我知道这个问题已经得到了很好的回答，但这里有一个“$@”$@“$*”和$*之间的比较

测试脚本内容:

# cat ./test.sh
#!/usr/bin/env bash
echo "================================="

echo "Quoted DOLLAR-AT"
for ARG in "$@"; do
    echo $ARG
done

echo "================================="

echo "NOT Quoted DOLLAR-AT"
for ARG in $@; do
    echo $ARG
done

echo "================================="

echo "Quoted DOLLAR-STAR"
for ARG in "$*"; do
    echo $ARG
done

echo "================================="

echo "NOT Quoted DOLLAR-STAR"
for ARG in $*; do
    echo $ARG
done

echo "================================="

现在，运行带有各种参数的测试脚本:

# ./test.sh  "arg with space one" "arg2" arg3
=================================
Quoted DOLLAR-AT
arg with space one
arg2
arg3
=================================
NOT Quoted DOLLAR-AT
arg
with
space
one
arg2
arg3
=================================
Quoted DOLLAR-STAR
arg with space one arg2 arg3
=================================
NOT Quoted DOLLAR-STAR
arg
with
space
one
arg2
arg3
=================================

我知道这个问题已经得到了很好的回答，但这里有一个“$@”$@“$*”和$*之间的比较

测试脚本内容:

# cat ./test.sh
#!/usr/bin/env bash
echo "================================="

echo "Quoted DOLLAR-AT"
for ARG in "$@"; do
    echo $ARG
done

echo "================================="

echo "NOT Quoted DOLLAR-AT"
for ARG in $@; do
    echo $ARG
done

echo "================================="

echo "Quoted DOLLAR-STAR"
for ARG in "$*"; do
    echo $ARG
done

echo "================================="

echo "NOT Quoted DOLLAR-STAR"
for ARG in $*; do
    echo $ARG
done

echo "================================="

现在，运行带有各种参数的测试脚本:

# ./test.sh  "arg with space one" "arg2" arg3
=================================
Quoted DOLLAR-AT
arg with space one
arg2
arg3
=================================
NOT Quoted DOLLAR-AT
arg
with
space
one
arg2
arg3
=================================
Quoted DOLLAR-STAR
arg with space one arg2 arg3
=================================
NOT Quoted DOLLAR-STAR
arg
with
space
one
arg2
arg3
=================================

这里有很多答案推荐带引号或不带引号的$@或$*，但似乎没有人解释这些参数的真正作用以及为什么你应该这样做。所以让我从这个答案中偷取一个很好的总结:

+--------+---------------------------+
| Syntax |      Effective result     |
+--------+---------------------------+
|   $*   |     $1 $2 $3 ... ${N}     |
+--------+---------------------------+
|   $@   |     $1 $2 $3 ... ${N}     |
+--------+---------------------------+
|  "$*"  |    "$1c$2c$3c...c${N}"    |
+--------+---------------------------+
|  "$@"  | "$1" "$2" "$3" ... "${N}" |
+--------+---------------------------+

请注意，引号会造成所有的不同，如果没有引号，两者的行为是相同的。

出于我的目的，我需要将参数从一个脚本传递到另一个脚本，为此最好的选择是:

# file: parent.sh
# we have some params passed to parent.sh 
# which we will like to pass on to child.sh as-is

./child.sh $*

注意，在上述情况下，没有引号和$@也可以工作。

#!/usr/bin/env bash
while [ "$1" != "" ]; do
  echo "Received: ${1}" && shift;
done;

只是认为在尝试测试args如何进入脚本时，这可能更有用

如果你确实希望传递相同的参数，请使用“$@”而不是普通的$@。

观察:

$ cat no_quotes.sh
#!/bin/bash
echo_args.sh $@

$ cat quotes.sh
#!/bin/bash
echo_args.sh "$@"

$ cat echo_args.sh
#!/bin/bash
echo Received: $1
echo Received: $2
echo Received: $3
echo Received: $4

$ ./no_quotes.sh first second
Received: first
Received: second
Received:
Received:

$ ./no_quotes.sh "one quoted arg"
Received: one
Received: quoted
Received: arg
Received:

$ ./quotes.sh first second
Received: first
Received: second
Received:
Received:

$ ./quotes.sh "one quoted arg"
Received: one quoted arg
Received:
Received:
Received:

使用“$@”(适用于所有POSIX兼容程序)。

[…)， bash提供了“$@”变量，它扩展为所有用空格分隔的命令行参数。

以Bash为例。