是否有任何方法我可以使用moment.js格式方法持续时间对象?我在文档中找不到它,也没有看到它是持续时间对象的属性。

我希望能够做到以下几点:

var diff = moment(end).unix() - moment(start).unix();
moment.duration(diff).format('hh:mm:ss')

此外,如果有其他库可以轻松地容纳这种功能,我会很有兴趣推荐。

谢谢!


当前回答

import * as moment from 'moment'
var sleep = require('sleep-promise');

(async function () {
    var t1 = new Date().getTime();
    await sleep(1000); 
    var t2 = new Date().getTime();
    var dur = moment.duration(t2-t1); 
    console.log(`${dur.hours()}h:${dur.minutes()}m:${dur.seconds()}s`);
})();

0h:0m:1s

其他回答

const duration = moment.duration(62, 'hours');
const n = 24 * 60 * 60 * 1000;
const days = Math.floor(duration / n);
const str = moment.utc(duration % n).format('H [h] mm [min] ss [s]');
console.log(`${days > 0 ? `${days} ${days == 1 ? 'day' : 'days'} ` : ''}${str}`);

打印:

2天14小时00分00秒

如果diff是一瞬间

var diff = moment(20111031) - moment(20111010);
var formated1 = moment(diff).format("hh:mm:ss");
console.log("format 1: "+formated1);

你不需要.format。像这样使用持续时间:

const duration = moment.duration(83, 'seconds');
console.log(duration.minutes() + ':' +duration.seconds());
// output: 1:23

我在这里找到了这个解决方案:https://github.com/moment/moment/issues/463

编辑:

用秒、分和小时填充:

const withPadding = (duration) => {
    if (duration.asDays() > 0) {
        return 'at least one day';
    } else {
        return [
            ('0' + duration.hours()).slice(-2),
            ('0' + duration.minutes()).slice(-2),
            ('0' + duration.seconds()).slice(-2),
        ].join(':')
    }
}

withPadding(moment.duration(83, 'seconds'))
// 00:01:23

withPadding(moment.duration(6048000, 'seconds'))
// at least one day
// set up
let start = moment("2018-05-16 12:00:00"); // some random moment in time (in ms)
let end = moment("2018-05-16 12:22:00"); // some random moment after start (in ms)
let diff = end.diff(start);

// execution
let f = moment.utc(diff.asMilliseconds()).format("HH:mm:ss.SSS");
alert(f);

看看JSFiddle

使用这个插件Moment Duration Format。

例子:

moment.duration(123, "minutes").format("h:mm");