mysql_connect(): user 'name'@'host'拒绝访问

当您连接到无效或缺少凭据(用户名/密码)的MySQL/MariaDB服务器时，会出现此警告。所以这通常不是代码问题，而是服务器配置问题。

See the manual page on mysql_connect("localhost", "user", "pw") for examples. Check that you actually used a $username and $password. It's uncommon that you gain access using no password - which is what happened when the Warning: said (using password: NO). Only the local test server usually allows to connect with username root, no password, and the test database name. You can test if they're really correct using the command line client: mysql --user="username" --password="password" testdb Username and password are case-sensitive and whitespace is not ignored. If your password contains meta characters like $, escape them, or put the password in single quotes. Most shared hosting providers predeclare mysql accounts in relation to the unix user account (sometimes just prefixes or extra numeric suffixes). See the docs for a pattern or documentation, and CPanel or whatever interface for setting a password. See the MySQL manual on Adding user accounts using the command line. When connected as admin user you can issue a query like: CREATE USER 'username'@'localhost' IDENTIFIED BY 'newpassword'; Or use Adminer or WorkBench or any other graphical tool to create, check or correct account details. If you can't fix your credentials, then asking the internet to "please help" will have no effect. Only you and your hosting provider have permissions and sufficient access to diagnose and fix things. Verify that you could reach the database server, using the host name given by your provider: ping dbserver.hoster.example.net Check this from a SSH console directly on your webserver. Testing from your local development client to your shared hosting server is rarely meaningful. Often you just want the server name to be "localhost", which normally utilizes a local named socket when available. Othertimes you can try "127.0.0.1" as fallback. Should your MySQL/MariaDB server listen on a different port, then use "servername:3306". If that fails, then there's a perhaps a firewall issue. (Off-topic, not a programming question. No remote guess-helping possible.) When using constants like e.g. DB_USER or DB_PASSWORD, check that they're actually defined. If you get a "Warning: Access defined for 'DB_USER'@'host'" and a "Notice: use of undefined constant 'DB_PASS'", then that's your problem. Verify that your e.g. xy/db-config.php was actually included and whatelse. Check for correctly set GRANT permissions. It's not sufficient to have a username+password pair. Each MySQL/MariaDB account can have an attached set of permissions. Those can restrict which databases you are allowed to connect to, from which client/server the connection may originate from, and which queries are permitted. The "Access denied" warning thus may as well show up for mysql_query calls, if you don't have permissions to SELECT from a specific table, or INSERT/UPDATE, and more commonly DELETE anything. You can adapt account permissions when connected per command line client using the admin account with a query like: GRANT ALL ON yourdb.* TO 'username'@'localhost'; If the warning shows up first with Warning: mysql_query(): Access denied for user ''@'localhost' then you may have a php.ini-preconfigured account/password pair. Check that mysql.default_user= and mysql.default_password= have meaningful values. Oftentimes this is a provider-configuration. So contact their support for mismatches. Find the documentation of your shared hosting provider: e.g. HostGator, GoDaddy, 1and1, DigitalOcean, BlueHost, DreamHost, MediaTemple, ixWebhosting, lunarhosting, or just google yours´. Else consult your webhosting provider through their support channels. Note that you may also have depleted the available connection pool. You'll get access denied warnings for too many concurrent connections. (You have to investigate the setup. That's an off-topic server configuration issue, not a programming question.) Your libmysql client version may not be compatible with the database server. Normally MySQL and MariaDB servers can be reached with PHPs compiled in driver. If you have a custom setup, or an outdated PHP version, and a much newer database server, or significantly outdated one - then the version mismatch may prevent connections. (No, you have to investigate yourself. Nobody can guess your setup).

