斯威夫特 您可以使用以下功能打开蓝牙页面设置App

func openSettingsApp(){
    if let settings = NSURL(string: "prefs:root=Bluetooth") {
        UIApplication.sharedApplication().openURL(settings)
    }
}

同样，这不会打开应用程序的设置。这将打开蓝牙设置应用程序，因为这是深度链接到蓝牙。

你可以在iOS 5.0及更高版本上使用这个:这个不再有效。

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"prefs://"]];

在iOS 10上测试。工作

NSArray* urlStrings = @[@"prefs:root=WIFI", @"App-Prefs:root=WIFI"];
for(NSString* urlString in urlStrings){
NSURL* url = [NSURL URLWithString:urlString];
if([[UIApplication sharedApplication] canOpenURL:url]){
    [[UIApplication sharedApplication] openURL:url];
    break;
}
}

快乐编码:)

斯威夫特4.0

'openURL'在iOS 10.0中已弃用:请使用 openURL:选项:completionHandler:不是

UIApplication.shared.open(URL.init(string: UIApplicationOpenSettingsURLString)! , options: [:], completionHandler: nil)

把这个加到你的课上，

 public class func showSettingsAlert(title:String,message:String,onVC viewController:UIViewController,onCancel:(()->())?){
            YourClass.show2ButtonsAlert(onVC: viewController, title: title, message: message, button1Title: "Settings", button2Title: "Cancel", onButton1Click: {
                if let settingsURL = NSURL(string: UIApplicationOpenSettingsURLString){
                    UIApplication.sharedApplication().openURL(settingsURL)
                }
                }, onButton2Click: {
                    onCancel?()
            })
        }

 public class func show2ButtonsAlert(onVC viewController:UIViewController,title:String,message:String,button1Title:String,button2Title:String,onButton1Click:(()->())?,onButton2Click:(()->())?){
            dispatch_async(dispatch_get_main_queue()) {
                let alert : UIAlertController = UIAlertController(title: title, message: message, preferredStyle: UIAlertControllerStyle.Alert)

                alert.addAction(UIAlertAction(title: button1Title, style:.Default, handler: { (action:UIAlertAction) in
                    onButton1Click?()
                }))

                alert.addAction(UIAlertAction(title: button2Title, style:.Default, handler: { (action:UIAlertAction) in
                    onButton2Click?()
                }))

                viewController.presentViewController(alert, animated: true, completion: nil)
            }
        }

像这样调用，

YourClass.showSettingsAlert("App would like to access camera", message: "App would like to access camera desc", onVC: fromViewController, onCancel: {
  print("canceled")
})

斯威夫特3:

guard let url = URL(string: UIApplicationOpenSettingsURLString) else {return}
if #available(iOS 10.0, *) {
  UIApplication.shared.open(url, options: [:], completionHandler: nil)
} else {
  // Fallback on earlier versions
  UIApplication.shared.openURL(url)
}