar);
        i = std::find_if(nextIllegalChar, version.end(), isdigit);

        versions.push_back(boost::lexical_cast<int>(versionPart));
    }

    return versions;
}

/** Losslessly parse system version into a number
 * @return <0>: the version as a number,
 * @return <1>: how many numeric parts went into the composed number. e.g.
 * X.Y.Z = 3.  You need this to know how to compare again <0>
 */
- (std::tuple<int, int>) parseSystemVersion {
    std::string version = [[[UIDevice currentDevice] systemVersion] UTF8String];
    int versionAsNumber = 0;
    int nParts = 0;

    auto i = version.begin();
    while (i != version.end()) {
        auto nextIllegalChar = std::find_if(i, version.end(), [] (char c) -> bool { return !isdigit(c); } );
        std::string versionPart(i, nextIllegalChar);
        i = std::find_if(nextIllegalChar, version.end(), isdigit);

        int part = (boost::lexical_cast<int>(versionPart));
        versionAsNumber = versionAsNumber * 100 + part;
        nParts ++;
    }

    return {versionAsNumber, nParts};
}


/** Assume that the system version will not go beyond X.Y.Z.W format.
 * @return The version string.
 */
- (int) parseSystemVersionAlt {
    std::string version = [[[UIDevice currentDevice] systemVersion] UTF8String];
    int versionAsNumber = 0;
    int nParts = 0;

    auto i = version.begin();
    while (i != version.end() && nParts < 4) {
        auto nextIllegalChar = std::find_if(i, version.end(), [] (char c) -> bool { return !isdigit(c); } );
        std::string versionPart(i, nextIllegalChar);
        i = std::find_if(nextIllegalChar, version.end(), isdigit);

        int part = (boost::lexical_cast<int>(versionPart));
        versionAsNumber = versionAsNumber * 100 + part;
        nParts ++;
    }

    // don't forget to pad as systemVersion may have less parts (i.e. X.Y).
    for (; nParts < 4; nParts++) {
        versionAsNumber *= 100;
    }

    return versionAsNumber;
}