代码不运行/我的PHP代码的某些部分被输出

如果你的PHP代码没有任何结果，或者你在网页中看到你的PHP源代码输出的部分文字，你可以很确定你的PHP实际上没有被执行。如果在浏览器中使用“查看源代码”，则可能会看到完整的PHP源代码文件。因为PHP代码嵌入在<?php ?>标记时，浏览器将尝试将它们解释为HTML标记，结果可能看起来有些混乱。

要真正运行PHP脚本，您需要:

执行脚本的web服务器 将文件扩展名设置为.php，否则web服务器不会将其解释为* 通过web服务器访问你的。php文件

*除非你重新配置，否则一切都可以配置。

最后一点尤其重要。只需双击该文件，就可以在浏览器中使用如下地址打开它:

file://C:/path/to/my/file.php

这完全绕过了您可能正在运行的任何web服务器，并且文件没有得到解释。你需要在你的web服务器上访问文件的URL，可能是这样的:

http://localhost/my/file.php

您可能还想检查是否使用了短的打开标记<?而不是<?php和您的php配置已关闭短打开标记。

还可以看到PHP代码没有被执行，而是代码显示在页面上

致命错误:当不在对象上下文时使用$this

$是PHP中的一个特殊变量，不能被赋值。如果在不存在该对象的上下文中访问该对象，则给出此致命错误。

此错误可能发生:

If a non-static method is called statically. Example: class Foo { protected $var; public function __construct($var) { $this->var = $var; } public static function bar () { // ^^^^^^ echo $this->var; // ^^^^^ } } Foo::bar(); How to fix: review your code again, $this can only be used in an object context, and should never be used in a static method. Also, a static method should not access the non-static property. Use self::$static_property to access the static property. If code from a class method has been copied over into a normal function or just the global scope and keeping the $this special variable. How to fix: Review the code and replace $this with a different substitution variable.

相关问题:

致命错误:当不在对象上下文中时使用$this 致命错误:当不在对象上下文中时使用$this 所有“使用$this时不在对象上下文”的问题在Stackoverflow

致命错误:调用成员函数…在一个非物体上

发生在类似于xyz->method()的代码中，其中xyz不是对象，因此不能调用该方法。

这是一个致命错误，将停止脚本(向前兼容性注意:它将从PHP 7开始成为一个可捕获的错误)。

大多数情况下，这表明代码缺少对错误条件的检查。在调用一个对象的方法之前，验证它确实是一个对象。

一个典型的例子是

// ... some code using PDO
$statement = $pdo->prepare('invalid query', ...);
$statement->execute(...);

在上面的例子中，查询不能被准备，并且prepare()会将false赋值给$statement。尝试调用execute()方法将导致致命错误，因为false是一个“非对象”，因为该值是一个布尔值。

弄清楚为什么函数返回一个布尔值而不是一个对象。例如，检查$pdo对象中最近发生的错误。关于如何调试的细节将取决于如何处理特定函数/对象/类的错误。

如果->准备失败，那么你的$pdo数据库句柄对象没有被传递到当前作用域。找到它被定义的地方。然后将其作为参数传递，将其作为属性存储，或通过全局作用域共享。

另一个问题可能是有条件地创建一个对象，然后尝试在该条件块之外调用一个方法。例如

if ($someCondition) {
    $myObj = new MyObj();
}
// ...
$myObj->someMethod();

如果试图在条件块之外执行方法，则可能无法定义对象。

相关问题:

调用非对象上的成员函数 列出所有PHP“致命错误:调用成员函数…”关于Stackoverflow的问题

警告:open_basedir限制生效

此警告可以与与文件和目录访问相关的各种函数一起出现。它警告一个配置问题。

当它出现时，这意味着已禁止访问某些文件。

警告本身不会破坏任何东西，但如果文件访问被阻止，脚本通常无法正常工作。

修复方法通常是更改PHP配置，相关设置称为open_basedir。

有时使用了错误的文件或目录名称，解决方法是使用正确的名称。

相关问题:

Open_basedir限制生效。文件(/)不在允许路径内: 所有PHP的“警告:open_basedir限制在有效”的查询在Stackoverflow

注意:未定义变量

在尝试使用以前未定义的变量时发生。

一个典型的例子是

foreach ($items as $item) {
    // do something with item
    $counter++;
}

如果您之前没有定义$counter，上面的代码将触发通知。

正确的方法是在使用变量之前设置它

$counter = 0;
foreach ($items as $item) {
    // do something with item
    $counter++;
}

类似地，变量在其作用域之外是不可访问的，例如在使用匿名函数时。

$prefix = "Blueberry";
$food = ["cake", "cheese", "pie"];
$prefixedFood = array_map(function ($food) {
  // Prefix is undefined
  return "${prefix} ${food}";
}, $food);

