一个简单的解决方案(假设你使用的是一个不错的IDE)是在所有地方输入'int'，然后让它为你设置类型。

实际上我只是添加了一个名为var的类，所以我不需要输入不同的东西。

代码仍然过于冗长，但至少您不必键入它!

我知道这是旧的，但为什么不创建一个var类，创建不同类型的构造函数，根据调用的构造函数，你会得到不同类型的var。您甚至可以内置方法将一种类型转换为另一种类型。

没有。唉，你必须输入完整的类型名。

编辑:在发布7年后，Java 10中添加了局部变量的类型推断(使用var)。

编辑:在发布6年之后，收集下面的一些评论:

The reason C# has the var keyword is because it's possible to have Types that have no name in .NET. Eg: var myData = new { a = 1, b = "2" }; In this case, it would be impossible to give a proper type to myData. 6 years ago, this was impossible in Java (all Types had names, even if they were extremely verbose and unweildy). I do not know if this has changed in the mean time. var is not the same as dynamic. variables are still 100% statically typed. This will not compile: var myString = "foo"; myString = 3; var is also useful when the type is obvious from context. For example: var currentUser = User.GetCurrent(); I can say that in any code that I am responsible for, currentUser has a User or derived class in it. Obviously, if your implementation of User.GetCurrent return an int, then maybe this is a detriment to you. This has nothing to do with var, but if you have weird inheritance hierarchies where you shadow methods with other methods (eg new public void DoAThing()), don't forget that non-virtual methods are affected by the Type they are cast as. I can't imagine a real world scenario where this is indicative of good design, but this may not work as you expect: class Foo { public void Non() {} public virtual void Virt() {} } class Bar : Foo { public new void Non() {} public override void Virt() {} } class Baz { public static Foo GetFoo() { return new Bar(); } } var foo = Baz.GetFoo(); foo.Non(); // <- Foo.Non, not Bar.Non foo.Virt(); // <- Bar.Virt var bar = (Bar)foo; bar.Non(); // <- Bar.Non, not Foo.Non bar.Virt(); // <- Still Bar.Virt As indicated, virtual methods are not affected by this. No, there is no non-clumsy way to initialize a var without an actual variable. var foo1 = "bar"; //good var foo2; //bad, what type? var foo3 = null; //bad, null doesn't have a type var foo4 = default(var); //what? var foo5 = (object)null; //legal, but go home, you're drunk In this case, just do it the old fashioned way: object foo6;

一般来说，你可以为任何类型使用Object类，但是你以后必须做类型强制转换!

如:-

Object object = 12;
    Object object1 = "Aditya";
    Object object2 = 12.12;

    System.out.println(Integer.parseInt(object.toString()) + 2);

    System.out.println(object1.toString() + " Kumar");
    System.out.println(Double.parseDouble(object2.toString()) + 2.12);

如果您将Lombok添加到项目中，您可以使用它的val关键字。

http://projectlombok.org/features/val.html

Java 10确实得到了局部变量类型推断，所以现在它有var，这与c#相当(据我所知)。

它还可以推断出不可标记的类型(程序员无法在该位置命名的类型;尽管哪些类型是不可标记的是不同的)。参见var和匿名类的技巧(你永远不应该在工作中使用)。

我能发现的一个区别是，在c#中，

如果一个名为var的类型在作用域中，那么var关键字将解析为该类型名称，并且不会被视为隐式类型局部变量声明的一部分。

在Java 10中，var不是一个合法的类型名称。