我如何在另一个JavaScript文件中添加一个JavaScript文件,类似于CSS中的 @import?
当前回答
不要忘了查看LAB.js!
<script type="text/javascript">
$LAB.script("jquery-1.8.3.js").wait().script("scripts/clientscript.js");
</script>
其他回答
我只是写了这个JavaScript代码(使用DOM操作的Prototype):
var require = (function() {
var _required = {};
return (function(url, callback) {
if (typeof url == 'object') {
// We've (hopefully) got an array: time to chain!
if (url.length > 1) {
// Load the nth file as soon as everything up to the
// n-1th one is done.
require(url.slice(0, url.length - 1), function() {
require(url[url.length - 1], callback);
});
} else if (url.length == 1) {
require(url[0], callback);
}
return;
}
if (typeof _required[url] == 'undefined') {
// Haven't loaded this URL yet; gogogo!
_required[url] = [];
var script = new Element('script', {
src: url,
type: 'text/javascript'
});
script.observe('load', function() {
console.log("script " + url + " loaded.");
_required[url].each(function(cb) {
cb.call(); // TODO: does this execute in the right context?
});
_required[url] = true;
});
$$('head')[0].insert(script);
} else if (typeof _required[url] == 'boolean') {
// We already loaded the thing, so go ahead.
if (callback) {
callback.call();
}
return;
}
if (callback) {
_required[url].push(callback);
}
});
})();
使用:
<script src="prototype.js"></script>
<script src="require.js"></script>
<script>
require(['foo.js','bar.js'], function () {
/* Use foo.js and bar.js here */
});
</script>
地址: http://gist.github.com/284442.
与 $.getScript 和实际上任何其他解决方案需要一个呼叫回复,当加载完成时的问题是,如果你有多个文件使用它,并依赖对方,你已经没有办法知道什么时候所有的脚本被加载(一旦它们被纳入多个文件)。
文件3JS
var f3obj = "file3";
// Define other stuff
文件2JS:
var f2obj = "file2";
$.getScript("file3.js", function(){
alert(f3obj);
// Use anything defined in file3.
});
此分類上一篇: JS
$.getScript("file2.js", function(){
alert(f3obj); //This will probably fail because file3 is only guaranteed to have loaded inside the callback in file2.
alert(f2obj);
// Use anything defined in the loaded script...
});
您可以尝试使用 $.when 检查一系列丢失的对象,但现在您正在做这一点在每个文件和文件2 将被视为加载,一旦 $.when 执行,而不是当呼叫回复执行,所以文件1 仍然继续执行之前文件3 被加载,这真的仍然有相同的问题。
我喜欢延长jQuery的想法,但显然你不需要。
在呼叫document.writeln之前,它检查以确保脚本已经没有被加载,通过评估所有脚本元素。
而不是这个方法,你可以尝试修改 jQuery readyList,但这似乎是一个更糟糕的解决方案。
解决方案:
$.extend(true,
{
import_js : function(scriptpath, reAddLast)
{
if (typeof reAddLast === "undefined" || reAddLast === null)
{
reAddLast = true; // Default this value to true. It is not used by the end user, only to facilitate recursion correctly.
}
var found = false;
if (reAddLast == true) // If we are re-adding the originating script we do not care if it has already been added.
{
found = $('script').filter(function () {
return ($(this).attr('src') == scriptpath);
}).length != 0; // jQuery to check if the script already exists. (replace it with straight JavaScript if you don't like jQuery.
}
if (found == false) {
var callingScriptPath = $('script').last().attr("src"); // Get the script that is currently loading. Again this creates a limitation where this should not be used in a button, and only before document.ready.
document.writeln("<script type='text/javascript' src='" + scriptpath + "'></script>"); // Add the script to the document using writeln
if (reAddLast)
{
$.import_js(callingScriptPath, false); // Call itself with the originating script to fix the order.
throw 'Readding script to correct order: ' + scriptpath + ' < ' + callingScriptPath; // This halts execution of the originating script since it is getting reloaded. If you put a try / catch around the call to $.import_js you results will vary.
}
return true;
}
return false;
}
});
使用:
var f3obj = "file3";
// Define other stuff
$(function(){
f3obj = "file3docready";
});
文件2:
$.import_js('js/file3.js');
var f2obj = "file2";
$(function(){
f2obj = "file2docready";
});
文件1:
$.import_js('js/file2.js');
// Use objects from file2 or file3
alert(f3obj); // "file3"
alert(f2obj); // "file2"
$(function(){
// Use objects from file2 or file3 some more.
alert(f3obj); //"file3docready"
alert(f2obj); //"file2docready"
});
另一种方式,在我看来是更清洁的,是做一个同步的Ajax请求而不是使用一个<script>标签。
下面是使用 jQuery 的例子:
function require(script) {
$.ajax({
url: script,
dataType: "script",
async: false, // <-- This is the key
success: function () {
// all good...
},
error: function () {
throw new Error("Could not load script " + script);
}
});
}
然后你可以在你的代码中使用它,因为你通常会使用一个包括:
require("/scripts/subscript.js");
并能够在下列行中从所需脚本中呼叫一个函数:
subscript.doSomethingCool();
输入声明在 ECMAScript 6 中。
合成
import name from "module-name";
import { member } from "module-name";
import { member as alias } from "module-name";
import { member1 , member2 } from "module-name";
import { member1 , member2 as alias2 , [...] } from "module-name";
import name , { member [ , [...] ] } from "module-name";
import "module-name" as name;
var js = document.createElement("script");
js.type = "text/javascript";
js.src = jsFilePath;
document.body.appendChild(js);