在一个使用AJAX调用的web应用程序中,我需要提交一个请求,但在URL的末尾添加一个参数,例如:
原始URL:
http://server/myapp.php?id=10
导致的网址:
http://server/myapp.php?id=10&enabled=true
寻找一个JavaScript函数,该函数解析URL并查看每个参数,然后添加新参数或更新已经存在的值。
在一个使用AJAX调用的web应用程序中,我需要提交一个请求,但在URL的末尾添加一个参数,例如:
原始URL:
http://server/myapp.php?id=10
导致的网址:
http://server/myapp.php?id=10&enabled=true
寻找一个JavaScript函数,该函数解析URL并查看每个参数,然后添加新参数或更新已经存在的值。
当前回答
var MyApp = new Class();
MyApp.extend({
utility: {
queryStringHelper: function (url) {
var originalUrl = url;
var newUrl = url;
var finalUrl;
var insertParam = function (key, value) {
key = escape(key);
value = escape(value);
//The previous post had the substr strat from 1 in stead of 0!!!
var kvp = newUrl.substr(0).split('&');
var i = kvp.length;
var x;
while (i--) {
x = kvp[i].split('=');
if (x[0] == key) {
x[1] = value;
kvp[i] = x.join('=');
break;
}
}
if (i < 0) {
kvp[kvp.length] = [key, value].join('=');
}
finalUrl = kvp.join('&');
return finalUrl;
};
this.insertParameterToQueryString = insertParam;
this.insertParams = function (keyValues) {
for (var keyValue in keyValues[0]) {
var key = keyValue;
var value = keyValues[0][keyValue];
newUrl = insertParam(key, value);
}
return newUrl;
};
return this;
}
}
});
其他回答
你需要适应的基本实现是这样的:
function insertParam(key, value) {
key = encodeURIComponent(key);
value = encodeURIComponent(value);
// kvp looks like ['key1=value1', 'key2=value2', ...]
var kvp = document.location.search.substr(1).split('&');
let i=0;
for(; i<kvp.length; i++){
if (kvp[i].startsWith(key + '=')) {
let pair = kvp[i].split('=');
pair[1] = value;
kvp[i] = pair.join('=');
break;
}
}
if(i >= kvp.length){
kvp[kvp.length] = [key,value].join('=');
}
// can return this or...
let params = kvp.join('&');
// reload page with new params
document.location.search = params;
}
这大约是正则表达式或基于搜索的解决方案的两倍,但这完全取决于查询字符串的长度和任何匹配的索引
为了完成起见,我以慢速regex方法为基准(大约慢了150%)
function insertParam2(key,value)
{
key = encodeURIComponent(key); value = encodeURIComponent(value);
var s = document.location.search;
var kvp = key+"="+value;
var r = new RegExp("(&|\\?)"+key+"=[^\&]*");
s = s.replace(r,"$1"+kvp);
if(!RegExp.$1) {s += (s.length>0 ? '&' : '?') + kvp;};
//again, do what you will here
document.location.search = s;
}
我是这么做的。使用我的editParams()函数,你可以添加,删除或更改任何参数,然后使用内置的replaceState()函数更新URL:
window.history.replaceState('object or string', 'Title', 'page.html' + editParams('enable', 'true'));
// background functions below:
// add/change/remove URL parameter
// use a value of false to remove parameter
// returns a url-style string
function editParams (key, value) {
key = encodeURI(key);
var params = getSearchParameters();
if (Object.keys(params).length === 0) {
if (value !== false)
return '?' + key + '=' + encodeURI(value);
else
return '';
}
if (value !== false)
params[key] = encodeURI(value);
else
delete params[key];
if (Object.keys(params).length === 0)
return '';
return '?' + $.map(params, function (value, key) {
return key + '=' + value;
}).join('&');
}
// Get object/associative array of URL parameters
function getSearchParameters () {
var prmstr = window.location.search.substr(1);
return prmstr !== null && prmstr !== "" ? transformToAssocArray(prmstr) : {};
}
// convert parameters from url-style string to associative array
function transformToAssocArray (prmstr) {
var params = {},
