我还在试着接受这件事。

我可以让用户选择文件(甚至多个)与文件输入:

<form>
  <div>
    <label>Select file to upload</label>
    <input type="file">
  </div>
  <button type="submit">Convert</button>
</form>

我可以用<填充事件处理程序>来捕获提交事件。但是一旦我这样做了,我如何使用fetch发送文件?

fetch('/files', {
  method: 'post',
  // what goes here? What is the "body" for this? content-type header?
}).then(/* whatever */);

当前回答

从Alex Montoya的多文件输入元素方法出发

const inputFiles = document.querySelectorAll('input[type="file"]');
const formData = new FormData();

for (const file of inputFiles) {
    formData.append(file.name, file.files[0]);
}

fetch(url, {
    method: 'POST',
    body: formData })

其他回答

这里公认的答案有点过时了。截至2020年4月,MDN网站上的推荐方法建议使用FormData,也不要求设置内容类型。https://developer.mozilla.org/en-US/docs/Web/API/Fetch_API/Using_Fetch

为了方便起见,我引用了代码片段:

const formData = new FormData();
const fileField = document.querySelector('input[type="file"]');

formData.append('username', 'abc123');
formData.append('avatar', fileField.files[0]);

fetch('https://example.com/profile/avatar', {
  method: 'PUT',
  body: formData
})
.then((response) => response.json())
.then((result) => {
  console.log('Success:', result);
})
.catch((error) => {
  console.error('Error:', error);
});

使用Fetch API发送文件的一个重要注意事项

我们需要忽略Fetch请求的内容类型头。然后浏览器会自动添加内容类型头,包括表单边界,看起来像

Content-Type: multipart/form-data; boundary=—-WebKitFormBoundaryfgtsKTYLsT7PNUVD

表单边界是表单数据的分隔符

这是一个带有注释的基本示例。上传功能就是你要找的:

// Select your input type file and store it in a variable
const input = document.getElementById('fileinput');

// This will upload the file after having read it
const upload = (file) => {
  fetch('http://www.example.net', { // Your POST endpoint
    method: 'POST',
    headers: {
      // Content-Type may need to be completely **omitted**
      // or you may need something
      "Content-Type": "You will perhaps need to define a content-type here"
    },
    body: file // This is your file object
  }).then(
    response => response.json() // if the response is a JSON object
  ).then(
    success => console.log(success) // Handle the success response object
  ).catch(
    error => console.log(error) // Handle the error response object
  );
};

// Event handler executed when a file is selected
const onSelectFile = () => upload(input.files[0]);

// Add a listener on your input
// It will be triggered when a file will be selected
input.addEventListener('change', onSelectFile, false);

如何上传一个文件选择使用HTML5获取

<label role="button">
  Upload a picture
  <input accept="image/*" type="file" hidden />
</label>
const input = document.querySelector(`input[type="file"]`);

function upload() {
  fetch(uplaodURL, { method: "PUT", body: input.files[0] });
}

input.addEventListener("change", upload); 

这是我的代码:

html:

const upload = (file) => { console.log(file); fetch('http://localhost:8080/files/uploadFile', { method: 'POST', // headers: { // //"Content-Disposition": "attachment; name='file'; filename='xml2.txt'", // "Content-Type": "multipart/form-data; boundary=BbC04y " //"multipart/mixed;boundary=gc0p4Jq0M2Yt08jU534c0p" // ή // multipart/form-data // }, body: file // This is your file object }).then( response => response.json() // if the response is a JSON object ).then( success => console.log(success) // Handle the success response object ).catch( error => console.log(error) // Handle the error response object ); //cvForm.submit(); }; const onSelectFile = () => upload(uploadCvInput.files[0]); uploadCvInput.addEventListener('change', onSelectFile, false); <form id="cv_form" style="display: none;" enctype="multipart/form-data"> <input id="uploadCV" type="file" name="file"/> <button type="submit" id="upload_btn">upload</button> </form> <ul class="dropdown-menu"> <li class="nav-item"><a class="nav-link" href="#" id="upload">UPLOAD CV</a></li> <li class="nav-item"><a class="nav-link" href="#" id="download">DOWNLOAD CV</a></li> </ul>