我想检查设备的iOS版本是否大于3.1.3 我尝试了以下方法:
[[UIDevice currentDevice].systemVersion floatValue]
但是不管用,我只想要一个:
if (version > 3.1.3) { }
我怎样才能做到这一点呢?
我想检查设备的iOS版本是否大于3.1.3 我尝试了以下方法:
[[UIDevice currentDevice].systemVersion floatValue]
但是不管用,我只想要一个:
if (version > 3.1.3) { }
我怎样才能做到这一点呢?
当前回答
在您的项目中添加以下Swift代码,并轻松访问iOS版本和设备等信息。
class DeviceInfo: NSObject {
struct ScreenSize
{
static let SCREEN_WIDTH = UIScreen.main.bounds.size.width
static let SCREEN_HEIGHT = UIScreen.main.bounds.size.height
static let SCREEN_MAX_LENGTH = max(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
static let SCREEN_MIN_LENGTH = min(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
}
struct DeviceType
{
static let IS_IPHONE_4_OR_LESS = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH < 568.0
static let IS_IPHONE_5 = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 568.0
static let IS_IPHONE_6 = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH >= 667.0
static let IS_IPHONE_6P = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 736.0
static let IS_IPHONE_X = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 812.0
static let IS_IPAD = UIDevice.current.userInterfaceIdiom == .pad && ScreenSize.SCREEN_MAX_LENGTH == 1024.0
static let IS_IPAD_PRO = UIDevice.current.userInterfaceIdiom == .pad && ScreenSize.SCREEN_MAX_LENGTH == 1366.0
}
struct VersionType{
static let SYS_VERSION_FLOAT = (UIDevice.current.systemVersion as NSString).floatValue
static let iOS7 = (VersionType.SYS_VERSION_FLOAT < 8.0 && VersionType.SYS_VERSION_FLOAT >= 7.0)
static let iOS8 = (VersionType.SYS_VERSION_FLOAT >= 8.0 && VersionType.SYS_VERSION_FLOAT < 9.0)
static let iOS9 = (VersionType.SYS_VERSION_FLOAT >= 9.0 && VersionType.SYS_VERSION_FLOAT < 10.0)
static let iOS10 = (VersionType.SYS_VERSION_FLOAT >= 9.0 && VersionType.SYS_VERSION_FLOAT < 11.0)
}
}
其他回答
作为yasimturks解决方案的一种变体,我定义了一个函数和一些枚举值,而不是五个宏。我觉得它更优雅,但那是个人品味的问题。
用法:
if (systemVersion(LessThan, @"5.0")) ...
. h文件:
typedef enum {
LessThan,
LessOrEqual,
Equal,
GreaterOrEqual,
GreaterThan,
NotEqual
} Comparison;
BOOL systemVersion(Comparison test, NSString* version);
m文件:
BOOL systemVersion(Comparison test, NSString* version) {
NSComparisonResult result = [[[UIDevice currentDevice] systemVersion] compare: version options: NSNumericSearch];
switch (test) {
case LessThan: return result == NSOrderedAscending;
case LessOrEqual: return result != NSOrderedDescending;
case Equal: return result == NSOrderedSame;
case GreaterOrEqual: return result != NSOrderedAscending;
case GreaterThan: return result == NSOrderedDescending;
case NotEqual: return result != NSOrderedSame;
}
}
你应该在名称中添加应用程序的前缀,尤其是比较类型。
根据苹果官方文档的建议:你可以使用nsobjcrtime .h头文件中的NSFoundationVersionNumber。
if (floor(NSFoundationVersionNumber) > NSFoundationVersionNumber_iOS_6_1) {
// here you go with iOS 7
}
UIDevice + IOSVersion.h
@interface UIDevice (IOSVersion)
+ (BOOL)isCurrentIOSVersionEqualToVersion:(NSString *)iOSVersion;
+ (BOOL)isCurrentIOSVersionGreaterThanVersion:(NSString *)iOSVersion;
+ (BOOL)isCurrentIOSVersionGreaterThanOrEqualToVersion:(NSString *)iOSVersion;
+ (BOOL)isCurrentIOSVersionLessThanVersion:(NSString *)iOSVersion;
+ (BOOL)isCurrentIOSVersionLessThanOrEqualToVersion:(NSString *)iOSVersion
@end
UIDevice + IOSVersion.m
#import "UIDevice+IOSVersion.h"
@implementation UIDevice (IOSVersion)
+ (BOOL)isCurrentIOSVersionEqualToVersion:(NSString *)iOSVersion
{
return [[[UIDevice currentDevice] systemVersion] compare:iOSVersion options:NSNumericSearch] == NSOrderedSame;
}
+ (BOOL)isCurrentIOSVersionGreaterThanVersion:(NSString *)iOSVersion
{
return [[[UIDevice currentDevice] systemVersion] compare:iOSVersion options:NSNumericSearch] == NSOrderedDescending;
}
+ (BOOL)isCurrentIOSVersionGreaterThanOrEqualToVersion:(NSString *)iOSVersion
{
return [[[UIDevice currentDevice] systemVersion] compare:iOSVersion options:NSNumericSearch] != NSOrderedAscending;
}