这应该使用use来传递

$prefix = "Blueberry";
$food = ["cake", "cheese", "pie"];
$prefixedFood = array_map(function ($food) use ($prefix) {
  return "${prefix} ${food}";
}, $food);

注意:未定义的属性

此错误的含义大致相同，但指的是对象的属性。重用上面的示例，这段代码将触发错误，因为没有设置counter属性。

$obj = new stdclass;
$obj->property = 2342;
foreach ($items as $item) {
    // do something with item
    $obj->counter++;
}

相关问题:

所有关于Stackoverflow的PHP“注意:未定义变量”问题 “注意:未定义的变量”，“注意:未定义的索引”，“注意:未定义的偏移量”使用PHP 参考:什么是变量作用域，哪些变量可以从哪里访问，什么是“未定义变量”错误?

mysql_connect(): user 'name'@'host'拒绝访问

当您连接到无效或缺少凭据(用户名/密码)的MySQL/MariaDB服务器时，会出现此警告。所以这通常不是代码问题，而是服务器配置问题。

See the manual page on mysql_connect("localhost", "user", "pw") for examples. Check that you actually used a $username and $password. It's uncommon that you gain access using no password - which is what happened when the Warning: said (using password: NO). Only the local test server usually allows to connect with username root, no password, and the test database name. You can test if they're really correct using the command line client: mysql --user="username" --password="password" testdb Username and password are case-sensitive and whitespace is not ignored. If your password contains meta characters like $, escape them, or put the password in single quotes. Most shared hosting providers predeclare mysql accounts in relation to the unix user account (sometimes just prefixes or extra numeric suffixes). See the docs for a pattern or documentation, and CPanel or whatever interface for setting a password. See the MySQL manual on Adding user accounts using the command line. When connected as admin user you can issue a query like: CREATE USER 'username'@'localhost' IDENTIFIED BY 'newpassword'; Or use Adminer or WorkBench or any other graphical tool to create, check or correct account details. If you can't fix your credentials, then asking the internet to "please help" will have no effect. Only you and your hosting provider have permissions and sufficient access to diagnose and fix things. Verify that you could reach the database server, using the host name given by your provider: ping dbserver.hoster.example.net Check this from a SSH console directly on your webserver. Testing from your local development client to your shared hosting server is rarely meaningful. Often you just want the server name to be "localhost", which normally utilizes a local named socket when available. Othertimes you can try "127.0.0.1" as fallback. Should your MySQL/MariaDB server listen on a different port, then use "servername:3306". If that fails, then there's a perhaps a firewall issue. (Off-topic, not a programming question. No remote guess-helping possible.) When using constants like e.g. DB_USER or DB_PASSWORD, check that they're actually defined. If you get a "Warning: Access defined for 'DB_USER'@'host'" and a "Notice: use of undefined constant 'DB_PASS'", then that's your problem. Verify that your e.g. xy/db-config.php was actually included and whatelse. Check for correctly set GRANT permissions. It's not sufficient to have a username+password pair. Each MySQL/MariaDB account can have an attached set of permissions. Those can restrict which databases you are allowed to connect to, from which client/server the connection may originate from, and which queries are permitted. The "Access denied" warning thus may as well show up for mysql_query calls, if you don't have permissions to SELECT from a specific table, or INSERT/UPDATE, and more commonly DELETE anything. You can adapt account permissions when connected per command line client using the admin account with a query like: GRANT ALL ON yourdb.* TO 'username'@'localhost'; If the warning shows up first with Warning: mysql_query(): Access denied for user ''@'localhost' then you may have a php.ini-preconfigured account/password pair. Check that mysql.default_user= and mysql.default_password= have meaningful values. Oftentimes this is a provider-configuration. So contact their support for mismatches. Find the documentation of your shared hosting provider: e.g. HostGator, GoDaddy, 1and1, DigitalOcean, BlueHost, DreamHost, MediaTemple, ixWebhosting, lunarhosting, or just google yours´. Else consult your webhosting provider through their support channels. Note that you may also have depleted the available connection pool. You'll get access denied warnings for too many concurrent connections. (You have to investigate the setup. That's an off-topic server configuration issue, not a programming question.) Your libmysql client version may not be compatible with the database server. Normally MySQL and MariaDB servers can be reached with PHPs compiled in driver. If you have a custom setup, or an outdated PHP version, and a much newer database server, or significantly outdated one - then the version mismatch may prevent connections. (No, you have to investigate yourself. Nobody can guess your setup).

更多的引用:

mysql服务器错误:mysql用户无法访问root用户 mysql_connect():拒绝访问 mysql_select_db()拒绝访问用户" @'localhost'(使用密码:NO) PHPMyAdmin拒绝用户“root”@“localhost”的访问

顺便说一句，你可能不想再使用mysql_*函数了。新来者经常迁移到mysqli，然而这也一样乏味。相反，阅读PDO和准备好的语句。 $db =新PDO("mysql:主机=localhost;dbname=testdb"， "用户名"，"密码");