prmarr = prmstr.split("&");
for (var i = 0; i < prmarr.length; i++) {
var tmparr = prmarr[i].split("=");
params[tmparr[0]] = tmparr[1];
}
return params;
}
加入@Vianney的回答https://stackoverflow.com/a/44160941/6609678
我们可以导入node中的内置URL模块,如下所示
const { URL } = require('url');
例子:
Terminal $ node
> const { URL } = require('url');
undefined
> let url = new URL('', 'http://localhost:1989/v3/orders');
undefined
> url.href
'http://localhost:1989/v3/orders'
> let fetchAll=true, timePeriod = 30, b2b=false;
undefined
> url.href
'http://localhost:1989/v3/orders'
> url.searchParams.append('fetchAll', fetchAll);
undefined
> url.searchParams.append('timePeriod', timePeriod);
undefined
> url.searchParams.append('b2b', b2b);
undefined
> url.href
'http://localhost:1989/v3/orders?fetchAll=true&timePeriod=30&b2b=false'
> url.toString()
'http://localhost:1989/v3/orders?fetchAll=true&timePeriod=30&b2b=false'
有用的链接:
https://developer.mozilla.org/en-US/docs/Web/API/URL https://developer.mozilla.org/en/docs/Web/API/URLSearchParams
这就是我在服务器端(如Node.js)添加或更新一些基本url参数时使用的方法。
CoffeScript:
### @method addUrlParam Adds parameter to a given url. If the parameter already exists in the url is being replaced. @param {string} url @param {string} key Parameter's key @param {string} value Parameter's value @returns {string} new url containing the parameter ### addUrlParam = (url, key, value) -> newParam = key+"="+value result = url.replace(new RegExp('(&|\\?)' + key + '=[^\&|#]*'), '$1' + newParam) if result is url result = if url.indexOf('?') != -1 then url.split('?')[0] + '?' + newParam + '&' + url.split('?')[1] else if url.indexOf('#') != -1 then url.split('#')[0] + '?' + newParam + '#' + url.split('#')[1] else url + '?' + newParam return result
JavaScript:
function addUrlParam(url, key, value) { var newParam = key+"="+value; var result = url.replace(new RegExp("(&|\\?)"+key+"=[^\&|#]*"), '$1' + newParam); if (result === url) { result = (url.indexOf("?") != -1 ? url.split("?")[0]+"?"+newParam+"&"+url.split("?")[1] : (url.indexOf("#") != -1 ? url.split("#")[0]+"?"+newParam+"#"+ url.split("#")[1] : url+'?'+newParam)); } return result; } var url = "http://www.example.com?foo=bar&ciao=3&doom=5#hashme"; result1.innerHTML = addUrlParam(url, "ciao", "1"); <p id="result1"></p>
这是我自己的尝试,但我将使用annakata的答案,因为它看起来更清晰:
function AddUrlParameter(sourceUrl, parameterName, parameterValue, replaceDuplicates)
{
if ((sourceUrl == null) || (sourceUrl.length == 0)) sourceUrl = document.location.href;
var urlParts = sourceUrl.split("?");
var newQueryString = "";
if (urlParts.length > 1)
{
var parameters = urlParts[1].split("&");
for (var i=0; (i < parameters.length); i++)
{
var parameterParts = parameters[i].split("=");
if (!(replaceDuplicates && parameterParts[0] == parameterName))
{
if (newQueryString == "")
newQueryString = "?";
else
newQueryString += "&";
newQueryString += parameterParts[0] + "=" + parameterParts[1];
}
}
}
if (newQueryString == "")
newQueryString = "?";
else
newQueryString += "&";
newQueryString += parameterName + "=" + parameterValue;
return urlParts[0] + newQueryString;
}
另外,我从stackoverflow上的另一篇文章中找到了这个jQuery插件,如果你需要更多的灵活性,你可以使用它: http://plugins.jquery.com/project/query-object
我认为代码应该是(还没有测试):
return $.query.parse(sourceUrl).set(parameterName, parameterValue).toString();