+ (BOOL)isCurrentIOSVersionLessThanVersion:(NSString *)iOSVersion
{
return [[[UIDevice currentDevice] systemVersion] compare:iOSVersion options:NSNumericSearch] == NSOrderedAscending;
}
+ (BOOL)isCurrentIOSVersionLessThanOrEqualToVersion:(NSString *)iOSVersion
{
return [[[UIDevice currentDevice] systemVersion] compare:iOSVersion options:NSNumericSearch] != NSOrderedDescending;
}
@end
试试这个
if ([[[UIDevice currentDevice] systemVersion] floatValue] >= 7) {
// do some work
}
这两种常见的答案存在一些问题:
Comparing strings using NSNumericSearch sometimes has unintuitive results (the SYSTEM_VERSION_* macros all suffer from this): [@"10.0" compare:@"10" options:NSNumericSearch] // returns NSOrderedDescending instead of NSOrderedSame FIX: Normalize your strings first and then perform the comparisons. could be annoying trying to get both strings in identical formats. Using the foundation framework version symbols is not possible when checking future releases NSFoundationVersionNumber_iOS_6_1 // does not exist in iOS 5 SDK FIX: Perform two separate tests to ensure the symbol exists AND THEN compare symbols. However another here: The foundation framwork versions symbols are not unique to iOS versions. Multiple iOS releases can have the same framework version. 9.2 & 9.3 are both 1242.12 8.3 & 8.4 are both 1144.17 FIX: I believe this issue is unresolvable
为了解决这些问题,下面的方法将版本号字符串处理为以10000为基数的数字(每个主要/次要/补丁组件都是一个单独的数字),并执行以十进制为基数的转换,以便使用整数运算符进行比较。
添加了另外两个方法,用于方便地比较iOS版本字符串,以及比较字符串与任意数量的组件。
+ (SInt64)integerFromVersionString:(NSString *)versionString withComponentCount:(NSUInteger)componentCount
{
//
// performs base conversion from a version string to a decimal value. the version string is interpreted as
// a base-10000 number, where each component is an individual digit. this makes it simple to use integer
// operations for comparing versions. for example (with componentCount = 4):
//
// version "5.9.22.1" = 5*1000^3 + 9*1000^2 + 22*1000^1 + 1*1000^0 = 5000900220001
// and
// version "6.0.0.0" = 6*1000^3 + 0*1000^2 + 0*1000^1 + 0*1000^1 = 6000000000000
// and
// version "6" = 6*1000^3 + 0*1000^2 + 0*1000^1 + 0*1000^1 = 6000000000000
//
// then the integer comparisons hold true as you would expect:
//
// "5.9.22.1" < "6.0.0.0" // true
// "6.0.0.0" == "6" // true
//
static NSCharacterSet *nonDecimalDigitCharacter;
static dispatch_once_t onceToken;
dispatch_once(&onceToken,
^{ // don't allocate this charset every time the function is called
nonDecimalDigitCharacter = [[NSCharacterSet decimalDigitCharacterSet] invertedSet];
});
SInt64 base = 10000; // each component in the version string must be less than base
SInt64 result = 0;
SInt64 power = 0;
// construct the decimal value left-to-right from the version string
for (NSString *component in [versionString componentsSeparatedByString:@"."])
{
if (NSNotFound != [component rangeOfCharacterFromSet:nonDecimalDigitCharacter].location)
{
// one of the version components is not an integer, so bail out
result = -1;
break;
}
result += [component longLongValue] * (long long)pow((double)base, (double)(componentCount - ++power));
}
return result;
}
+ (SInt64)integerFromVersionString:(NSString *)versionString
{
return [[self class] integerFromVersionString:versionString
withComponentCount:[[versionString componentsSeparatedByString:@"."] count]];
}
+ (SInt64)integerFromiOSVersionString:(NSString *)versionString
{
// iOS uses 3-component version string
return [[self class] integerFromVersionString:versionString
withComponentCount:3];
}
它支持许多版本标识符(通过4位数字,0-9999;可以支持任意数量的组件(Apple目前似乎使用3个组件,例如major.minor.patch),但这可以使用componentCount参数显式指定。确保你的componentCount和base不会导致溢出,即确保2^63 >= base^componentCount!
使用的例子:
NSString *currentVersion = [[UIDevice currentDevice] systemVersion];
if ([Util integerFromiOSVersionString:currentVersion] >= [Util integerFromiOSVersionString:@"42"])
{
NSLog(@"we are in some horrible distant future where iOS still exists");
}