如何检查是否存在文件,而不使用试用声明?


当前回答

你可以写布莱恩的建议,没有尝试:

from contextlib import suppress

with suppress(IOError), open('filename'):
    process()

suppress 是 Python 3.4 的组成部分。在旧版本中,您可以快速写下自己的 suppress:

from contextlib import contextmanager

@contextmanager
def suppress(*exceptions):
    try:
        yield
    except exceptions:
        pass

其他回答

如果你正在检查的原因是,所以你可以做一些类似的文件_存在: open_it(),它更安全地使用一个尝试周围试图打开它。

如果您不打算立即打开文件,您可以使用 os.path.isfile。

如果路径是现有常规文件,则返回是真实的,这跟随了象征性链接,因此 islink() 和 isfile() 都可以对同一条路径是真实的。

import os.path
os.path.isfile(fname) 

如果你需要确保它是一个文件。

从 Python 3.4 开始,Pathlib 模块提供一个以对象为导向的方法(在 Python 2.7 中返回Pathlib2):

from pathlib import Path

my_file = Path("/path/to/file")
if my_file.is_file():
    # file exists

要查看一个目录,请:

if my_file.is_dir():
    # directory exists

要检查路径对象是否存在,无论它是否是一个文件或目录,使用存在():

if my_file.exists():
    # path exists

您也可以在尝试区块中使用 resolve(strict=True):

try:
    my_abs_path = my_file.resolve(strict=True)
except FileNotFoundError:
    # doesn't exist
else:
    # exists
import os.path

def isReadableFile(file_path, file_name):
    full_path = file_path + "/" + file_name
    try:
        if not os.path.exists(file_path):
            print "File path is invalid."
            return False
        elif not os.path.isfile(full_path):
            print "File does not exist."
            return False
        elif not os.access(full_path, os.R_OK):
            print "File cannot be read."
            return False
        else:
            print "File can be read."
            return True
    except IOError as ex:
        print "I/O error({0}): {1}".format(ex.errno, ex.strerror)
    except Error as ex:
        print "Error({0}): {1}".format(ex.errno, ex.strerror)
    return False
#------------------------------------------------------

path = "/usr/khaled/documents/puzzles"
fileName = "puzzle_1.txt"

isReadableFile(path, fileName)

这就是我如何在一个文件夹中找到一个文件列表(在这些图像中)并在一个文件夹中搜索它(与子文件夹):

# This script concatenates JavaScript files into a unified JavaScript file to reduce server round-trips

import os
import string
import math
import ntpath
import sys

#import pyodbc

import gzip
import shutil

import hashlib

# BUF_SIZE is totally arbitrary, change for your app!
BUF_SIZE = 65536  # Let’s read stuff in 64 kilobyte chunks

# Iterate over all JavaScript files in the folder and combine them
filenames = []
shortfilenames = []

imgfilenames = []
imgshortfilenames = []

# Get a unified path so we can stop dancing with user paths.
# Determine where files are on this machine (%TEMP% directory and application installation directory)
if '.exe' in sys.argv[0]: # if getattr(sys, 'frozen', False):
    RootPath = os.path.abspath(os.path.join(__file__, "..\\"))

elif __file__:
    RootPath = os.path.abspath(os.path.join(__file__, "..\\"))

print ("\n storage of image files RootPath: %s\n" %RootPath)

FolderPath = "D:\\TFS-FARM1\\StoneSoup_STS\\SDLC\\Build\\Code\\StoneSoup_Refactor\\StoneSoupUI\\Images"
print ("\n storage of image files in folder to search: %s\n" %FolderPath)

for root, directories, filenames2 in os.walk(FolderPath):
    for filename in filenames2:
        fullname = os.path.join(root, filename)
        filenames.append(fullname)
        shortfilenames.append(filename)

for i, fname in enumerate(shortfilenames):
        print("%s - %s" % (i+1, fname))

for root, directories, filenames2 in os.walk(RootPath):
    for filename in filenames2:
        fullname = os.path.join(root, filename)
        imgfilenames.append(fullname)
        imgshortfilenames.append(filename)

for i, fname in enumerate(imgshortfilenames):
        print("%s - %s" % (i+1, fname))

for i, fname in enumerate(imgshortfilenames):
        if fname in shortfilenames:
            print("%s - %s exists" % (i+1, fname))
        else:
            print("%s - %s ABSENT" % (i+1, fname))

它被认为是更好的风格,避免赛车条件。

不要用我的话来支持这个理论,这里有几个:

风格:本课程的“处理异常条件”部分为软件设计(2007) 避免竞赛条件

你可以写布莱恩的建议,没有尝试:

from contextlib import suppress

with suppress(IOError), open('filename'):
    process()

suppress 是 Python 3.4 的组成部分。在旧版本中,您可以快速写下自己的 suppress:

from contextlib import contextmanager

@contextmanager
def suppress(*exceptions):
    try:
        yield
    except exceptions:
        pass