我试图找到一个MySQL查询，将在特定字段中找到DISTINCT值，计数该值的出现次数，然后按计数顺序排列结果。
示例数据库
id name
----- ------
1 Mark
2 Mike
3 Paul
4 Mike
5 Mike
6 John
7 Mark
预期的结果
name count
----- -----
Mike 3
Mark 2
Paul 1
John 1
当前回答
SELECT name,COUNT(*) as count
FROM tablename
GROUP BY name
ORDER BY count DESC;
其他回答
SELECT name,COUNT(*) as count
FROM tablename
GROUP BY name
ORDER BY count DESC;
像这样的东西怎么样:
SELECT
name,
count(*) AS num
FROM
your_table
GROUP BY
name
ORDER BY
count(*)
DESC
您选择名称和它出现的次数，但按名称分组，因此每个名称只选择一次。
最后，按降序排列次数，让最频繁出现的用户排在前面。
刚刚将Amber的COUNT(*)更改为COUNT(1)以获得更好的性能。
SELECT name, COUNT(1) as count
FROM tablename
GROUP BY name
ORDER BY count DESC;
$sql ="SELECT DISTINCT column_name FROM table_NAME";
$res = mysqli_query($connection_variable,$sql);
while($row = mysqli_fetch_assoc($res))
{
$sqlgetnum = "select count(*) as count from table_NAME where column_name= '$row[column_name]'";
}
对我来说工作很顺利
Group by给出了所有不同的值
