从这个最初的问题,我将如何在多个字段应用排序?

使用这种稍作调整的结构,我将如何排序城市(上升)和价格(下降)?

var homes = [
    {"h_id":"3",
     "city":"Dallas",
     "state":"TX",
     "zip":"75201",
     "price":"162500"},
    {"h_id":"4",
     "city":"Bevery Hills",
     "state":"CA",
     "zip":"90210",
     "price":"319250"},
    {"h_id":"6",
     "city":"Dallas",
     "state":"TX",
     "zip":"75000",
     "price":"556699"},
    {"h_id":"5",
     "city":"New York",
     "state":"NY",
     "zip":"00010",
     "price":"962500"}
    ];

我喜欢的事实是,给出的答案提供了一个一般的方法。在我计划使用这段代码的地方,我将不得不对日期以及其他东西进行排序。“启动”对象的能力似乎很方便,如果不是有点麻烦的话。

我试图把这个答案构建成一个很好的通用示例,但我运气不太好。


当前回答

另一种方式

var homes = [ {"h_id":"3", "city":"Dallas", "state":"TX", "zip":"75201", "price":"162500"}, {"h_id":"4", "city":"Bevery Hills", "state":"CA", "zip":"90210", "price":"319250"}, {"h_id":"6", "city":"Dallas", "state":"TX", "zip":"75000", "price":"556699"}, {"h_id":"5", "city":"New York", "state":"NY", "zip":"00010", "price":"962500"} ]; function sortBy(ar) { return ar.sort((a, b) => a.city === b.city ? b.price.toString().localeCompare(a.price) : a.city.toString().localeCompare(b.city)); } console.log(sortBy(homes));

其他回答

简单的一个:

var someArray = [...];

function generateSortFn(props) {
    return function (a, b) {
        for (var i = 0; i < props.length; i++) {
            var prop = props[i];
            var name = prop.name;
            var reverse = prop.reverse;
            if (a[name] < b[name])
                return reverse ? 1 : -1;
            if (a[name] > b[name])
                return reverse ? -1 : 1;
        }
        return 0;
    };
};

someArray.sort(generateSortFn([{name: 'prop1', reverse: true}, {name: 'prop2'}]));
function sortMultiFields(prop){
    return function(a,b){
        for(i=0;i<prop.length;i++)
        {
            var reg = /^\d+$/;
            var x=1;
            var field1=prop[i];
            if(prop[i].indexOf("-")==0)
            {
                field1=prop[i].substr(1,prop[i].length);
                x=-x;
            }

            if(reg.test(a[field1]))
            {
                a[field1]=parseFloat(a[field1]);
                b[field1]=parseFloat(b[field1]);
            }
            if( a[field1] > b[field1])
                return x;
            else if(a[field1] < b[field1])
                return -x;
        }
    }
}

如果你想按降序排序特定字段,如何使用(在字段前放-(减号)号)

homes.sort(sortMultiFields(["city","-price"]));

使用上面的函数,你可以对带有多个字段的json数组进行排序。根本不需要改变函数体

在这里,您可以尝试按多个字段进行排序的更小且方便的方法!

var homes = [ { "h_id": "3", "city": "Dallas", "state": "TX", "zip": "75201", "price": "162500" }, { "h_id": "4", "city": "Bevery Hills", "state": "CA", "zip": "90210", "price": "319250" }, { "h_id": "6", "city": "Dallas", "state": "TX", "zip": "75000", "price": "556699" }, { "h_id": "5", "city": "New York", "state": "NY", "zip": "00010", "price": "962500" } ]; homes.sort((a, b)=> { if (a.city === b.city){ return a.price < b.price ? -1 : 1 } else { return a.city < b.city ? -1 : 1 } }) console.log(homes);

通过添加两个辅助函数,可以简单地解决这类问题。sortByKey接受一个数组和一个函数,该函数应返回一个项目列表,用于与每个数组条目进行比较。

这利用了javascript对简单值的数组进行智能比较的事实,即[2]<[2,0]<[2,1]<[10,0]。

// Two helpers: function cmp(a, b) { if (a > b) { return 1 } else if (a < b) { return -1 } else { return 0 } } function sortByKey(arr, key) { arr.sort((a, b) => cmp(key(a), key(b))) } // A demonstration: let arr = [{a:1, b:2}, {b:3, a:0}, {a:1, b:1}, {a:2, b:2}, {a:2, b:1}, {a:1, b:10}] sortByKey(arr, item => [item.a, item.b]) console.log(JSON.stringify(arr)) // '[{"b":3,"a":0},{"a":1,"b":1},{"a":1,"b":10},{"a":1,"b":2},{"a":2,"b":1},{"a":2,"b":2}]' sortByKey(arr, item => [item.b, item.a]) console.log(JSON.stringify(arr)) // '[{"a":1,"b":1},{"a":2,"b":1},{"a":1,"b":10},{"a":1,"b":2},{"a":2,"b":2},{"b":3,"a":0}]'

我从Python的列表中偷取了这个想法。排序功能。

对于你的具体问题,一个非通用的,简单的解决方案:

homes.sort(
   function(a, b) {          
      if (a.city === b.city) {
         // Price is only important when cities are the same
         return b.price - a.price;
      }
      return a.city > b.city ? 1 : -1;
   });