下面是我基于施瓦兹变换的解决方案，希望你觉得有用。

function sortByAttribute(array, ...attrs) {
  // generate an array of predicate-objects contains
  // property getter, and descending indicator
  let predicates = attrs.map(pred => {
    let descending = pred.charAt(0) === '-' ? -1 : 1;
    pred = pred.replace(/^-/, '');
    return {
      getter: o => o[pred],
      descend: descending
    };
  });
  // schwartzian transform idiom implementation. aka: "decorate-sort-undecorate"
  return array.map(item => {
    return {
      src: item,
      compareValues: predicates.map(predicate => predicate.getter(item))
    };
  })
  .sort((o1, o2) => {
    let i = -1, result = 0;
    while (++i < predicates.length) {
      if (o1.compareValues[i] < o2.compareValues[i]) result = -1;
      if (o1.compareValues[i] > o2.compareValues[i]) result = 1;
      if (result *= predicates[i].descend) break;
    }
    return result;
  })
  .map(item => item.src);
}

下面是一个如何使用它的例子:

let games = [
  { name: 'Pako',              rating: 4.21 },
  { name: 'Hill Climb Racing', rating: 3.88 },
  { name: 'Angry Birds Space', rating: 3.88 },
  { name: 'Badland',           rating: 4.33 }
];

// sort by one attribute
console.log(sortByAttribute(games, 'name'));
// sort by mupltiple attributes
console.log(sortByAttribute(games, '-rating', 'name'));

这里有一个简单的泛型函数方法。使用数组指定排序顺序。前置减号以指定降序。

var homes = [
    {"h_id":"3", "city":"Dallas", "state":"TX","zip":"75201","price":"162500"},
    {"h_id":"4","city":"Bevery Hills", "state":"CA", "zip":"90210", "price":"319250"},
    {"h_id":"6", "city":"Dallas", "state":"TX", "zip":"75000", "price":"556699"},
    {"h_id":"5", "city":"New York", "state":"NY", "zip":"00010", "price":"962500"}
    ];

homes.sort(fieldSorter(['city', '-price']));
// homes.sort(fieldSorter(['zip', '-state', 'price'])); // alternative

function fieldSorter(fields) {
    return function (a, b) {
        return fields
            .map(function (o) {
                var dir = 1;
                if (o[0] === '-') {
                   dir = -1;
                   o=o.substring(1);
                }
                if (a[o] > b[o]) return dir;
                if (a[o] < b[o]) return -(dir);
                return 0;
            })
            .reduce(function firstNonZeroValue (p,n) {
                return p ? p : n;
            }, 0);
    };
}

编辑:在ES6中它甚至更短!

"use strict"; const fieldSorter = (fields) => (a, b) => fields.map(o => { let dir = 1; if (o[0] === '-') { dir = -1; o=o.substring(1); } return a[o] > b[o] ? dir : a[o] < b[o] ? -(dir) : 0; }).reduce((p, n) => p ? p : n, 0); const homes = [{"h_id":"3", "city":"Dallas", "state":"TX","zip":"75201","price":162500}, {"h_id":"4","city":"Bevery Hills", "state":"CA", "zip":"90210", "price":319250},{"h_id":"6", "city":"Dallas", "state":"TX", "zip":"75000", "price":556699},{"h_id":"5", "city":"New York", "state":"NY", "zip":"00010", "price":962500}]; const sortedHomes = homes.sort(fieldSorter(['state', '-price'])); document.write('<pre>' + JSON.stringify(sortedHomes, null, '\t') + '</pre>')

这是一个通用的多维排序，允许在每个层次上进行反转和/或映射。

用Typescript编写。对于Javascript，请查看这个JSFiddle

的代码

type itemMap = (n: any) => any;

interface SortConfig<T> {
  key: keyof T;
  reverse?: boolean;
  map?: itemMap;
}

export function byObjectValues<T extends object>(keys: ((keyof T) | SortConfig<T>)[]): (a: T, b: T) => 0 | 1 | -1 {
  return function(a: T, b: T) {
    const firstKey: keyof T | SortConfig<T> = keys[0];
    const isSimple = typeof firstKey === 'string';
    const key: keyof T = isSimple ? (firstKey as keyof T) : (firstKey as SortConfig<T>).key;
    const reverse: boolean = isSimple ? false : !!(firstKey as SortConfig<T>).reverse;
    const map: itemMap | null = isSimple ? null : (firstKey as SortConfig<T>).map || null;

    const valA = map ? map(a[key]) : a[key];
    const valB = map ? map(b[key]) : b[key];
    if (valA === valB) {
      if (keys.length === 1) {
        return 0;
      }
      return byObjectValues<T>(keys.slice(1))(a, b);
    }
    if (reverse) {
      return valA > valB ? -1 : 1;
    }
    return valA > valB ? 1 : -1;
  };
}