更多的引用:

mysql服务器错误:mysql用户无法访问root用户 mysql_connect():拒绝访问 mysql_select_db()拒绝访问用户" @'localhost'(使用密码:NO) PHPMyAdmin拒绝用户“root”@“localhost”的访问

顺便说一句，你可能不想再使用mysql_*函数了。新来者经常迁移到mysqli，然而这也一样乏味。相反，阅读PDO和准备好的语句。 $db =新PDO("mysql:主机=localhost;dbname=testdb"， "用户名"，"密码");

警告:[function]: failed to open stream: [reason]

当你通过include, require或fopen调用一个文件时，PHP无法找到该文件或没有足够的权限来加载该文件。

这种情况的发生有多种原因:

文件路径错误 文件路径是相对的 包含路径是错误的 权限限制太大 SELinux已生效 还有更多……

一个常见的错误是不使用绝对路径。这可以通过使用完整路径或神奇常数如__DIR__或dirname(__FILE__)轻松解决:

include __DIR__ . '/inc/globals.inc.php';

or:

require dirname(__FILE__) . '/inc/globals.inc.php';

确保使用正确的路径是排除这些问题的一个步骤，这也可能与不存在的文件、文件系统的权限阻止访问或PHP本身的打开basedir限制有关。

快速解决此问题的最佳方法是遵循下面的故障排除清单。

相关问题:

故障排除清单:无法打开流

相关的错误:

警告:open_basedir限制生效

警告:字符串偏移量为XXX

当您尝试使用方括号语法访问数组元素时，就会发生这种情况，但您是在字符串上执行此操作，而不是在数组上执行此操作，因此该操作显然没有意义。

例子:

$var = "test";
echo $var["a_key"];

如果你认为变量应该是一个数组，看看它来自哪里并修复那里的问题。

已弃用:不支持使用花括号的数组和字符串偏移访问语法

在PHP 7.4.0之前，字符串偏移量和数组元素可以通过花括号{}访问:

$string = 'abc';
echo $string{0};  // a

$array = [1, 2, 3];
echo $array{0};  // 1

自PHP 7.4.0起已弃用，并生成一个警告:

已弃用:不支持使用花括号的数组和字符串偏移访问语法

你必须使用方括号[]来访问字符串偏移量和数组元素:

$string = 'abc';
echo $string[0];  // a

$array = [1, 2, 3];
echo $array[0];  // 1

此更改的RFC链接到一个PHP脚本，该脚本试图机械地修复此问题。

代码不运行/我的PHP代码的某些部分被输出

如果你的PHP代码没有任何结果，或者你在网页中看到你的PHP源代码输出的部分文字，你可以很确定你的PHP实际上没有被执行。如果在浏览器中使用“查看源代码”，则可能会看到完整的PHP源代码文件。因为PHP代码嵌入在<?php ?>标记时，浏览器将尝试将它们解释为HTML标记，结果可能看起来有些混乱。

要真正运行PHP脚本，您需要:

执行脚本的web服务器 将文件扩展名设置为.php，否则web服务器不会将其解释为* 通过web服务器访问你的。php文件

*除非你重新配置，否则一切都可以配置。

最后一点尤其重要。只需双击该文件，就可以在浏览器中使用如下地址打开它:

file://C:/path/to/my/file.php

这完全绕过了您可能正在运行的任何web服务器，并且文件没有得到解释。你需要在你的web服务器上访问文件的URL，可能是这样的:

http://localhost/my/file.php

您可能还想检查是否使用了短的打开标记<?而不是<?php和您的php配置已关闭短打开标记。

还可以看到PHP代码没有被执行，而是代码显示在页面上

致命错误:闭包类的对象不能转换为字符串

这意味着您没有执行匿名函数(或闭包)。

在这个例子中，使用箭头函数会抛出一个错误:

echo $fn = fn($x = 42) => $x;

或者对任何匿名函数

echo function($x = 42) { return $x; };

要解决这个错误，您需要执行闭包。

echo $fn = (fn($x = 42) => $x)(30); // take notice of the 2 sets of brackets

echo (function($x = 42) { return $x; })(30);

这种语法叫做IIFE，是在PHP 7中添加的。