在Objective-C中,检查NSString子字符串的代码是:
NSString *string = @"hello Swift";
NSRange textRange =[string rangeOfString:@"Swift"];
if(textRange.location != NSNotFound)
{
NSLog(@"exists");
}
但是如何在Swift中做到这一点呢?
在Objective-C中,检查NSString子字符串的代码是:
NSString *string = @"hello Swift";
NSRange textRange =[string rangeOfString:@"Swift"];
if(textRange.location != NSNotFound)
{
NSLog(@"exists");
}
但是如何在Swift中做到这一点呢?
当前回答
在Swift 4.2中
Use
func contains(_ str: String) -> Bool
例子
let string = "hello Swift"
let containsSwift = string.contains("Swift")
print(containsSwift) // prints true
其他回答
在Xcode 7.1和Swift 2.1中,containsString()为我工作得很好。
let string = "hello swift"
if string.containsString("swift") {
print("found swift")
}
斯威夫特4:
let string = "hello swift"
if string.contains("swift") {
print("found swift")
}
一个不区分大小写的Swift 4示例:
let string = "Hello Swift"
if string.lowercased().contains("swift") {
print("found swift")
}
或者使用不区分大小写的字符串扩展名:
extension String {
func containsIgnoreCase(_ string: String) -> Bool {
return self.lowercased().contains(string.lowercased())
}
}
let string = "Hello Swift"
let stringToFind = "SWIFT"
if string.containsIgnoreCase(stringToFind) {
print("found: \(stringToFind)") // found: SWIFT
}
print("string: \(string)")
print("stringToFind: \(stringToFind)")
// console output:
found: SWIFT
string: Hello Swift
stringToFind: SWIFT
这是我在快速操场上的第一次尝试。 我通过提供两个新函数(contains和containsIgnoreCase)来扩展String
extension String {
func contains(other: String) -> Bool{
var start = startIndex
do{
var subString = self[Range(start: start++, end: endIndex)]
if subString.hasPrefix(other){
return true
}
}while start != endIndex
return false
}
func containsIgnoreCase(other: String) -> Bool{
var start = startIndex
do{
var subString = self[Range(start: start++, end: endIndex)].lowercaseString
if subString.hasPrefix(other.lowercaseString){
return true
}
}while start != endIndex
return false
}
}
像这样使用它
var sentence = "This is a test sentence"
sentence.contains("this") //returns false
sentence.contains("This") //returns true
sentence.containsIgnoreCase("this") //returns true
"This is another test sentence".contains(" test ") //returns true
我欢迎任何反馈:)
给你!准备Xcode 8和Swift 3。
import UIKit
let mString = "This is a String that contains something to search."
let stringToSearchUpperCase = "String"
let stringToSearchLowerCase = "string"
mString.contains(stringToSearchUpperCase) //true
mString.contains(stringToSearchLowerCase) //false
mString.lowercased().contains(stringToSearchUpperCase) //false
mString.lowercased().contains(stringToSearchLowerCase) //true
您不需要为此编写任何定制代码。从1.2版本开始,Swift已经有了所有你需要的方法:
获取字符串长度:count(string); 检查字符串是否包含子字符串:contains(字符串,子字符串); 检查字符串是否以substring开头:startsWith(string, substring) 等。
在Swift 3中
if((a.range(of: b!, options: String.CompareOptions.caseInsensitive, range: nil, locale: nil)) != nil){
print("Done")
}