一些给出的答案没有考虑到今天!

这是我的建议。

$var = "2010-01-21 00:00:00.0"
$given_date = new \DateTime($var);

if ($given_date == new \DateTime('today')) {
  //today
}

if ($given_date < new \DateTime('today')) {
  //past
}

if ($given_date > new \DateTime('today')) {
  //future
}

扩展Josua在w3schools上的回答:

//create objects for the dates to compare
$date1=date_create($someDate);
$date2=date_create(date("Y-m-d"));
$diff=date_diff($date1,$date2);
//now convert the $diff object to type integer
$intDiff = $diff->format("%R%a");
$intDiff = intval($intDiff);
//now compare the two dates
if ($intDiff > 0)  {echo '$date1 is in the past';}
else {echo 'date1 is today or in the future';}

我希望这能有所帮助。我在stackoverflow上的第一篇文章!

strtotime($var);

将其转换为时间值

time() - strtotime($var);

给出自$var后的秒数

if((time()-(60*60*24)) < strtotime($var))

将检查$var是否在最后一天内。

$toBeComparedDate = '2014-08-12';
$today = (new DateTime())->format('Y-m-d'); //use format whatever you are using
$expiry = (new DateTime($toBeComparedDate))->format('Y-m-d');

var_dump(strtotime($today) > strtotime($expiry)); //false or true

一些给出的答案没有考虑到今天!

这是我的建议。

$var = "2010-01-21 00:00:00.0"
$given_date = new \DateTime($var);

if ($given_date == new \DateTime('today')) {
  //today
}

if ($given_date < new \DateTime('today')) {
  //past
}

if ($given_date > new \DateTime('today')) {
  //future
}

如果你做事有时间和日期，碳是你最好的朋友;

安装包，然后:

$theDay = Carbon::make("2010-01-21 00:00:00.0");

$theDay->isToday();
$theDay->isPast();
$theDay->isFuture();
if($theDay->lt(Carbon::today()) || $theDay->gt(Carbon::today()))

Lt =小于， Gt =大于

在这个问题中:

$theDay->gt(Carbon::today()) ? true : false;

还有更多;