dropdown1 = Select(driver.find_element_by_name("fruits"))
dropdown1.select_by_visible_text('banana')

列表项

公共类ListBoxMultiple {

public static void main(String[] args) throws InterruptedException {
    // TODO Auto-generated method stub
    System.setProperty("webdriver.chrome.driver", "./drivers/chromedriver.exe");
    WebDriver driver=new ChromeDriver();
    driver.get("file:///C:/Users/Amitabh/Desktop/hotel2.html");//open the website
    driver.manage().window().maximize();


    WebElement hotel = driver.findElement(By.id("maarya"));//get the element

    Select sel=new Select(hotel);//for handling list box
    //isMultiple
    if(sel.isMultiple()){
        System.out.println("it is multi select list");
    }
    else{
        System.out.println("it is single select list");
    }
    //select option
    sel.selectByIndex(1);// you can select by index values
    sel.selectByValue("p");//you can select by value
    sel.selectByVisibleText("Fish");// you can also select by visible text of the options
    //deselect option but this is possible only in case of multiple lists
    Thread.sleep(1000);
    sel.deselectByIndex(1);
    sel.deselectAll();

    //getOptions
    List<WebElement> options = sel.getOptions();

    int count=options.size();
    System.out.println("Total options: "+count);

    for(WebElement opt:options){ // getting text of every elements
        String text=opt.getText();
        System.out.println(text);
        }

    //select all options
    for(int i=0;i<count;i++){
        sel.selectByIndex(i);
        Thread.sleep(1000);
    }

    driver.quit();

}

}

我尝试了很多东西，但是我的下拉是在一个表中，我不能执行简单的选择操作。只有下面的解决方案有效。在这里，我突出显示下拉elem和按下箭头，直到得到所需的值-

        #identify the drop down element
        elem = browser.find_element_by_name(objectVal)
        for option in elem.find_elements_by_tag_name('option'):
            if option.text == value:
                break

            else:
                ARROW_DOWN = u'\ue015'
                elem.send_keys(ARROW_DOWN)

在看了很多类似这篇文章之后，我设法想出了一个解决方案，让我可以在下拉列表中选择一个项目。我尝试了.send_keys，单击()和选择在各种方式没有成功。最后，在单击下拉列表中的项目之前，向下拉列表发送了3次click()命令。

dropMenu = browser.find_element_by_id('cmbDeviceType')
dropMenu.click()
dropMenu.click()
dropMenu.click()

deviceType = browser.find_element_by_id('cmbDeviceType_DDD_L_LBI16T0')
deviceType.click()

绝对不是很漂亮，但是很好用。

希望这能帮助到一些人。这是在Firefox 88.0.1上使用Python3.7.7完成的。

你可以很好地使用css选择器组合

driver.find_element_by_css_selector("#fruits01 [value='1']").click()

将attribute = value css选择器中的1更改为所需水果对应的值。

根据提供的HTML:

<select id="fruits01" class="select" name="fruits">
  <option value="0">Choose your fruits:</option>
  <option value="1">Banana</option>
  <option value="2">Mango</option>
</select>

要从html-select菜单中选择<option>元素，必须使用select类。此外，当你必须与下拉菜单交互时，你必须为element_to_be_clickable()诱导WebDriverWait。

要从下拉菜单中选择<选项>，文本为Mango，你可以使用以下定位器策略之一:

Using ID attribute and select_by_visible_text() method: from selenium import webdriver from selenium.webdriver.support.ui import WebDriverWait from selenium.webdriver.common.by import By from selenium.webdriver.support import expected_conditions as EC from selenium.webdriver.support.ui import Select select = Select(WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.ID, "fruits01")))) select.select_by_visible_text("Mango") Using CSS-SELECTOR and select_by_value() method: select = Select(WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "select.select[name='fruits']")))) select.select_by_value("2") Using XPATH and select_by_index() method: select = Select(WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "//select[@class='select' and @name='fruits']")))) select.select_by_index(2)