用法示例

先按姓排序，再按名排序:

interface Person {
  firstName: string;
  lastName: string;
}

people.sort(byObjectValues<Person>(['lastName','firstName']));

按语言代码的名称排序，而不是按语言代码排序(见地图)，然后按降序排序(见反向)。

interface Language {
  code: string;
  version: number;
}

// languageCodeToName(code) is defined elsewhere in code

languageCodes.sort(byObjectValues<Language>([
  {
    key: 'code',
    map(code:string) => languageCodeToName(code),
  },
  {
    key: 'version',
    reverse: true,
  }
]));

改编自@chriskelly的回答。

大多数答案都忽略了，如果价值在1万美元以下或超过100万美元，价格将无法正确排序。原因是JS按字母顺序排序。这里回答得很好，为什么JavaScript不能对“5,10,1”排序，这里如何正确地对整数数组排序。

最后，如果我们要排序的字段或节点是一个数字，我们必须做一些计算。我并不是说在这种情况下使用parseInt()是正确的答案，排序结果更重要。

var homes = [{ "h_id": "2", "city": "Dallas", "state": "TX", "zip": "75201", "price": "62500" }, { "h_id": "1", "city": "Dallas", "state": "TX", "zip": "75201", "price": "62510" }, { "h_id": "3", "city": "Dallas", "state": "TX", "zip": "75201", "price": "162500" }, { "h_id": "4", "city": "Bevery Hills", "state": "CA", "zip": "90210", "price": "319250" }, { "h_id": "6", "city": "Dallas", "state": "TX", "zip": "75000", "price": "556699" }, { "h_id": "5", "city": "New York", "state": "NY", "zip": "00010", "price": "962500" }]; homes.sort(fieldSorter(['price'])); // homes.sort(fieldSorter(['zip', '-state', 'price'])); // alternative function fieldSorter(fields) { return function(a, b) { return fields .map(function(o) { var dir = 1; if (o[0] === '-') { dir = -1; o = o.substring(1); } if (!parseInt(a[o]) && !parseInt(b[o])) { if (a[o] > b[o]) return dir; if (a[o] < b[o]) return -(dir); return 0; } else { return dir > 0 ? a[o] - b[o] : b[o] - a[o]; } }) .reduce(function firstNonZeroValue(p, n) { return p ? p : n; }, 0); }; } document.getElementById("output").innerHTML = '<pre>' + JSON.stringify(homes, null, '\t') + '</pre>'; <div id="output"> </div>

用来测试的小提琴

另一种方式

var homes = [ {"h_id":"3", "city":"Dallas", "state":"TX", "zip":"75201", "price":"162500"}, {"h_id":"4", "city":"Bevery Hills", "state":"CA", "zip":"90210", "price":"319250"}, {"h_id":"6", "city":"Dallas", "state":"TX", "zip":"75000", "price":"556699"}, {"h_id":"5", "city":"New York", "state":"NY", "zip":"00010", "price":"962500"} ]; function sortBy(ar) { return ar.sort((a, b) => a.city === b.city ? b.price.toString().localeCompare(a.price) : a.city.toString().localeCompare(b.city)); } console.log(sortBy(homes));

哇，这里有一些复杂的解。如此复杂，我决定想出一些更简单但也相当强大的东西。在这里;

function sortByPriority(data, priorities) {
  if (priorities.length == 0) {
    return data;
  }

  const nextPriority = priorities[0];
  const remainingPriorities = priorities.slice(1);

  const matched = data.filter(item => item.hasOwnProperty(nextPriority));
  const remainingData = data.filter(item => !item.hasOwnProperty(nextPriority));

  return sortByPriority(matched, remainingPriorities)
    .sort((a, b) => (a[nextPriority] > b[nextPriority]) ? 1 : -1)
    .concat(sortByPriority(remainingData, remainingPriorities));
}

这里有一个如何使用它的例子。

const data = [
  { id: 1,                         mediumPriority: 'bbb', lowestPriority: 'ggg' },
  { id: 2, highestPriority: 'bbb', mediumPriority: 'ccc', lowestPriority: 'ggg' },
  { id: 3,                         mediumPriority: 'aaa', lowestPriority: 'ggg' },
];

const priorities = [
  'highestPriority',
  'mediumPriority',
  'lowestPriority'
];


const sorted = sortByPriority(data, priorities);

这将首先根据属性的优先级排序，然后根据属性的值进行排序。