Looper.myLooper() == Looper.getMainLooper()

如果返回true，那么你在UI线程上!

一种基于协程的、与android无关的方法:

val onMainThread: Boolean
    get() = Thread.currentThread() === try {
        runBlocking(Dispatchers.Main.immediate) {
            Thread.currentThread()
        }
    } catch (e: IllegalStateException) {
        // No main dispatcher has been registered; not in an Android context?
        null
    }

只需记录这一行，它应该打印“main”。

Thread.currentThread () . name

最好的方法是最清晰、最健壮的方法:*

Thread.currentThread().equals( Looper.getMainLooper().getThread() )

或者，如果运行时平台是API级别23 (Marshmallow 6.0)或更高:

Looper.getMainLooper().isCurrentThread()

参见Looper API。注意，调用loop . getmainlooper()涉及同步(请参阅源代码)。您可能希望通过存储返回值并重用它来避免开销。

* greg7gkb和2cupsOfTech

除了之前所有的答案

inline fun <T> ensureNotOnMainThread(block: () -> T): T {
    check(Thread.currentThread() != Looper.getMainLooper().thread) { "This function cannot be called on main thread" }
    return block()
}

允许用它包装任何方法，示例如下:

fun isInDataBase(id: String) = ensureNotOnMainThread { db.contains(id) }

首先检查是否是主线程

在Kotlin

fun isRunningOnMainThread(): Boolean {
    return Thread.currentThread() == Looper.getMainLooper().thread
}

在Java中

static boolean isRunningOnMainThread() {
  return Thread.currentThread().equals(Looper.getMainLooper().getThread());
}