如何列出PostgreSQL数据库的所有表并按大小排序?


当前回答

这里的大多数答案使用pg_size_pretty,这是非常有用的,但如果你想输出一个数值,你可以自己计算

SELECT tab_size /1024 AS size_kb
      ,tab_size /1024 /1024 AS size_mb
      ,tab_size /1024 /1024 / 1024 AS size_gb
      ,tab_size /1024 /1024 / 1024 / 1024 AS size_tb
  FROM 
      (
       SELECT pg_total_relation_size(relid) AS tab_size
         FROM pg_catalog.pg_statio_user_tables
        WHERE schemaname = 'your_schema' 
          AND relname = 'your_table'
      ) AS tabs;

其他回答

这样会更清楚。

Pg_size_pretty (<numeric_value>) -转换no。字节转换为人类可读的格式。

Pg_database_size (<db_name>) -以字节为单位获取数据库大小。

Pg_total_relation_size (<relation_name>) -以字节为单位获取表的总大小及其索引。

Pg_relation_size (<relation_name>) -以字节为单位获取关系(表/索引)大小。

Pg_indexes_size (<relation_name>) -以字节为单位获取关系的索引大小。

Current_database() -获取当前正在对其执行查询的数据库。

查询:

select current_database() as database,
       pg_size_pretty(total_database_size) as total_database_size,
       schema_name,
       table_name,
       pg_size_pretty(total_table_size) as total_table_size,
       pg_size_pretty(table_size) as table_size,
       pg_size_pretty(index_size) as index_size
       from ( select table_name,
                table_schema as schema_name,
                pg_database_size(current_database()) as total_database_size,
                pg_total_relation_size(table_name) as total_table_size,
                pg_relation_size(table_name) as table_size,
                pg_indexes_size(table_name) as index_size
                from information_schema.tables
                where table_schema=current_schema() and table_name like 'table_%'
                order by total_table_size
            ) as sizes;

结果:

 database  | total_database_size | schema_name | table_name | total_table_size | table_size | index_size
-----------+---------------------+-------------+------------+------------------+------------+------------
 vigneshdb | 1586 MB             | corpdata    | table_aaa  | 16 kB            | 0 bytes    | 8192 bytes
 vigneshdb | 1586 MB             | corpdata    | table_bbb  | 24 kB            | 0 bytes    | 16 kB
 vigneshdb | 1586 MB             | corpdata    | table_ccc  | 640 kB           | 112 kB     | 488 kB
 vigneshdb | 1586 MB             | corpdata    | table_ddd  | 9760 kB          | 3152 kB    | 6568 kB
 vigneshdb | 1586 MB             | corpdata    | table_eee  | 1120 MB          | 311 MB     | 808 MB

人性化的格式以字节、kB、MB、GB和TB表示。

bytes to kB -从10240字节开始

bytes to MB -从10485248 bytes = 10239.5 kB ~ 10mb开始

bytes to GB -从10736893952开始,字节= 10239.5 MB ~ 10bg

bytes to TB -从10994579406848 bytes = 10239.5 GB ~ 10tb开始

所有单位转换从10 + <单位>开始。

参考- Postgres官方文件

select table_name, pg_relation_size(quote_ident(table_name))
from information_schema.tables
where table_schema = 'public'
order by 2

如果你有多个模式,这将显示模式公共中所有表的大小,你可能想使用:

select table_schema, table_name, pg_relation_size('"'||table_schema||'"."'||table_name||'"')
from information_schema.tables
order by 3

SQLFiddle示例:http://sqlfiddle.com/#!15/13157/3

手册中所有对象大小函数的列表。

我需要找出哪些表占用了最多的空间。

根据其他人的回答,我使用了这个问题:

select table_name, pg_size_pretty( pg_relation_size(quote_ident(table_name)) )
from information_schema.tables
where table_schema = 'public'
order by pg_relation_size(quote_ident(table_name)) desc

得到如下结果:

table_name              pg_size_pretty
--------------------------------------
trade_binance           96 GB
closs_v2_binance_stash  46 GB
closs_bitfinex_stash    5725 MB
trade_bitfinex          5112 MB
...
api_requests            0 bytes
trade_huobi             0 bytes

我应该买个更大的固态硬盘。

SELECT nspname || '.' || relname AS "relation",
    pg_size_pretty(pg_total_relation_size(C.oid)) AS "total_size"
  FROM pg_class C
  LEFT JOIN pg_namespace N ON (N.oid = C.relnamespace)
  WHERE nspname NOT IN ('pg_catalog', 'information_schema')
    AND C.relkind <> 'i'
    AND nspname !~ '^pg_toast'
  ORDER BY pg_total_relation_size(C.oid) DESC
  ;

信贷: https://makandracards.com/makandra/52141-postgresql-how-to-show-table-sizes

select table_name,n_live_tup, pg_size_pretty(pg_relation_size(table_name))
from information_schema.tables
inner join pg_stat_user_tables  on table_name=relname
where table_schema = 'public'
order by 2 desc

另一种替代方法